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CorollaryStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-14
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Commuting nearby group elements have commuting logarithms under the stated domain hypotheses

Statement

Assume ACω. There is an exponential neighborhood U of the identity such that, whenever g,h∈U commute and X=log⁡Gg, Y=log⁡Gh, one has [X,Y]=0.

Facts & Assumptions

Given: The stated group and local logarithm.

[F1]

The local logarithm is inverse to the exponential on its fixed domain. Local logarithm on a Lie group.

[F2]

Conjugation intertwines exponential, and Ad⁡exp⁡X=ead⁡X under countable choice. Adjoint intertwines the exponential map. Adjoint exponential identity. The Axiom of Countable Choice (ACω).

[F3]

The entire operator series D(A)=∑n≥0An/(n+1)! has constant term I. Right-trivialized differential of the Lie-group exponential.

Proof

technique · direct
1.1F1F2F3

The map (g,Y)↦Ad⁡gY is continuous and equals Y at g=e. Shrink the logarithm neighborhood so that Y and Ad⁡gY both lie in its exponential chart whenever g,h∈U and Y=log⁡Gh. Since the power series D(ad⁡X) depends continuously on X and equals I at X=0, shrink once more so it is invertible for every X=log⁡Gg.

2.1F1F2step 1.1

If gh=hg, then ghg−1=h. With h=exp⁡GY, [F2] gives exp⁡G(Ad⁡gY)=exp⁡GY. Both exponents lie in the injectivity domain fixed in step 1.1, so Ad⁡gY=Y.

3.1F2F3step 1.1step 2.1algebra

Write g=exp⁡GX. By [F2], (ead⁡X−I)Y=0. The power-series identity eA−I=D(A)A gives D(ad⁡X)[X,Y]=0; invertibility from step 1.1 yields [X,Y]=0.

4.1F1F2F3step 1.1step 2.1step 3.1∎

The group is nonempty. In dimensions zero and one the conclusion is automatic. Singular ad⁡X is allowed because only D(ad⁡X), close to I, is inverted. There is no interval, endpoint, metric, or biconditional. ACω is inherited exactly through [F1]–[F3]; finitely many neighborhood shrinkings add no choice.

Depends on

Used by

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Dependency tree · two levels

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Sources