Alphabeta Math
CounterexampleConstruction: AI-generatedVerification: AI-adaptedPipeline-generatedprecheck pass
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Commutativizing the target erases the A₂ wall-crossing identity

Statement refuted

The A₂ quantum-dilogarithm wall identity is not preserved if the skew quantum torus product is replaced by ordinary commutative multiplication while its factor normalization is kept. In the commutative formal power-series ring in x1,x2 over Q(t), the resulting claimed equality is Et2(x2)Et2(x1)=Et2(x1)Et2(tx1x2)Et2(x2),Et2(x)=∑n≥0tnxn∏r=1n(t2r−1).

Facts & Assumptions

Given: A formal variable t and the series displayed in the refuted claim.

[F1]

The degree-one coefficient of Et2(x) is c1=t/(t2−1), directly from its defining series.

[F2]

The A₂ chamber products arise from the completed skew Hall integration and the subobject-first normalization (Euler and skew integration are multiplicative for finite acyclic quivers, Completed Hall wall crossing for finite acyclic quivers).

Counterexample

Given: The commutative power-series ring and the displayed candidate identity.

1.1F1algebra

In the left side, the coefficient of bidegree (1,1) can only come from the linear term of each of the two factors. It is therefore c12.

1.2F1algebra

In the right side, that bidegree receives the contribution c12 from the linear terms of the first and third factors, and the contribution tc1 from the linear term of the middle factor. All remaining terms have a coordinate degree exceeding (1,1) in at least one variable. Thus its coefficient is c12+tc1.

2.1F1F2step 1.1step 1.2algebra∎

The difference is tc1=t2/(t2−1), a nonzero rational function (and nonzero at every finite-field specialization t=q>1). The two formal series are unequal, so ordinary commutative multiplication cannot retain the A₂ wall identity. This is exactly why the target skew twist is part of the theorem's normalization.

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