Alphabeta Math
LemmaStatement: AI-generatedProof: AI-generated
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Unique conjugator factorization restricts to a normalizer splitting

Statement

Let A be a group with specified subgroups AI. Form the groupoid C with arrows (I,g,J) satisfying g−1AIg=AJ, and product (I,g,J)(J,h,K)=(I,gh,K). Let P have only vertex arrows AI, and let R⊆C be a wide subgroupoid. Suppose every arrow g:I→J has a unique factorization g=pr with p∈AI and r∈R(I,J). Then C=P⋊R in the internal sense, and NA(AI)=AI⋊RI. Explicitly, every normalizer element has a unique such factorization, AI∩RI={1} and the action in the usual product coordinates is αr(q)=rqr−1.

Facts & Assumptions

[F1]

The set-sized groupoid axioms, tagged arrows, vertex groups and left-to-right product are specified in Set-sized groupoids, functors and composition conversion.

[F2]

A wide subgroupoid R⊆C has all the objects of C, contains their identity arrows, and is closed under composable products and inverses, with these operations inherited from C. This is an inline definition using the groupoid structure in [F1]. The unique factorization hypothesis is an assumption of this lemma, to be supplied separately in applications. The internal groupoid semidirect notation means unique factorization and AIr=rAJ for every r:I→J.

[F3]

Groups and subgroups use Group and abelian group and Subgroup. The normalizer is NA(H)={g∈A:gHg−1=H} as in The normalizer N_G(H)={g∈ G:gHg⁻¹=H} of a subgroup.

[F4]

Normality means invariance under every conjugation by the ambient group, as in Normal subgroup: invariance under conjugation. The internal group semidirect product G=N⋊H means N⊴G, G=NH and N∩H={1}, as in An internal semidirect product and a complement to a normal subgroup.

[F5]

An action by automorphisms satisfies αrs=αr∘αs and α1=id⁡, as in An action of a group H on a group N by automorphisms. For such an action, the external semidirect product has coordinates (p,r) with multiplication (p,r)(q,s)=(pαr(q),rs), as in The external semidirect product N⋊_α H.

Proof

Given: The group, subgroup family, wide subgroupoid and assumed unique factorizations.

Goal: Prove the groupoid and normalizer semidirect conclusions.

1.1F1F3algebra

If g:I→J and h:J→K, then (gh)−1AI(gh)=h−1(g−1AIg)h=AK. Identity arrows and inverse labels g−1 have the required endpoints. Associativity follows from the group multiplication. Thus the tagged arrows form the groupoid in [F1]. At I, the arrow condition g−1AIg=AI is equivalent to gAIg−1=AI, so its vertex group is NA(AI) under the identification (I,g,I)↦g. Also P is a subgroupoid because each AI is a subgroup.

2.1F2F3F4step 1.1

An arrow r:I→J satisfies r−1AIr=AJ, equivalently AIr=rAJ. Along with the assumed unique factorization this is exactly the specified internal groupoid semidirect property. By the closure and identity requirements in [F2], RI=R(I,I) is a subgroup of NA(AI). At a vertex, factorization gives NA(AI)=AIRI. An element common to AI and RI has the two factorizations x⋅1 and 1⋅x, so uniqueness implies x=1. Finally AI is normal in NA(AI) by the normalizer definition. Hence these are the internal group semidirect conditions of [F4].

3.1F3F5step 2.1algebra∎

For r∈RI, conjugation αr:q↦rqr−1 preserves AI, preserves multiplication, and has inverse conjugation by r−1, so is an automorphism. Also αrr′=αr∘αr′ and α1=id⁡AI, giving the action in [F5]. The map (p,r)↦pr is bijective by factorization and satisfies (pr)(qs)=p(rqr−1)rs, exactly the external semidirect group law of [F5]. This proves all vertex claims.

Depends on

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