Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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A singular cochain need not have finite support on singular simplices

Statement refuted

Refuted claim: every singular cochain on a singular chain group is supported on only finitely many singular simplices.

On the interval I=[0,1], define a homomorphism φ:C0(I;Z)Z by φ(σ)=1 for every singular 0-simplex σ:Δ0I. This is a perfectly valid singular 0-cochain, but it is nonzero on every singular 0-simplex.

Facts & Assumptions

Given: The interval I=[0,1].

[L1]

Singular 0-chains are finite integer linear combinations of singular 0-simplices (Singular simplices and singular chain groups with coefficients).

[L2]

For each point xI, the constant map cx:Δ0I is a singular 0-simplex (Singular simplices and singular chain groups with coefficients).

Counterexample

technique · direct
1.1

The assignment φ(σ)=1 on each singular 0-simplex extends uniquely to a homomorphism from the free abelian group C0(I;Z) to Z, so it is a singular 0-cochain in the usual dual-group sense.

L1given
2.1

By [L2], each point xI determines a singular 0-simplex cx, and distinct points give distinct maps, so I has infinitely many singular 0-simplices. The cochain φ takes the value 1 on every one of them, so its support is infinite.

L2step 1.1
3.1

Thus φ is a singular cochain whose support is not finite, refuting the claim.

step 2.1

Depends on

Used by

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Dependency tree · two levels

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Sources