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How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Arithmetization, Incompleteness, and Relative Consistency: Examples and Counterexamples

1 · Prerequisites

2 · Summary

The examples calculate a diagonal substitution, a conservative explicit function definition and an actual finite refutation support. The two conditional model examples retain their external consistency hypotheses and distinguish a nonstandard proof belief from a real proof, and an ordinary set model from a transitive one.

3 · Logical flowchart

4 · Definitions, theorems and proofs

None yet.

5 · Examples, counterexamples and false statements

ExampleConstruction: AI-adaptedVerification: AI-adaptedaudited 2026-09-10Open item page →

A diagonal substitution worked symbolically

Example

Take ψ(y)(y=y) in the diagonal construction. With D representing the diagonal substitution function d, let η(x)=y(D(x,y)y=y), e=#η, and θ=η(eˉ). Then d(e)=#θ and Q proves θθ=θ.

Facts & Assumptions

[F1]

The syntactic diagonal lemma: For every formula ψ(v) with no other free variables in an effective signature extending arithmetic, there is a sentence θ such that Q in that signature proves θψ(θ). The construction is effective and requires neither consistency nor soundness.

Verification

Given: The explicit tautological psi and the fixed diagonal construction with its representing graph D.

1.1

The substitution operation in F1 takes the formula eta with its designated x place and inserts the numeral eˉ. Thus d(e)=#(y(D(eˉ,y)y=y))=#θ. Here e is a natural number, eta is a formula, and the inserted eˉ is a term; none is identified with the other. The unique-value property used in F1 gives QD(eˉ,y)y=θ.

F1given
2.1

If theta holds, choose its y witness; the equation in step 1.1 replaces y with the numeral of theta, yielding that numeral equal to itself. Conversely that reflexive equality and D(eˉ,θ) give the existential theta. Thus in this concrete instance Q proves theta, as well as the displayed biconditional. The calculation is independent of which fixed token numbering produces the numerical value e.

step 1.1algebra
ExampleConstruction: AI-adaptedVerification: AI-adaptedaudited 2026-09-10Open item page →

A consistent theory can believe it has a proof of contradiction

Example

If PA is externally consistent, then PA+¬Con(PA) is consistent and has a set model. In every such model a code it regards as a PA-refutation is nonstandard.

Facts & Assumptions

[F1]

Deduction theorem for sentence assumptions: In ZF, for a sentence theory T, a sentence σ and any formula θ,

T{σ}θTσθ.

The forward transformation also works for an open discharged assumption σ provided every variable generalized or existentially eliminated in the given derivation is absent from FV(σ); the other assumptions remain sentences.

[F2]

Second incompleteness for standard provability: If T is consistent and has the arithmetic/interpretation and D1–D3 hypotheses above for the displayed standard predicate, T does not prove its displayed Con(T). Numeralwise correctness of an arbitrary predicate is insufficient.

[F3]

Models and consistency for countable theories: In external ZF, an explicitly countable sentence theory is consistent iff it has a nonempty set model, and iff it has a model with carrier injecting into ω. For an effective presentation, external consistency agrees with the truth of its certified Con formula in standard arithmetic. No transitivity or external well-foundedness of a model follows.

[F4]

Robinson arithmetic, PA, and numeral conventions: Use the arithmetic signature 0,S,+,,=. Robinson arithmetic Q consists of the universal closures of these seven formulas:

Sx0;Sx=Syx=y;x0yx=Sy; x+0=x;x+Sy=S(x+y);x0=0;xSy=xy+x.

PA adds, for every formula ϕ(x,zˉ), the universal closure of [ϕ(0,zˉ)x(ϕ(x,zˉ)ϕ(Sx,zˉ))]xϕ(x,zˉ). Parameters zˉ are allowed. No induction schema is included in Q.

For an external natural number n, its numeral is the term nˉ=Sn0. Define xy by z(z+x=y) and x<y by xyxy, with z fresh. The left-addend witness is intentional: commutativity is not an axiom of Q.

Use def-set-coded-formal-derivation for the six logical schemes and three rules. Negation, conjunction and existential quantification are primitive: AB expands to ¬(A¬B), AB to ¬(¬A¬B), and xA to ¬x¬A. Inequality means negated equality. Substitute capture-free, always taking the least available fresh variable index and universally closing the remaining parameters in increasing index order. Thus each displayed axiom and each induction instance is a definite finite sentence.

Verification

Given: External consistency of PA and its standard certified Con predicate.

1.1

If the extension were inconsistent, sentence deduction F1 would give PA¬Con(PA), and classical logic would yield PACon(PA). This contradicts F2 under the assumed consistency, so the extension is consistent. F3 gives a nonempty set model N.

F1F2F3given
2.1

N satisfies the added axiom, hence has an element c satisfying its arithmetic proof predicate for a PA-refutation. For each external n, consistency says n is not an actual refutation code. Numeralwise correctness of the standard predicate (as required in F2) gives a Q, hence PA, proof negating that instance, so N satisfies its negation at nˉN. Therefore cnˉN for every external n. This is the promised nonstandard witness, not an externally correct finite proof. The numeral convention is F4.

F2F4step 1.1
ExampleConstruction: AI-adaptedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

A uniquely defined function adds no old-language theorems

Example

Adding xf(x)=x+x to PA is conservative. For example f(2ˉ)=4ˉ expands to the ordinary PA calculation 2ˉ+2ˉ=4ˉ. An added constant c with all axioms nˉ<c for external n is not a single explicit definition; no nonconservativity claim about that separate axiom family is made.

Facts & Assumptions

[F1]

Explicit definitions are conservative: Adding relation symbols by old-language defining formulas and function symbols by old-language graphs that T proves uniquely total gives a conservative extension of T. The extension is equiconsistent with T. This includes any set of such definitions, since a proof uses only finitely many.

[F2]

Robinson arithmetic, PA, and numeral conventions: Use the arithmetic signature 0,S,+,,=. Robinson arithmetic Q consists of the universal closures of these seven formulas:

Sx0;Sx=Syx=y;x0yx=Sy; x+0=x;x+Sy=S(x+y);x0=0;xSy=xy+x.

PA adds, for every formula ϕ(x,zˉ), the universal closure of [ϕ(0,zˉ)x(ϕ(x,zˉ)ϕ(Sx,zˉ))]xϕ(x,zˉ). Parameters zˉ are allowed. No induction schema is included in Q.

For an external natural number n, its numeral is the term nˉ=Sn0. Define xy by z(z+x=y) and x<y by xyxy, with z fresh. The left-addend witness is intentional: commutativity is not an axiom of Q.

Use def-set-coded-formal-derivation for the six logical schemes and three rules. Negation, conjunction and existential quantification are primitive: AB expands to ¬(A¬B), AB to ¬(¬A¬B), and xA to ¬x¬A. Inequality means negated equality. Substitute capture-free, always taking the least available fresh variable index and universally closing the remaining parameters in increasing index order. Thus each displayed axiom and each induction instance is a definite finite sentence.

Verification

Given: PA with its displayed addition axioms and the graph y=x+x.

1.1

Use the graph F(x,y):=y=x+x. For every x, taking the term x+x gives existence, and equality transitivity gives uniqueness. Hence F1 applies. Eliminating f from f(2ˉ)=4ˉ gives y(y=2ˉ+2ˉy=4ˉ), equivalent to 2ˉ+2ˉ=4ˉ. By the addition axioms F2, 2ˉ+S(S0)=S(2ˉ+S0)=S(S(2ˉ+0))=S(S2ˉ)=4ˉ.

F1F2given
2.1

At zero the same graph gives f(0)=0+0=0. At one, f(S0)=S0+S0=S(S0+0)=S(S0)=2ˉ. In contrast the formulas nˉ<c form a separate infinite family indexed externally by n; they contain no old-language uniquely total defining graph for c as specified. The conservativity conclusion above comes from the displayed graph F, not from misclassifying that family as one defining equation.

F2step 1.1
False statementConstruction: AI-adaptedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

Consistency does not justify a transitive ZFC model

Statement

False proposed implication over ZFC: Con(ZFC)TM(ZFC). Assuming externally Con(ZFC+Con(ZFC)), there is a set model of ZFC in which this implication fails.

Facts & Assumptions

[F1]

The transitive-model consistency-strength gap: Let S=ZFC+Con(ZFC). Assuming externally Con(S), ZFC does not prove Con(ZFC)TM(ZFC). Moreover S+¬TM(ZFC) is consistent and has a set model. The stronger external premise Con(S) is retained.

Refutation

Given: External Con(ZFC+Con(ZFC)) and the standard arithmetic Con and actual-membership TM formulas.

1.1

Under exactly the stated external premise, F1 supplies a nonempty set model N of ZFC+Con(ZFC)+¬TM(ZFC). This N is the countermodel witness and meets the ZFC hypothesis of the proposed assertion.

F1given
2.1

In N the antecedent Con(ZFC) is true by its added axiom, while the consequent TM(ZFC) is false by the other added axiom. Thus the implication is false in N by its Boolean satisfaction rule. The supplied model can be at most countable, but its relation is not asserted to be actual membership and it is not asserted to be transitive. Neither countability nor mere consistency repairs the proposed conclusion.

step 1.1algebra
ExampleConstruction: AI-adaptedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-10Open item page →

A hypothetical refutation selects one finite target fragment

Example

A finite derivation uses only its finite axiom support. For a concrete refutation, let U contain the two sentences A=x(x=x) and ¬A. The derivation from these two axioms and a propositional explosion instance has support Δ={A,¬A}, regardless of U's other axioms.

Facts & Assumptions

[F1]

Finite-fragment model transfer proves relative consistency: Let T extend enough ZF to formalize set-model soundness, and let U be an explicitly countable sentence theory. Suppose that for each external finite ΔU there are a finite Γ and T proofs of existence of a suitable TM/CTM of Γ and of its conversion into a set model of Δ. Then external Con(T) implies Con(U). This is a metatheorem with fixed finite proof inputs, not a uniform internal all-fragment assertion.

[F2]

Formal consistency transfer from a verified reduction: If an arithmetic base B verifies a total code map r and p(PrfU(p,)PrfT(r(p),)), then BCon(T)Con(U). For reflection/finite-fragment applications the support extractor, fragment maps and reflection/transfer/soundness proof constructors must actually be supplied and verified to obtain such an r.

Verification

Given: The displayed two-axiom refutation, and separately the fragment-transfer hypotheses when compiling it into T.

1.1

The five-line derivation is: line 0, A; line 1, not-A; line 2, the logical tautology A(¬A); line 3, ¬A by MP at 0,2; line 4, bottom by MP at 1,3. Its two nonlogical axiom lines give exactly Δ={A,¬A}. The set of support lines has size 2, while the proof has length 5. Adding or repeating unrelated U axioms does not alter these premise references.

givenalgebra
2.1

For this Delta the hypotheses of F1 would give a finite source fragment Gamma, a T proof of its suitable source-model existence, and a T proof converting that model into a model of Delta. But any Delta model satisfies both A and not-A, impossible, so appending the formal soundness proof of the displayed five-line derivation compiles a T-refutation. For a general proof with k axiom lines, taking their set gives at most k distinct axioms, and the same assembly depends only on that set.

F1step 1.1
3.1

To make this a B proof of a Con implication via F2, verify in B each arrow: extracting Delta from p, computing Gamma, generating its existence proof, generating the transfer proof, and appending the soundness/refutation block. A fixed finite assembly in step 2.1 does not by itself verify those maps uniformly. In the concrete proof, the extractor merely reads lines 0 and 1; its output contains neither the tautology nor the MP lines.

F2step 1.1step 2.1

Sources