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Summable canonical differentiation

Statement

Let I,Ei,gi,J,Z be as in Countable canonical model. Suppose that for every compact interval K⊂J there is a summable sequence ai≥0 such that gi(1+∣Ei∣2)exp⁡(−βEi)≤ai for every i∈I and β∈K. Then Z is positive, finite, and C2 on J, with Z′(β)=−∑igiEiexp⁡(−βEi) and Z′′(β)=∑igiEi2exp⁡(−βEi). The probabilities pi are normalized. Define Eˉ:=⟨E⟩β and Var⁡β(E):=∑ipi(Ei−Eˉ)2. These quantities are finite and satisfy −∂βlog⁡Z=Eˉ and ∂β2log⁡Z=Var⁡β(E). Moreover Hg(p)=log⁡Z+βEˉ, and its defining series is absolutely convergent.

Facts & Assumptions

Given: As stated in the item.

[F1]

Countable canonical model: Z, pi, expectation and Hg have the definitions and domains stated there. The centered variance is defined in this item's Statement.

[F3]

The natural logarithm as the inverse of the exponential function and The natural logarithm has derivative 1/x and equals the integral from 1 to x of 1/t: log⁡ is defined on positive reals and (log⁡u)′=u′/u for differentiable u>0.

[A1]

For every compact K⊂J there is a nonnegative summable sequence (ai) such that gi(1+∣Ei∣2)e−βEi≤ai for all i and β∈K; the tail ∑i>Nai tends to zero.

Proof

Given: The countable canonical model and the local summable envelope in the statement.

1.1F1A1F2F5

On a compact interval K⊂J, let ZN, DN, and QN be the first N partial sums of ∑igie−βEi, −∑igiEie−βEi, and ∑igiEi2e−βEi. Since ∣Ei∣r≤1+∣Ei∣2 for r=0,1,2, each tail is bounded uniformly on K by the corresponding tail of ∑iai, which tends to zero [A1]. Thus all three sequences converge uniformly; call their limits Z,D,Q. Each finite partial sum has the displayed derivatives by the chain rule [F5] and the exponential derivative [F2]. Each partial sum is continuous, so the uniform limits are continuous by the ε/3 definition of continuity.

2.1F2F4F5step 1.1

For an interior β and sufficiently small h≠0, apply [F4] to ZN on the interval with endpoints β and β+h: its difference quotient is DN(ξN,h) for some intermediate ξN,h. Choose N=N(h) so that sup⁡K∣ZN−Z∣<h2 and sup⁡K∣DN−D∣<∣h∣. The difference quotient for Z then differs from D(β) by at most 2∣h∣+∣h∣+sup⁡∣t−β∣≤∣h∣∣D(t)−D(β)∣, which tends to zero by continuity of D. Hence Z′=D. Applying the same argument to DN and QN proves D′=Q, so the displayed derivatives hold.

3.1F1F2F3step 2.1algebra

The summands of Z are positive and at least one is present, hence 0<Z<∞ on K; summing the definition of pi gives ∑ipi=1. The envelope gives finite first and second moments, and ∑ipi(Ei−Eˉ)2≤2∑ipiEi2+2Eˉ2<∞. Differentiating log⁡Z using [F3] yields −Z′/Z=Eˉ and Z′′/Z−(Z′/Z)2=⟨E2⟩−Eˉ2=Var⁡β(E) after expanding the defining variance.

4.1F1F2F3step 3.1∎

Since pi/gi=e−βEi/Z, its logarithm is −βEi−log⁡Z. The finite first moment makes ∑ipi∣log⁡(pi/gi)∣≤∣β∣∑ipi∣Ei∣+∣log⁡Z∣∑ipi<∞; summing the identity gives Hg=βEˉ+log⁡Z.

Depends on

Dependency tree · 2 levels

Sources