Alphabeta Math
LemmaStatement: AI-generatedProof: AI-generated
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Outside parabolic roots form an invariant set

Statement

Let (W,S) be a Coxeter system indexed by a possibly infinite set Γ0, acting geometrically on the real vector space V with simple-root basis (αi)i∈Γ0. For L⊆Γ0, write WL=⟨si:i∈L⟩ and ΦL={uαi:u∈WL, i∈L}. Let I⊆Γ0 and a∈Γ0∖I, and define I+a=I∪{a} and D=ΦI+a∖ΦI. Then αa∈D and wD=D for every w∈WI.

Facts & Assumptions

Given: the Coxeter system, geometric action, parabolic subgroups and root sets in the Statement. Goal: prove αa∈D and wD=D for all w∈WI.

[F1]

The vectors (αi)i∈Γ0 form a basis of V, every vector has finite support, and si(v)=v−2B(v,αi)αi, by Coxeter-system, roots, length and weak-order conventions. Define VI to be the subspace consisting of all finite real linear combinations of αi with i∈I.

[F2]

For each L⊆Γ0, the definitions WL=⟨si:i∈L⟩ and ΦL={uαi:u∈WL, i∈L} are supplied by Standard parabolic subgroups and parabolic roots. In particular, elements of WL are finite words in these involutive generators.

Proof

technique · direct
1.1F1F2given

For i∈I and v∈VI, the reflection formula gives si(v)∈VI, since both v and αi belong to VI. Thus every finite WI-word preserves VI, so ΦI⊆VI. Since a∈I+a, the identity word shows αa∈ΦI+a. Basis independence and a∉I give αa∉VI, hence αa∉ΦI. Therefore αa∈D.

2.1F2given∎

Since I⊆I+a, every WI-word is a WI+a-word, giving WI≤WI+a. For L=I or L=I+a, w∈WI and uαi∈ΦL, one has w(uαi)=(wu)αi∈ΦL. The same argument for w−1 yields wΦL=ΦL. If β∈D, then wβ∈ΦI+a; membership of wβ in ΦI would imply β∈ΦI by applying w−1, a contradiction. Thus wD⊆D, and applying this inclusion to w−1 gives wD=D.

Depends on

Used by · 2

Dependency tree · 2 levels

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