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Finite-bath canonical error bound

Statement

Let I be a finite nonempty subsystem state set, let Ei∈R satisfy ∣Ei∣≤L for L≥0, and let the dimensionless bath entropy sB be C2 on an open interval U containing [u0−L,u0+L], with ∣sB′′(u)∣≤M on that closed interval for M≥0. Use one energy unit for Ei,u0,L, so β=sB′(u0) has inverse-energy units and M has inverse-energy-squared units; δ=ML2/2 is dimensionless. Put Z:=∑j∈Ie−βEj and qi:=e−βEi/Z. Suppose the joint shell weights induce the normalized subsystem law pi:=esB(u0−Ei)/∑j∈IesB(u0−Ej). Then ∣sB(u0−Ei)−sB(u0)+βEi∣≤δ for every i, and ∑i∣pi−qi∣≤e2δ−1.

Facts & Assumptions

Given: As stated in the item.

[A1]

I is finite and nonempty; Ei∈R; L,M≥0; ∣Ei∣≤L; and sB is C2 on an open interval U containing [u0−L,u0+L] with the stated second-derivative bound. Both laws are normalized on the same state set.

[F1]

Countable canonical model: for a finite energy list and real β, qi=e−βEi/Z is the normalized canonical law.

[F2]

A uniform derivative bound gives a uniform Taylor remainder bound: a bound ∣sB′′∣≤M gives the first-order Taylor error at most M∣Ei∣2/2.

[F3]

The real exponential function and the number e by a power series, The natural logarithm as the inverse of the exponential function, and Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm: exp⁡ is a positive bijection with inverse log⁡, and log⁡(xy)=log⁡x+log⁡y for positive x,y. Thus exp⁡(u+v)=exp⁡(u)exp⁡(v): both positive sides have logarithm u+v, and log⁡ is injective.

Proof

Given: The finite subsystem, the twice differentiable bath entropy with bounded second derivative, and the stated shell-weight rule.

1.1A1F2

Apply [F2] to sB at u0 with increment −Ei. It gives sB(u0−Ei)=sB(u0)−βEi+ri where ∣ri∣≤MEi2/2≤δ.

2.1F1F3step 1.1

The marginal is therefore pi=qieri/C, where C:=∑jqjerj. The bounds e−δ≤erj≤eδ and ∑jqj=1 imply e−δ≤C≤eδ, so e−2δ≤pi/qi≤e2δ.

3.1F1F3step 2.1algebra∎

For x∈[e−2δ,e2δ], ∣x−1∣≤e2δ−1. Thus ∑i∣pi−qi∣=∑iqi∣pi/qi−1∣≤(e2δ−1)∑iqi=e2δ−1. The case δ=0 is included and gives equality of the laws.

Depends on

Dependency tree · 2 levels

Sources