How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Existence of all scheme fibre products
Statement
Every diagram of schemes has a fibre product. Given an affine cover and affine covers and , the product has open affine cover
Facts & Assumptions
Given: The objects, hypotheses and conventions in the statement above.
Let and be maps of commutative unital rings, allowing the zero ring. In the category of all schemes, The projections correspond to and . (Affine fibre products are spectra of tensor products)
Let be given. If is an open cover and every exists, these products glue along their inverse images over to a fibre product . There is also a base-cover version: if and exists for every , these products glue to . No overlap is required to be affine. (Gluing fibre products along open covers)
Proof
When are affine, cover by affines. Each local product exists by F1, so F2 glues them to the desired product, with the displayed affine charts.
When only is affine, cover by affine opens. The preceding construction gives each product of one of these opens with . Interchanging the roles of the two projections in F2 glues them. This interchange is justified directly by the symmetric compatible-pair condition, without needing a later associativity result.
For arbitrary , apply the preceding result over each affine , and then use the base-cover clause of F2. Its overlap construction makes the stated tensor spectra an open cover. Empty schemes and zero tensor rings give empty charts, and the empty-base case forces both factors to be empty.