Alphabeta Math
CounterexampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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A noncompactly supported form whose integral diverges

Statement refuted

False assertion: smoothness alone guarantees a finite integral of a top form on an oriented manifold, without a compact-support or convergence condition.

Facts & Assumptions

[F1]

Chart integral with its orientation sign: Let Mn be oriented and ω a smooth top form with compact support contained in a connected chart (U,ϕ). For n1 write (ϕ1)ω=fdx1dxn. Let σϕ{1,1} be the sign of its coordinate frame relative to the chosen orientation. Define the chart integral by Iϕ(ω)=σϕRnf~(x)dx. Here f~ is the Riemann-integrable zero extension, including across a genuine half-space face, as in lem-chart-supported-coefficients-have-well-defined-riemann-integrable-half-space-extensions. For n=0, a connected chart is a point p, and set Ip(ω)=ε(p)ω(p) using its determinant-line sign. Empty support gives zero. Negative charts are allowed: the upper-half-line chart u=bt at the right endpoint of an increasing interval has sign 1.

Counterexample

Given: The proposed assertion; use the data constructed below.

1.1

On the increasingly oriented line the form dx is smooth, but its support is all of R, which is not compact. Its restriction to every compact interval [R,R], R>0, has the ordinary integral RR1dx=2R, computed using chart integration or a finite endpoint chart partition.

F1algebra
2.1

The values 2R are unbounded as R increases. Hence even the elementary symmetric improper-integral attempt fails to give a finite value. The compact-support integral defined on this page is simply inapplicable to dx on the whole line; the calculation does not introduce a general improper manifold integral.

step 1.1algebra

Depends on

Used by

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Dependency tree · two levels

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Sources