Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passaudited 2026-09-04
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The Euler-product identity does not survive after leaving the absolute half-plane

Statement refuted

Once a multiplicative Dirichlet series is written as an Euler product on its absolute half-plane, the same prime-by-prime regrouping remains valid on the boundary or beyond.

Facts & Assumptions

Given: The Dirichlet series ζ(s)=n1ns.

Counterexample

technique · direct
1.1

On s>1, [L1] gives ζ(s)=p(1ps)1. At the boundary point s=1, however, the Dirichlet series is the harmonic series and diverges. So there is no value of the left-hand side there to which the proved Euler-product identity could apply.

L1givenalgebra
2.1

This already refutes the claimed boundary extension: the theorem proving the Euler product does not license prime-factor regrouping once absolute convergence is lost.

step 1.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources