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A nonbacktracking tail smaller than the required polynomial

Statement

Fix γ>1. With H and B as in the normalization and ordered-pair definitions, for every sufficiently large n, P(ρ(B)≥2)≤n−γ. The size cutoff may depend on γ and on the universal constants in the external theorem.

Facts & Assumptions

[F1]

The normalized matrix H is real symmetric, hence Hermitian, with independent mean-zero upper-triangular entries. It has row variance at most 1, entry variance at most 1/n, entry bound 1/q, and eventually 1≤q=γlog⁡n≤n1/10 (Normalize the logarithmic random graph for nonbacktracking estimates).

[F2]

Under independent mean-zero Hermitian upper entries with row variance sum at most 1, entry variance at most κ/n, and entry bound 1/q, Theorem 2.5 gives universal C,c>0 with P(ρ(B)≥1+t)≤Cn3−cqlog⁡(1+t) for 1∨q≤n1/10κ−1/9 and t≥0..

[F3]

The natural logarithm is strictly increasing on (0,∞), is onto R, and satisfies log⁡1=0 (Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm).

[F4]

The logarithm is inverse to the exponential (The natural logarithm as the inverse of the exponential function).

External input

For a matrix H, its nonbacktracking matrix B is indexed by ordered vertex pairs and has B(i,j),(k,l)=Hkl1j=k1i≠l. Write ρ(B)=max⁡{∣z∣:z is an eigenvalue of B}. Under independent mean-zero Hermitian upper entries with row variance sum at most 1, entry variance at most κ/n, and entry bound 1/q, Theorem 2.5 gives universal C,c>0 with P(ρ(B)≥1+t)≤Cn3−cqlog⁡(1+t) for 1∨q≤n1/10κ−1/9 and t≥0.

Proof

Given: The objects and hypotheses in the Statement.

Goal: Prove its conclusions.

1.1F1F2given

Apply [F2] to [F1] with κ=1 and t=1. This gives P(ρ(B)≥2)≤Cn3−cγlog⁡nlog⁡2. All normalization and independence hypotheses are precisely those in [F1].

2.1F3step 1.1algebra∎

By [F3], log⁡2>log⁡1=0. For each real M, surjectivity gives x>0 with log⁡x>M, and monotonicity gives log⁡n≥log⁡x>M for every integer n≥x. Hence log⁡n→∞. Since c>0 and γ>1 are fixed, eventually cγlog⁡nlog⁡2≥γ+4 and n≥max⁡{2,C}. Then the right side in step 1.1 is at most Cn−γ−1≤n−γ.

Depends on

Used by · 1

Dependency tree · 2 levels

Each result is drawn at its shortest distance from this item. Arrows run from prerequisites to the items that use them; this item has a heavier outline. External source nodes link directly to the cited text. The view shows up to two dependency steps; open a prerequisite to continue.

External dependencies

Benaych-Georges, Bordenave and Knowles, Spectral radii of sparse random matrices (19 September 2019) · PDF p. 3, Definition 2.1; p. 4, Assumption 2.4 and Theorem 2.5

Under independent mean-zero Hermitian upper entries with row variance sum at most 1, entry variance at most $\kappa/n$, and entry bound $1/q$, Theorem 2.5 gives universal $C,c>0$ with $\mathbb P(\rho(B)\ge1+t)\le Cn^{3-cq\log(1+t)}$ for $1\vee q\le n^{1/10}\kappa^{-1/9}$ and $t\ge0$.

Hypotheses: Hermitian H with independent mean-zero upper entries; q>0, kappa>=1 and all three bounds in Assumption 2.4; 1 vee q<=n^(1/10) kappa^(-1/9).

Reading limits: Checked the extracted PDF text on pp. 3–4, including Definition 2.1, Theorem 2.2, Assumption 2.4 and Theorem 2.5. The theorem is imported, not locally reconstructed; its proof and the remaining paper were not reviewed for this application.

Sources