How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced — the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted — a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated — a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
The Axiom of Countable Choice ()
Definition
The Axiom of Countable Choice, written , is the following statement.
For every family of nonempty sets indexed by there is a function with domain such that for every .
Equivalently, in the vocabulary of Choice function: every at most countable family of nonempty sets (Finite, countably infinite, countable, uncountable) has a choice function.
Remarks
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The two formulations are equivalent, and the passage between them uses no choice. Given an at most countable family of nonempty sets, either , where the empty function is a choice function, or a surjection exists (A nonempty set is at most countable iff it is a surjective image of ); applying the indexed form to gives with , and is a choice function for , the minimum being canonical by The well-ordering principle. Conversely a choice function on the at most countable family gives .
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is strictly weaker than the Axiom of Choice (The Axiom of Choice): AC implies it immediately, since AC applies to every family, while it is consistent with ZF that holds and AC fails. It is also strictly stronger than what ZF proves: it is consistent with ZF that fails, as Cohen's first model shows, since an infinite set of reals with no countably infinite subset (Cohen's first model: an infinite Dedekind-finite set of reals ‡) is already a failure of ; the Feferman-Levy model (The Feferman-Levy model: the reals as a countable union of countable sets ‡) is a second witness. Both statements are conditional on the consistency of ZF and are external results, established by forcing and by permutation models; they are recorded here with references and are not proved in this library, which contains neither technique. Of the two, only the failure of is recorded in this library's catalogue of unproved results; the separation of from AC in the other direction is quoted from the references alone.
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Dependent choice sits between them. The Axiom of Dependent Choice (DC) says that if is a relation on a nonempty set such that every has some with , then there is a sequence with for all . In ZF, ; both implications are theorems of ZF, and neither is proved here. That neither reverses is a pair of relative-consistency results of the same kind as in the previous bullet: if ZF is consistent, then so are ZF + DC + (not AC) and ZF + + (not DC). Both are established by forcing and by permutation models, are quoted here from the references rather than proved, and cannot be stated without the consistency hypothesis; so "DC is strictly between AC and " is shorthand for those two conditional statements and is never used here as a standalone assertion. DC is the principle that legitimises "choose , then choose depending on , and so on"; only legitimises countably many independent choices made at once.
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Being an axiom, carries no well-definedness obligation, which is why this item has no
justified_by. Its role in this library is bookkeeping: Countable unions of at most countable sets, assuming assumes it and flags the exact step that spends it, and FALSE: countable unions of countable sets are countable is a theorem of ZF records that the assumption cannot be removed. -
Every result proved on this page other than Countable unions of at most countable sets, assuming is a theorem of ZF alone. In particular Every subset of an at most countable set is at most countable, A nonempty set is at most countable iff it is a surjective image of , The Schröder-Bernstein theorem, is countably infinite, Cantor's theorem: and is uncountable (Cantor's nested intervals, 1874) are choice free, and each says so. The false statements at the end of the page are not all of that kind, and the claim above does not cover them: two of the three refute a ZF-provability claim only under the hypothesis that ZF is consistent, quoting an external independence result rather than proving it, and they say so in their own Facts.
Depends on
Used by
- Assuming AC_ω and DC, compactness, sequential compactness, countable compactness, limit point compactness, completeness and total boundedness, pseudocompactness, closedness and boundedness, and the extreme-value property are equivalent for nonempty subsets of ℝⁿ with n≥1 Corollary
- Assuming countable choice, perfect normality, and hence T₆, is hereditary Corollary
- Every pointwise-bounded equicontinuous sequence in C(K,ℝ) has a uniformly convergent subsequence Corollary
- Under dependent choice a normal T₁ space is completely regular, so T₄ ⟹ T_31/2, and together with the implications already proved this is the whole classical chain Corollary
- Assuming choice, two paracompact lower-limit lines can have a nonparacompact product Counterexample
- Refuted, assuming countable choice: every Hausdorff space built from ordinal spaces is normal. The deleted Tychonoff plank ((ω₁ + 1) × (ω + 1)) ∖ {(ω₁, ω)} is Hausdorff and not normal Counterexample
- Refuted: every limit ordinal has an at most countable cofinal subset — ω₁ has none, assuming countable choice Counterexample
- Nowhere dense, meager (first category), residual, and second category subsets of ℝ Definition
- The axiom of dependent choice: a relation in which every element is related to something admits an ℕ-indexed chain Definition
- A Lipschitz function on ℚ extends uniquely to a Lipschitz function on ℝ with the same constant Example
- Assuming countable choice, a strictly increasing ω-sequence of countable ordinals has a countable supremum, which is a countable limit ordinal below ω₁; the instance supₙ ω·(n+1) = ω² needs no choice Example
- Assuming countable choice, cf(ℵ_ω₁) = ℵ₁, so singular does not mean of countable cofinality Example
- Assuming the Ultrafilter Lemma and Countable Choice, an uncountable Cantor cube is compact Hausdorff and uniformizable but not first countable, hence not metrizable Example
- ℝ and ℚ are σ-compact, and Lindel"of assuming countable choice; ℝ is locally compact and ℚ is nowhere locally compact Example
- ℝ with the half-open intervals [a,b) as a basis is not compact and, assuming the Axiom of Countable Choice, is Lindel"of, while its square is not Lindel"of, the antidiagonal being an uncountable closed discrete subspace Example
- The long ray is connected and locally connected, every proper initial segment is order-convex and connected, and, assuming countable choice, no at most countable subset is cofinal Example
- Under the Axiom of Countable Choice and the Axiom of Dependent Choice, the family x↦|x-a|, a∈[0,1], is compact in C([0,1]) Example
- ω + 1 as a convergent sequence together with its limit, and, assuming countable choice, [0, ω₁), in which every sequence lies inside an at most countable initial segment Example
- Assuming choice, refuted: paracompactness is productive False statement
- Assuming countable choice, refuted: Lindelöfness is productive False statement
- FALSE: a totally bounded metric space is compact False statement
- FALSE: countable unions of countable sets are countable is a theorem of ZF False statement
- FALSE: every countably compact space is compact False statement
- FALSE: every infinite set has a countably infinite subset, in ZF False statement
- FALSE: every sequentially compact space is compact False statement
- FALSE: the compact-open topology on C(X,Y) is metrizable for every metric X and Y False statement
- A compact metric space has a countable dense subset, by countable choice Lemma
- A point lies in the closure of A ⊆ ℝ iff some sequence in A converges to it, so a subset of ℝ is closed iff it is sequentially closed Lemma
- Assuming countable choice, every countably compact paracompact Hausdorff space is compact Lemma
- Assuming countable choice, the deleted Tychonoff plank is a regular nonnormal open subspace of a compact Hausdorff normal space Lemma
- Subsets and countable unions of null subsets of ℝᵐ are null Lemma
- The lower-limit line has a clopen basis, is regular, and is Lindelöf under countable choice Lemma
- Under choice, the uncountable Δ-system lemma for finite sets Lemma
- Under countable choice, every regular Lindelöf space is paracompact Lemma
- Choice ledger for this page: ω₁ exists in ZF, and the boundedness theorem does not Remark
- Conventions on this page, and the one implication of the classical chain that is not available at this point in the reading order Remark
- The quasicompact convention, why compactness of a subset is read intrinsically here, and what each result on this page costs in choice Remark
- The sequence-to-ε direction of the Heine criterion uses countable choice for ℝ, and where this library records that cost Remark
- What each implication between the compactness properties of a metric space costs: which are theorems of ZF, which use countable choice, and which use dependent choice Remark
- What each result on this page costs in choice, and where the continuum escapes what ZFC can decide Remark
…and 37 more results.
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 50 results over 21 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- D. H. Fremlin, Measure Theory, Chapter 56 (standard reference, not scraped)
- Axiom of countable choice (Wikipedia) (standard reference, not scraped)
- Axiom of dependent choice (Wikipedia) (standard reference, not scraped)
- Axiom of choice (Wikipedia) (standard reference, not scraped)