Alphabeta Math
LemmaStatement: AI-generatedProof: AI-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Coordinate faces of the algebraic simplex

PDF p. 4: Smooth comparison with Bloch cycles

Statement

Let k be a field, n≥0, Δn=Spec⁡k[t0,…,tn]/(∑ata−1), and X a k-scheme. For a proper subset I⊊{0,…,n}, the coordinate face FI=V(ti:i∈I) is canonically Δn−∣I∣ after ordering the remaining coordinates. On each nonempty affine open of X, the coordinates indexed by I form a regular sequence in any order: successive multiplication is injective and the final quotient is nonzero. Imposing all coordinates gives the empty scheme. If δin inserts zero at position i, then for 0≤i<j≤n and n≥2, δjnδin−1=δinδj−1n−1.

Facts & Assumptions

Given: The field, scheme, coordinates and index set in the Statement.

Goal: Establish the face descriptions, regular sequences and coordinate identities.

[F1]

On an affine open Spec⁡B⊂X, the product ring is B[t0,…,tn]/(∑ta−1); quotienting by the indicated coordinates gives the face.

Proof

1.1F1construct

Choose b∉I. Eliminate tb using tb=1−∑a≠bta. The product ring becomes a polynomial ring in the remaining coordinates over B, and quotienting by the coordinates in I leaves a polynomial ring in n−∣I∣ variables. For B=k this gives the indicated simplex with its ordered barycentric coordinates.

2.1step 1.1algebra

Multiplication by an indeterminate in a polynomial ring is injective by coefficient comparison. After quotienting by earlier distinct indeterminates, the remaining ring is again polynomial over B. Thus the sequence is regular in every order on a nonempty affine open. If all coordinates vanish, ∑ta=1 becomes 0=1, so the resulting scheme is empty.

3.1step 1.1algebra∎

Both displayed composites insert zero in positions i and j and leave the other coordinates in their original order. Their coordinate maps agree, proving the identity and the lemma.

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