Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Spherical and stereographic pictures of the D4 arrangement

PDF p. 28: Figure 1 and caption

Example

In the D4 example with central vertex 2 and J={2}, intersect the seven relative planes in ΘJ with a unit sphere and project from its north pole to a plane. One coordinate choice gives the following line labels: H1=Hα1, H2=Hα2+α3+α4, and H3=Hα1+α2+α3+α4. The circle labels are H4=Hα3, H5=Hα1+α2+α3, H6=Hα4, and H7=Hα1+α2+α4. Here each Hβ denotes its restriction to ΘJ.

Facts & Assumptions

[F1]

For f∈ΘJ, set x=f(α1), y=f(α3), and z=f(α4). These are coordinates, and the seven relative planes are the kernels of x,y,z,x+y,x+z,y+z,x+y+z, with root labels as in Seven relative D4 hyperplanes and thirty-two chambers.

[F2]

For the unit sphere X2+Y2+Z2=1, stereographic projection from (0,0,1) has inverse (u,v)↦(2u,2v,u2+v2−1)/(1+u2+v2), as in Stereographic projection and its inverse are explicit in coordinates.

Verification

Given: The planes and projection in the Example.

Goal: Verify the stated line and circle labels for an explicit coordinate choice.

1.1F1given

Choose coordinates X=x, Y=(y+z)/2, and Z=(y−z)/2 on ΘJ, and use their standard Euclidean unit sphere. This is an invertible coordinate change. In the label order of the Example, the seven plane equations become X=0, Y=0, X+2Y=0, Y+Z=0, 2X+Y+Z=0, Y−Z=0, and 2X+Y−Z=0.

2.1F2step 1.1∎

A plane aX+bY+cZ=0 intersects the sphere in a great circle, meaning the intersection with a plane through the origin. Substitution of the inverse projection gives 2au+2bv+c(u2+v2−1)=0. If c=0, its image is a line; if c≠0, completing squares gives (u+a/c)2+(v+b/c)2=1+(a2+b2)/c2, a nonempty circle. In step 1.1 the first three equations have c=0 and the last four have c≠0. Hence their labels are respectively the three lines and four circles claimed.

Source notes

The article reference attributes the pictured labels. The displayed coordinates are one choice realizing those labels; the verification does not assume that the article specifies this coordinate choice.

Depends on

Dependency tree · 2 levels

Each result is drawn at its shortest distance from this item. Arrows run from prerequisites to the items that use them; this item has a heavier outline. External source nodes link directly to the cited text. The view shows up to two dependency steps; open a prerequisite to continue.

Sources