Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

An L1 transform need not be integrable

Statement refuted

Every integrable function on R has an integrable Fourier transform.

Facts & Assumptions

[F1]

The transform of f=1[1/2,1/2] is sin(πξ)/(πξ), with value one at zero (Transform of an interval indicator).

Counterexample

1.1

Take the f in F1, whose integral and norm are one. For integer k1 and ξ[k+1/6,k+5/6], sin(πξ)1/2. Consequently f^(ξ)1/[2π(k+1)] on an interval of length 2/3, and its integral there is at least 1/[3π(k+1)].

F1given
2.1

These intervals are disjoint. The sum of their lower bounds diverges: the block 2mk<2m+1 contributes at least 2m/[3π2m+1]=1/(6π). Hence f^=, despite f1=1. The failure concerns absolute integrability, not continuity or decay of the transform. Countable choice is inherited from F1 and Lebesgue interval measure.

F1step 1.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources