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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)verified 2026-11-04 (gpt-6.1-sol)
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Proper flat genus-one fibrations have one-dimensional fibres

Statement

Assume full AC. Let B be a connected integral base and let π:Y→B be a proper, flat, finitely presented morphism whose geometric generic fiber is a smooth geometrically integral genus-one curve. For b∈B, write Yb=Y×BSpec⁡κ(b) for the scheme-theoretic fiber. Then every Yb has Krull dimension one.

Facts & Assumptions

Given: Full AC, connected B, and a proper flat finitely presented morphism π:Y→B with geometric generic fiber a smooth geometrically integral genus-one curve.

[A1]

Full AC is the choice-function principle of The Axiom of Choice; the local-constancy supplier below assumes it.

[F1]

For a proper flat finitely presented morphism, the function b↦dim⁡Yb is locally constant, with empty fibers assigned dimension −∞ (Fibre dimension of proper flat finitely presented families).

[F2]

The generic fiber and genus-one condition have the meanings fixed in Flat genus-one fibration: after algebraic closure of K(B) it is a smooth proper geometrically integral curve with dim⁡H1(Yηˉ,O)=1.

Proof

technique · reduce to the locally constant fiber-dimension function
1.1A1F1F2given

By [F2], the geometric generic fiber is a curve, hence has Krull dimension one. In particular the fiber-dimension function of [F1] takes value one at the generic point η∈B.

2.1F1step 1.1given∎

By [F1], the fiber-dimension function is locally constant on B. A locally constant function on a connected topological space is constant: the inverse image of each value is open, and its complement is the union of the other open level sets, hence also open; a nonempty level set is therefore all of B. Since the value at η is one by step 1.1, every fiber has dimension one, including that no fiber is empty.

Depends on

Dependency tree · 2 levels

Sources