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For sigma-finite factors, the product measure exists, has the rectangle formula, is sigma-finite, and is unique
Statement
Let and be sigma-finite measure spaces. Then:
- the set function of The product measure of two sigma-finite measure spaces is a measure on ;
- for measurable rectangles, with the nonnegative extended-product convention ;
- the measure is sigma-finite; and
- it is the unique measure on with the rectangle formula.
Statement references
Facts & Assumptions
Given: Sigma-finite measure spaces and .
For every product-measurable set , (The product measure of two sigma-finite measure spaces)
Monotone convergence passes increasing limits through nonnegative integrals. (Monotone convergence for the integral)
A measure is determined by its values on a sigma-finite generating pi-system. (Measures agreeing on a generating pi-system are equal under an increasing finite-measure exhaustion from that pi-system)
The nonnegative integral is additive for finite sums of nonnegative measurable functions. (Additivity of the nonnegative Lebesgue integral)
The nonnegative integral agrees with the simple integral, whose zero coefficient on a null cell contributes zero even when another factor is infinite (The nonnegative integral agrees with the simple integral on simple functions, The integral of a nonnegative simple function).
Measurable rectangles form a pi-system that generates .
Since and are sigma-finite, there are measurable exhaustions and with .
Proof
If is a measurable rectangle, then Thus its section-measure function is , where the value outside is zero even when . The simple-function integral [L5] gives with when , and symmetrically when . This proves the rectangle formula in every extended-value case.
Let be pairwise disjoint measurable subsets of , and put . Then is a disjoint union, so for every . The section functions are nonnegative measurable, and finite additivity of their integrals gives Since the section functions for increase pointwise to that of , [L2] gives The empty set has product measure zero, so is a measure.
By [A2] and step 1.1, each rectangle has finite product measure and Hence is sigma-finite.
Let be another measure on with the same rectangle formula. Step 1.1 shows that and agree on the generating pi-system of measurable rectangles, and step 2.1 gives the required sigma-finite exhaustion. Therefore [L3] implies on all of . This proves existence, the rectangle formula, sigma-finiteness, and uniqueness.
Depends on
The product measure of two sigma-finite measure spaces
For sigma-finite measures, the two section-measure integrals of a measurable set agree
Measures on sigma-algebras
Pi-systems
Measures agreeing on a generating pi-system are equal under an increasing finite-measure exhaustion from that pi-system
Finite, sigma-finite, and semifinite measures
Monotone convergence for the integral
Additivity of the nonnegative Lebesgue integral
The nonnegative integral agrees with the simple integral on simple functions
The integral of a nonnegative simple function
The product sigma-algebra and its finite iterates