Alphabeta Math
CorollaryStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-14
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Commuting nearby group elements have commuting logarithms under the stated domain hypotheses

Statement

Assume ACω. There is an exponential neighborhood U of the identity such that, whenever g,hU commute and X=logGg, Y=logGh, one has [X,Y]=0.

Facts & Assumptions

Given: The stated group and local logarithm.

[F1]

The local logarithm is inverse to the exponential on its fixed domain. Local logarithm on a Lie group.

[F2]

Conjugation intertwines exponential, and AdexpX=eadX under countable choice. Adjoint intertwines the exponential map. Adjoint exponential identity. The Axiom of Countable Choice (ACω).

[F3]

The entire operator series D(A)=n0An/(n+1)! has constant term I. Right-trivialized differential of the Lie-group exponential.

Proof

technique · direct
1.1

The map (g,Y)AdgY is continuous and equals Y at g=e. Shrink the logarithm neighborhood so that Y and AdgY both lie in its exponential chart whenever g,hU and Y=logGh. Since the power series D(adX) depends continuously on X and equals I at X=0, shrink once more so it is invertible for every X=logGg.

F1F2F3
2.1

If gh=hg, then ghg1=h. With h=expGY, [F2] gives expG(AdgY)=expGY. Both exponents lie in the injectivity domain fixed in step 1.1, so AdgY=Y.

F1F2step 1.1
3.1

Write g=expGX. By [F2], (eadXI)Y=0. The power-series identity eAI=D(A)A gives D(adX)[X,Y]=0; invertibility from step 1.1 yields [X,Y]=0.

F2F3step 1.1step 2.1algebra
4.1

The group is nonempty. In dimensions zero and one the conclusion is automatic. Singular adX is allowed because only D(adX), close to I, is inverted. There is no interval, endpoint, metric, or biconditional. ACω is inherited exactly through [F1]–[F3]; finitely many neighborhood shrinkings add no choice.

F1F2F3step 1.1step 2.1step 3.1

Depends on

Used by

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