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Convex Lipschitz concentration — Theorem 6.5

PDF p. 34: Theorem 6.5, equation (6.4); PDF p. 35: Theorem 6.5, equation (6.4)

Statement

Let d≥1 be an integer and X=(X1,…,Xd) a vector of independent random variables taking values in [0,1] on a probability space with probability P. Let f:[0,1]d→R be convex and 1-Lipschitz for Euclidean distance ∥x−y∥2=(∑i=1d(xi−yi)2)1/2. Thus convexity means f((1−λ)x+λy)≤(1−λ)f(x)+λf(y) for x,y in the cube and 0≤λ≤1, and 1-Lipschitz means ∣f(x)−f(y)∣≤∥x−y∥2 for such x,y.

Let Mf(X) be a median of f(X), meaning that P(f(X)≤Mf(X))≥1/2 and P(f(X)≥Mf(X))≥1/2. Then, for every t>0, P(f(X)>Mf(X)+t)≤2e−t2/4.

Facts & Assumptions

[F1]

For independent [0,1]-valued coordinates, a convex Euclidean L-Lipschitz function with L>0, a median m, and t>0, the upper-tail probability is at most 2e−t2/(4L2) (Convex Lipschitz concentration with its coordinate metric).

[F2]

Convexity and the Lipschitz condition use the stated Euclidean coordinate metric (Independent-entry coordinates, convexity and Lipschitz constants).

Proof

Given: The independent coordinates, convex 1-Lipschitz function, median Mf(X), and t>0 in the statement.

Goal: Prove the stated upper-tail bound.

1.1givenF1F2

The hypotheses give a convex function on the coordinate cube with Euclidean Lipschitz bound L=1 and independent [0,1]-valued coordinates. The number Mf(X) satisfies both median inequalities required by [F1].

2.1F1step 1.1algebra∎

Apply [F1] with L=1, m=Mf(X) and the given t>0. The exponent becomes −t2/4, yielding P(f(X)>Mf(X)+t)≤2e−t2/4, as claimed.

Source notes

The article attributes this concentration result to Boucheron, Lugosi and Massart, Theorem 7.12. Its displayed function domain uses n after introducing d coordinates; the statement above uses d consistently. The article reference records attribution, while [F1] supplies the argument.

Depends on

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