Alphabeta Math
CounterexampleConstruction: AI-generatedVerification: AI-generatedPipeline-generated
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One observation does not determine a natural cubic smoothing fit

Statement refuted

The formula ∑i(yi−g(xi))2+λ∫ab∣D2g∣2 has a unique minimizing function for every nonempty data set whenever λ>0, including data with only one distinct input.

Facts & Assumptions

Given: The same squared-residual plus roughness criterion as the natural cubic smoothing spline, but with one distinct observed input.

[F1]

On data sets with at least two distinct inputs, the natural cubic smoothing criterion is ∑i(yi−g(xi))2+λ∫ab∣D2g∣2 (Natural cubic smoothing spline); the counterexample below evaluates this same formula on one input, outside that definition's domain.

[A1]

The extended criterion has one input x1=1/2, response y1=1, and λ>0.

Counterexample

Take the domain [0,1], one observation (x1,y1)=(1/2,1), and λ>0. Extend the displayed criterion formula to this data set. For every c∈R, set gc(x)=1+c(x−1/2). Then gc(1/2)=1 and D2gc=0.

Given: The one-point criterion J(g)=(1−g(1/2))2+λ∫01∣g′′(x)∣2dx.

1.1A1F1algebra

For every c, both terms in [F1] vanish at gc, so J(gc)=0. The criterion is a sum of nonnegative terms, hence zero is its minimum.

2.1A1step 1.1algebra∎

If c≠d, then gc(1)=1+c/2≠1+d/2=gd(1), so gc and gd are distinct minimizers. The one-observation extension is not unique, proving the lower bound of two distinct inputs is necessary.

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