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Omega replacement preserves sequential stable groups

PDF p. 3: Filtered S1 spectra: stable enhancement prerequisites

Statement

Let X be a level-Kan sequential pointed simplicial prespectrum with sphere-first structure maps K∧Xn→Xn+1, K=Δ1/∂Δ1. For the replacement QX of the simplicial Omega replacement input, the natural map Gk(X)→Gk(QX) is an isomorphism for every integer k. More precisely, for i+k≥2 there is a natural isomorphism πi+k((QX)i)≅Gk(X), compatible with advancement in i.

Facts & Assumptions

Given: X, k and i as in the Statement.

Goal: Compute the stable groups of the imported Omega replacement.

[F1]

External sequential simplicial Omega replacement gives (QX)i=colim⁡mΩmXi+m, its structure maps, and ιRX=RιX.

[F2]

Cofinal tails and level invariance of stable groups identifies a sequential colimit with any cofinal finite tail.

Proof

1.1givenconstruct

A filtered colimit of Kan simplicial sets is Kan: a horn has finitely many simplices, so a map from it factors through a stage and a filler there gives a filler in the colimit. Homotopy groups commute with this colimit because representatives use finite simplicial spheres and homotopies use their finite products with Δ1. Such maps and homotopies factor through stages, and equalities between finitely many simplices occur at a common later stage. The group operation is preserved by functoriality.

2.1F1F2step 1.1

By step 1.1 and iterated loop–suspension adjunction, πi+k((QX)i)≅colim⁡mπi+k+m(Xi+m)=Gk(X). Under [A,ΩB]≅[K∧A,B], each new loop coordinate is inserted on the left. Consequently the transition Ωmι adds the new inner loop coordinate on the left and corresponds exactly to suspension with K first followed by the structure map. The last equality uses the cofinal tail.

3.1F1F2step 2.1∎

The map Xi→(QX)i inserts the m=0 term. By ιRX=RιX, the adjoint structure maps of QX identify advancement in i with the same transition in the colimit of step 2.1. Thus these isomorphisms are compatible in i, and the map Gk(X)→Gk(QX) becomes the identity under them. This proves both assertions.

Depends on

Used by · 1

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