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TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generatedprecheck passverified 2026-10-15 (gpt-6-luna, gpt-6.1-sol, and delegated Codex review/repair agents; see completed run evidence)
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Proper-time parameter and normalized tangent

Statement

Let x:I→M be a C2 future timelike curve on a nonempty open interval I, with parameter s and tangent T=dx/ds. Fix c>0, s0∈I, and τ0∈R, and define ℓ(s)=−g(T,T) and τ(s)=τ0+c−1∫s0sℓ(r) dr. Then τ′(s)=ℓ(s)/c>0, so τ is an increasing C2 coordinate on its open image J=τ(I). The tangent with respect to this parameter is U=dx/dτ=cT/ℓ and satisfies g(U,U)=−c2. This is a mathematical reparametrization result; by itself it does not identify τ with a physical clock reading.

Facts & Assumptions

Given: A C2 future timelike curve and the definitions in the Statement.

[F1]

For a future timelike worldline, the proper-time density is h=−g(T,T)>0 and its integral defines proper time (Timelike worldlines, proper time, length and four-velocity on a Lorentzian four-manifold).

[F2]

The fundamental theorem gives the derivative of an integral of a continuous density (The first fundamental theorem: if f is integrable on [a,b] and continuous at c, then F′(c)=f(c); in particular a continuous f has F as a primitive); a C1 map with nonzero derivative has a local C1 inverse (The Euclidean inverse function theorem).

[F3]

The chain rule gives (x∘τ−1)′=T/(τ′) (The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a)).

Proof

1.1givenF1F2F4algebra

Since T is future timelike and continuous, −g(T,T) is a continuous positive function, so ℓ is continuous and strictly positive. By [F1] and [F2], τ is differentiable with τ′=ℓ/c>0. By [F4], the mean value theorem on each compact subinterval makes τ strictly increasing.

2.1step 1.1F2F3algebra∎

At each point the nonzero derivative gives a local inverse; injectivity makes those local inverses agree, so they define a C1 inverse on the open image J. Because T is C1 and g is smooth, ℓ is C1 and τ is C2. Its inverse is first C1 by [F2], and (τ−1)′=1/(τ′∘τ−1) is C1, so τ−1 is C2. By [F3], U=T/τ′=cT/ℓ, and hence g(U,U)=c2g(T,T)/ℓ2=−c2.

Depends on

Dependency tree · 2 levels

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