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Fundamental theorem of calculus for absolutely continuous functions
Statement
Assume the Axioms of Countable Choice and Dependent Choice. For , the following are equivalent:
- is absolutely continuous.
- exists almost everywhere, , and
Facts & Assumptions
Given: Countable choice, dependent choice, and a real function on the compact interval .
Proof
Assume (1). By Absolutely continuous functions have integrable derivatives, put a.e.; the first FTC The indefinite integral of an function is differentiable almost everywhere says a.e.
The corollary The indefinite integral of an function is absolutely continuous makes AC, so is AC and has derivative zero a.e. The zero-derivative theorem makes constant; , giving (2).
Conversely, (2) says , and the same corollary makes it AC. The singleton interval satisfies both clauses directly.
Depends on
The Axiom of Countable Choice ()
The axiom of dependent choice: a relation in which every element is related to something admits an -indexed chain
The indefinite integral of an function is absolutely continuous
The indefinite integral of an function is differentiable almost everywhere
Absolutely continuous functions have integrable derivatives
An absolutely continuous function with zero derivative almost everywhere is constant