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CounterexampleConstruction: AI-generatedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-13
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A monotone functor between poset categories preserves every monomorphism but need not preserve pullbacks

Statement refuted

Every functor that preserves monomorphisms preserves pullbacks.

Facts & Assumptions

Given: The diamond poset P={0,a,b,1} with 0<a<1, 0<b<1, and a,b incomparable; and the two-element chain Q={0<1}.

[F1]

Pullbacks have the compatible-pair universal property (Pullbacks and pushouts as limits and colimits of cospans and spans).

[L1]
[F2]
[F3]

A poset is a category with at most one arrow between any two objects, and monotone maps are functors (A preorder is a category with at most one morphism between any two objects, and its functors are exactly monotone maps).

Counterexample

technique · finite posets
1.1

Define the monotone map F:PQ by F(0)=0 and F(a)=F(b)=F(1)=1. By [F3] it is a functor. Every arrow in either poset category is monic, since two parallel arrows are automatically equal; hence F preserves every monomorphism.

F2F3
1.2

In P, the pullback of a1b is the meet ab=0, as follows directly from [F1] after translating arrows to inequalities. Its image is 0.

F1F3
2.1

The image cospan in Q is 111, whose pullback is 1. The canonical comparison is the noninvertible arrow 01, so [L1] says that F does not preserve this pullback. This refutes the statement.

F1L1step 1.2

Depends on

Used by

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