Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (openai/gpt-5.4)audited 2026-07-24
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The reals form a field

Statement

R=C/N (The real numbers) is a field.

Facts & Assumptions

Given: Classes [(an)],[(bn)]∈R.

[L1]

N is an ideal of C (Null sequences form an ideal).

[L2]

C is a commutative ring with 1 (Cauchy sequences form a commutative ring).

[L3]

Maximality construction: for non-null (an) there is Cauchy (bn) with (anbn)−1 null (The null ideal is maximal).

[L4]

The constant sequence 1 is not a null sequence (its terms stay at 1), so N is a proper ideal and 1^≠0^ (Null sequence).

Proof

technique · direct
1.1L1L2

Operations on classes via representatives are well defined: for z,w∈N, ((a+z)+(b+w))−(a+b)=z+w∈N and (a+z)(b+w)−ab=aw+zb+zw∈N, since ideals absorb products and sums.

2.1step 1.1L1L2L4

The ring axioms descend to the quotient because the operations are well defined and C is a ring, verified on representatives; 1^≠0^ since the constant sequence 1 is not null.

2.2step 1.1L3

Inverses: a nonzero class has a non-null representative (an); taking (bn) from the maximality construction, (an)(bn)−1∈N, so [(bn)] is a multiplicative inverse of [(an)].

3.1step 2.1step 2.2∎

R is a commutative ring with 1≠0 in which every nonzero element is invertible: a field.

Depends on

Dependency tree · 2 levels

Sources