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Reduced Coxeter lifts in the presented positive monoid

Statement

Let (W,S) be a finite-rank Coxeter system with length ℓ, let M be its presented positive Artin monoid, and let A be its Artin group. Write q:M→W and j:M→A for the generator maps. For a reduced expression w=s1⋯sr, set w=as1⋯asr in M. This is independent of the reduced expression, q(w)=w, and d(w)=ℓ(w). Thus w↦w is injective as a map of sets. Whenever ℓ(uv)=ℓ(u)+ℓ(v), one has uv=uv. Moreover j(w)=σw, the reduced-word lift in A. No injectivity of j is assumed here.

Facts & Assumptions

[F3]

The degree d is word length on the presented monoid. (Positive degree and atoms of the presented Artin monoid)

[F4]

The group lift σw is the product of the corresponding generators along any reduced word for w. (Reduced-word lifts and the prefix-order convention)

[F5]

The monoid M is the quotient of the free monoid on the generators as by the congruence generated by the braid relations. In particular, the two alternating words of length m(s,t)<∞ are equal in M, also inside any word context. (Positive degree and atoms of the presented Artin monoid)

Proof

Given: The objects and hypotheses in the statement.

Goal: Establish all assertions of the statement.

1.1F1F2F3F5

Any two reduced words for w are connected by the moves in [F1], and each move is an equality in the presented monoid by [F5]. Therefore w is well defined. Its image under q is w, and its degree is ℓ(w) by [F3]. Applying q shows that equal lifts have equal Coxeter elements, establishing set injectivity.

2.1F1F2F4step 1.1∎

Concatenate reduced words for u and v. If their lengths add to ℓ(uv), that concatenation is reduced and gives uv=uv by step 1.1. Applying j to a reduced word yields exactly the product defining σw in [F4]. These arguments do not cancel elements in M or assume that j is injective.

Depends on

Used by · 4

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