Alphabeta Math
CounterexampleConstruction: AI-generatedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-27
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

C^2 minus a complex line is a domain of holomorphy

Statement refuted

Refuted claim: removing a complex line from C2 produces a domain that still cannot be a domain of holomorphy.

Facts & Assumptions

Given: The domain Ω={(z1,z2)C2:z10}.

[L1]

A domain of holomorphy is tested by whether every holomorphic function extends through one fixed larger overlap (Holomorphic extension and domains of holomorphy in several variables).

Counterexample

technique · direct
1.1

The function f(z1,z2)=1/z1 is holomorphic on Ω.

givenalgebra
2.1

If f extended holomorphically across any point of the missing hyperplane {z1=0}, then z1f would extend holomorphically there as the constant function 1, forcing f=1/z1 near that point and hence forcing a holomorphic function equal to 1/z1 at z1=0, which is impossible. So the missing complex line blocks extension, and Ω is a domain of holomorphy rather than a Hartogs hole.

step 1.1L1algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources