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LemmaStatement: AI-generatedProof: AI-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Image filtration for a split tower

Statement

Let F∙E be equivalent as an augmented tower to the tail tower of a family (Gj)j≥0, including an equivalence E≃⨁j≥0Gj. For every integer n and q≥0, the image of πnFqE→πnE is the image of the canonical tail inclusion πn(⨁j≥qGj)→πn(⨁j≥0Gj). Moreover the quotient of this image by the corresponding image at q+1 is naturally πnGq. This statement does not require identifying homotopy groups of an infinite coproduct with a direct sum.

Facts & Assumptions

Given: The augmented tower equivalence, an integer n, and q≥0.

Goal: Identify the image filtration and its successive quotient.

[F1]
[F2]

Graded pieces of a direct-sum tail tower identifies the finite decomposition of each tail.

Proof

1.1F1givenconstruct

The commutative augmentation square in the specified equivalence identifies the two displayed images. The tail inclusion has a retraction induced by identity maps on summands indexed at least q and zero maps on the others; thus its map on homotopy groups is injective.

2.1F2step 1.1∎

By [F2], Tq≃Tq+1⊕Gq. Applying πn to this finite biproduct gives πnTq≅πnTq+1⊕πnGq. Under the injection from step 1.1, the quotient of the two successive images is consequently πnGq, naturally in the specified splitting.

Depends on

Used by · 2

Dependency tree · 3 levels

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