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Unique conjugator factorization restricts to a normalizer splitting
Statement
Let be a group with specified subgroups . Form the groupoid with arrows satisfying , and product . Let have only vertex arrows , and let be a wide subgroupoid. Suppose every arrow has a unique factorization with and . Then in the internal sense, and . Explicitly, every normalizer element has a unique such factorization, and the action in the usual product coordinates is .
Facts & Assumptions
The set-sized groupoid axioms, tagged arrows, vertex groups and left-to-right product are specified in Set-sized groupoids, functors and composition conversion.
A wide subgroupoid has all the objects of , contains their identity arrows, and is closed under composable products and inverses, with these operations inherited from . This is an inline definition using the groupoid structure in [F1]. The unique factorization hypothesis is an assumption of this lemma, to be supplied separately in applications. The internal groupoid semidirect notation means unique factorization and for every .
Groups and subgroups use Group and abelian group and Subgroup. The normalizer is as in The normalizer N_G(H)={g∈ G:gHg⁻¹=H} of a subgroup.
Normality means invariance under every conjugation by the ambient group, as in Normal subgroup: invariance under conjugation. The internal group semidirect product means , and , as in An internal semidirect product and a complement to a normal subgroup.
An action by automorphisms satisfies and , as in An action of a group H on a group N by automorphisms. For such an action, the external semidirect product has coordinates with multiplication , as in The external semidirect product N⋊_α H.
Proof
Given: The group, subgroup family, wide subgroupoid and assumed unique factorizations.
Goal: Prove the groupoid and normalizer semidirect conclusions.
If and , then . Identity arrows and inverse labels have the required endpoints. Associativity follows from the group multiplication. Thus the tagged arrows form the groupoid in [F1]. At , the arrow condition is equivalent to , so its vertex group is under the identification . Also is a subgroupoid because each is a subgroup.
An arrow satisfies , equivalently . Along with the assumed unique factorization this is exactly the specified internal groupoid semidirect property. By the closure and identity requirements in [F2], is a subgroup of . At a vertex, factorization gives . An element common to and has the two factorizations and , so uniqueness implies . Finally is normal in by the normalizer definition. Hence these are the internal group semidirect conditions of [F4].
For , conjugation preserves , preserves multiplication, and has inverse conjugation by , so is an automorphism. Also and , giving the action in [F5]. The map is bijective by factorization and satisfies , exactly the external semidirect group law of [F5]. This proves all vertex claims.
Depends on
- Set-sized groupoids, functors and composition conversion
- Group and abelian group
- Subgroup
- The normalizer N_G(H)={g∈ G:gHg⁻¹=H} of a subgroup
- Normal subgroup: invariance under conjugation
- An internal semidirect product and a complement to a normal subgroup
- An action of a group H on a group N by automorphisms
- The external semidirect product N⋊_α H
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