Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passaudited 2026-08-29
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Exterior multiplication is well defined, graded, associative, unital, and graded-commutative

Statement

The wedge product of The graded exterior algebra ΛV is well defined and bilinear in each homogeneous pair of degrees. It is associative, has unit 1∈F=Λ0V, is graded in the sense that ΛkV∧ΛℓV⊆Λk+ℓV, and is graded-commutative:

α∧β=(−1)kℓβ∧α(α∈ΛkV, β∈ΛℓV).

All of this holds over every field, including characteristic two.

Facts & Assumptions

Given: A vector space V over a field F and homogeneous elements of degrees k,ℓ.

[L1]

The exterior algebra is the graded sum of the exterior powers, with the wedge product defined by concatenation on decomposables and extended bilinearly; the definition checks that a repeated pair persists under concatenation, so the product is well defined (The graded exterior algebra ΛV).

Proof

technique · direct
1.1L1

Well-definedness and bilinearity in each degree pair are recorded in [L1], and the graded containment is the degree count of the concatenation.

1.2L1

Unitality: for a decomposable α, the convention 1∧α=α is the definition in [L1]; bilinearity extends it.

1.3L1L2

Associativity: on decomposables, (α∧β)∧γ and α∧(β∧γ) are both the concatenation of the three lists by [L1]; multilinearity of [L2] extends the equality to all elements.

1.4L2algebra

For vectors v,w, alternation of [L2] applied to (v+w,v+w) gives 0=v∧w+w∧v, so v∧w=−w∧v; no division by 2 is used, so this holds in characteristic two as well, where it reads v∧w=w∧v.

2.1step 1.3step 1.4L2

Block swap: for decomposable α=v1∧⋯∧vk and β=w1∧⋯∧wℓ, move each of the ℓ factors wj leftward past all k factors vi using step 1.4, collecting ℓk factors of −1; associativity of step 1.3 makes the block move legitimate, giving α∧β=(−1)kℓβ∧α, and multilinearity extends this to all homogeneous elements.

3.1step 1.1step 1.2step 1.3step 1.4step 2.1∎

Steps 1.1 through 2.1 prove the five asserted laws in every characteristic, because the only sign rule used is the alternation identity of step 1.4.

Depends on

Dependency tree · 2 levels

Sources