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The fundamental theorem on flows
Statement
Let be a smooth vector field on . For each , let be the maximal integral curve through , and set
Then is open in , each fibre is an interval containing , the map is smooth, and is the unique maximal local flow generated by .
Facts & Assumptions
Given: A smooth vector field on .
Every point lies on a unique maximal integral curve (Through each point there is a unique maximal integral curve).
Integral curves exist uniquely on uniform local time intervals and depend smoothly on the initial point (Local existence, uniqueness, and smooth dependence for manifold integral curves).
Proof
By [L1], for each there is a unique maximal integral curve through . Therefore the set and the map are well defined, each fibre is an open interval containing , and .
Fix and , and put . Then the translated curve is an integral curve through on the interval . By uniqueness of maximal integral curves, it agrees with on their common domain, so whenever both sides are defined. The same translation argument applied to shows .
Fix . The trajectory segment if , or if , is compact. By [L2], every has an open neighbourhood and a smooth local flow . A finite subcover of gives a common lower time bound for these finitely many local flows. Partition the interval from to as with . For each , choose one of the finitely many containing and use its local flow for the time increment . This requires only finitely many choices.
Starting with the identity near , compose the finitely many smooth local time-increment maps from step 2.1. By continuity, shrink the initial neighbourhood of finitely many times so that every intermediate image lies in the domain of the next local map. The resulting smooth map satisfies ; uniqueness of integral curves makes for every . Apply [L2] once more at , and shrink so that lies in its local-flow neighbourhood. For in a small open interval about , the formula is smooth on and, by uniqueness, equals . Hence . Since was arbitrary, is open and is smooth.
Step 3.1 makes each slice open in . For , step 1.2 gives , so and hence . The same step also yields and symmetrically for . Thus is a diffeomorphism with inverse .
Steps 1.1-4.1 show that is a smooth local flow whose time slices are exactly the maximal integral curves of . Any other local flow of has the same time slices by uniqueness of integral curves, so its domain is contained in and its map agrees with . Therefore is the unique maximal local flow generated by .