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If continuously differentiable functions converge at one point and their derivatives converge uniformly on a closed interval, then the functions converge uniformly to a differentiable function whose derivative is the derivative limit

Statement

Let $a < b$ be reals and let $f_{k} : [a, b] \to R$ be continuously differentiable: each $f_{k}$ is differentiable on $[a, b]$ and each derivative $f_{k}^{'}$ is continuous there (Continuity of $f : A \to R$ at a point of $A$ and on $A$ : the $ε$ - $δ$ condition, its agreement with $\lim_{x \to c} f (x) = f (c)$ at a limit point, and continuity at an isolated point). Suppose there is $c \in [a, b]$ such that the real sequence $(f_{k} (c))$ converges to $A$ , and suppose $f_{k}^{'} \to g$ uniformly on $[a, b]$ . Then there is a differentiable function $f : [a, b] \to R$ such that

$f_{k} ⟶ f uniformly, f^{'} = g .$

Facts & Assumptions

Given: Reals $a < b$ , a point $c \in [a, b]$ , continuously differentiable functions $f_{k} : [a, b] \to R$ , convergence $f_{k} (c) \to A$ , and uniform convergence $f_{k}^{'} \to g$ .

[L1]

A uniform limit of continuous real-valued functions is continuous, and a continuous function on $[a, b]$ is Riemann integrable (The uniform limit of continuous real-valued functions on a metric space is continuous, A continuous function on $[a, b]$ is Riemann integrable, by Heine-Cantor and Riemann's criterion).

[L2]

Uniform convergence of integrable functions preserves integrability and the limit of the integrals (A uniform limit of Riemann-integrable functions is Riemann integrable, and its integral is the limit of their integrals).

[L3]

If $s < t$ , $G$ is differentiable on $[s, t]$ , and $G^{'}$ is integrable there, then $\int_{s}^{t} G^{'} = G (t) - G (s)$ (The second fundamental theorem: if $G$ is differentiable on $[a, b]$ with $G^{'} = f$ and $f$ is integrable, then $\int_{a}^{b} f = G (b) - G (a)$ ). Restriction to a closed subinterval preserves differentiability and the derivative at its limit points, and integrability on $[a, b]$ passes to every nondegenerate closed subinterval (The derivative $f^{'} (c) = \lim_{x \to c} \frac{f (x) - f (c)}{x - c}$ of $f : A \to R$ at a point $c \in A$ that is a limit point of $A$ , and differentiability on a set, The $ε$ - $δ$ limit $\lim_{x \to c} f (x) = L$ of $f : A \to R$ at a limit point $c$ of $A$ , Limit point, isolated point, adherent point, derived set, and dense subset of $R$ , Intervals of $R$ : the nine order-convex forms, nondegeneracy, and length, A function integrable on $[a, b]$ is integrable on every closed subinterval). Finally $\int_{t}^{s} h = - \int_{s}^{t} h$ and $\int_{s}^{s} h = 0$ whenever the displayed integrals are defined (The integral with oriented limits: $\int_{a}^{a} f : = 0$ and $\int_{b}^{a} f : = - \int_{a}^{b} f$ ).

[L4]

If $g$ is continuous, its integral function $H (x) = \int_{a}^{x} g$ is differentiable with $H^{'} = g$ ; oriented additivity gives $\int_{c}^{x} g = H (x) - H (c)$ (The first fundamental theorem: if $f$ is integrable on $[a, b]$ and continuous at $c$ , then $F^{'} (c) = f (c)$ ; in particular a continuous $f$ has $F$ as a primitive, The integral function $F (x) : = \int_{a}^{x} f$ of an integrable $f$ , For $a < c < b$ : $f$ is integrable on $[a, b]$ if and only if it is integrable on $[a, c]$ and on $[c, b]$ , and then $\int_{a}^{b} f = \int_{a}^{c} f + \int_{c}^{b} f$ ; with the oriented form for arbitrary $a, b, c$ ).

[L5]

Sums and scalar multiples of differentiable functions are differentiable, with the corresponding derivative rules (Sums, scalar multiples, products and quotients: $(f + g)^{'} (c) = f^{'} (c) + g^{'} (c)$ , $(α f)^{'} (c) = α f^{'} (c)$ , $(f g)^{'} (c) = f^{'} (c) g (c) + f (c) g^{'} (c)$ , and $(f / g)^{'} (c) = (f^{'} (c) g (c) - f (c) g^{'} (c)) / g (c)^{2}$ when $g (c) \neq 0$ , The derivative $f^{'} (c) = \lim_{x \to c} \frac{f (x) - f (c)}{x - c}$ of $f : A \to R$ at a point $c \in A$ that is a limit point of $A$ , and differentiability on a set).

[L6]

A uniform bound $∣ p - q ∣ \leq η$ on an interval gives $∣ \int_{u}^{v} p - \int_{u}^{v} q ∣ \leq η ∣ v - u ∣$ (Uniformly close integrable functions have integrals differing by at most the interval length times their uniform error).

[L7]

On a subset of $R$ with its usual subspace metric, real-native continuity is equivalent to metric-space continuity (Dictionary: for $A \subseteq R$ with the metric $d (x, y) = ∣ x - y ∣$ , continuity and uniform continuity of $f : A \to R$ agree with the metric-space notions, the Lipschitz and Hölder conditions are the metric ones instantiated, and a subset of $R$ is compact in the open-cover sense of $R$ exactly when it is a compact metric subspace).

Proof

technique · constructive

1.1L1L2L7

By [L7], each real-continuous derivative $f_{k}^{'}$ is metric-continuous. The uniform-limit clause of [L1] makes $g$ metric-continuous, and [L7] makes $g$ real-continuous. The integrability clause of [L1] therefore makes every $f_{k}^{'}$ and $g$ Riemann integrable; [L2] also gives the integrability of the uniform limit.

1.2givenchoose

Let $ε > 0$ . Choose $N_{0}$ such that $∣ f_{k} (c) - A ∣ < ε / 2$ for $k \geq N_{0}$ , and choose $N_{1}$ such that $∣ f_{k}^{'} (x) - g (x) ∣ < ε / (2 (b - a + 1))$ for $k \geq N_{1}$ and all $x \in [a, b]$ .

2.1step 1.1L3

Fix $k$ and $x \in [a, b]$ . If $c < x$ , restrict $f_{k}$ to $[c, x]$ ; its derivative is $f_{k}^{'}$ there and that derivative is integrable there by steps 1.1 and [L3], so the first clause of [L3] gives $f_{k} (x) = f_{k} (c) + \int_{c}^{x} f_{k}^{'}$ . If $x < c$ , apply that clause on $[x, c]$ and then use orientation; if $x = c$ , use $\int_{c}^{c} f_{k}^{'} = 0$ . Thus in every case $f_{k} (x) = f_{k} (c) + \int_{c}^{x} f_{k}^{'}$ .

2.2step 1.1L4construct

Define $H (x) : = \int_{a}^{x} g$ and construct $f : [a, b] \to R$ by $f (x) : = A + H (x) - H (c) = A + \int_{c}^{x} g$ .

3.1step 2.2L4L5

By [L4] and [L5], $H$ is differentiable with $H^{'} = g$ , and therefore the constructed function $f = A + H - H (c)$ is differentiable with $f^{'} = g$ .

3.2step 2.2step 2.1step 1.2L6choosealgebra

Choose $N$ at least as large as $N_{0}, N_{1}$ . For $k \geq N$ and $x \in [a, b]$ , steps 2.2 and 2.1 with [L6] give $∣ f_{k} (x) - f (x) ∣ \leq ∣ f_{k} (c) - A ∣ + ∣ \int_{c}^{x} f_{k}^{'} - \int_{c}^{x} g ∣ < ε / 2 + ε ∣ x - c ∣ / (2 (b - a + 1)) < ε$ .

4.1step 3.2step 3.1discharge-construct∎

The index $N$ in step 3.2 serves every $x \in [a, b]$ , so $f_{k} \to f$ uniformly; step 3.1 gives $f^{'} = g$ . Thus the constructed $f$ has both asserted properties.

If continuously differentiable functions converge at one point and their derivatives converge uniformly on a closed interval, then the functions converge uniformly to a differentiable function whose derivative is the derivative limit

Statement

Facts & Assumptions

Proof

Depends on

Dependency tree · 2 levels

Sources