Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-11
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A nonzero polynomial of degree n over an integral domain has at most n distinct roots

Statement

Let D be an integral domain. A nonzero polynomial f∈D[x] of degree n has at most n distinct roots in D.

Facts & Assumptions

Given: An integral domain D and a nonzero polynomial f∈D[x] of degree n.

[L1]

If a is a root of f, then f=(x−a)q for some polynomial q (Factor theorem over a commutative ring).

[L2]

Degrees add when nonzero polynomials over a domain are multiplied (Over an integral domain, degrees add under multiplication of nonzero polynomials).

[L3]

In an integral domain, a product is zero only if one factor is zero (Zero divisor, and integral domain: a commutative ring with 1≠0 and no zero divisors).

[L4]

If a property holds at 0 and passes from n to n+1, it holds for every natural number (The principle of mathematical induction).

Proof

technique · induction
1.1basegiven

If n=0, then f is a nonzero constant and has no root, proving the base case.

2.1step 1.1ihL1L2choose

For n>0, if f has no root the claim is immediate; otherwise choose a root a, use [L1] to write f=(x−a)q, and use [L2] to obtain deg⁡q=n−1.

3.1step 2.1ihL3L4discharge-induction∎

If b≠a is another root, then 0=f(b)=(b−a)q(b), and [L3] gives q(b)=0 because b−a≠0; the induction hypothesis bounds the roots other than a by n−1, so f has at most n roots, and [L4] completes the induction.

Depends on

Dependency tree · 2 levels

Sources