Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-02
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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A group homomorphism is injective if and only if its kernel is trivial

Statement

A group homomorphism is injective if and only if its kernel is trivial.

For a group homomorphism f:G→H, f is injective exactly when ker⁡f={eG}.

Proof

technique · direct
1.1L1L2L3L4givenalgebra

If f is injective and g∈ker⁡f, then f(g)=eH=f(eG), so g=eG.

2.1step 1.1L1L2L3L4givenalgebra

Conversely, if ker⁡f={eG} and f(x)=f(y), then f(y−1x)=eH, whence y−1x=eG and x=y.

3.1step 1.1step 2.1∎

The two implications prove the equivalence.

Depends on

Dependency tree · 2 levels

Sources