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Concatenation of length-additive standard expressions

PDF p. 18: Remark 4.14

Statement

Let y:I→K and z:K→L be composable morphisms in the Brink–Howlett groupoid, and put x=yz. If ℓ(x)=ℓ(y)+ℓ(z), then concatenating any chosen standard expression y for y with any chosen standard expression z for z gives a standard expression yz for x. This includes empty expressions for identity morphisms.

Proof

Given: Composable morphisms y:I→K and z:K→L, their product x=yz, the equality ℓ(x)=ℓ(y)+ℓ(z), and chosen standard expressions y and z.

Goal: Show that their concatenation is a standard expression for x.

[F1] By Standard expressions and their lengths, a standard expression is a finite composable sequence of the specified wall-crossing morphisms whose product is the morphism and whose factor lengths sum to its Coxeter length. The empty sequence represents an identity and has length sum zero; composable labels multiply in sequence order.

1.1F1given

Write y=(u1,…,um) and z=(v1,…,vn). By [F1], their sequences consist of the required wall-crossing morphisms, with products y and z and respective length sums ℓ(y) and ℓ(z). Their endpoint K agrees, so their concatenation is composable from I to L and has product yz=x. This remains true when either sequence is empty.

2.1F1step 1.1given∎

The sum of the Coxeter lengths of the concatenated factors is ℓ(y)+ℓ(z)=ℓ(x), including when a sequence is empty. Hence [F1] identifies the concatenation yz as a standard expression for x, as claimed.

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Used by · 1

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