Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-01
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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The exponential is the unique solution of y′=y with y(0)=1

Statement

If y:R→R is differentiable, y′=y, and y(0)=1, then y=exp⁡.

Facts & Assumptions

Proof

technique · direct
1.1givenL1L2

Define h(x)=y(x)exp⁡(−x). By [L1] and [L2], h′(x)=y′(x)exp⁡(−x)−y(x)exp⁡(−x)=0.

2.1step 1.1L1L3

The differentiable function h is continuous, so [L3] makes it constant; h(0)=y(0)exp⁡(0)=1.

3.1step 2.1L1algebra∎

Thus y(x)exp⁡(−x)=1, and multiplying by exp⁡(x) gives y(x)=exp⁡(x).

Depends on

Dependency tree · 2 levels

Sources