Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedprecheck passaudited 2026-10-02
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p-regular and p-restricted labels differ

Statement refuted

The p-regular and p-restricted partitions of n coincide, so that the James labelling Dλ of the simple k[Sn]-modules by p-regular λ and the labelling D(μ) by p-restricted μ assign the same partition to each simple module, and a statement proved for one labelling applies verbatim to the other.

Facts & Assumptions

Given: The prime p=2 and the partitions (2) and (1,1) of n=2, with multiplicities zj(λ) of the positive parts and the conjugate partition λ′ (p-regular and p-restricted partitions, Partitions, English diagrams, and conjugation).

[F1]

A partition λ is p-regular when zj(λ)<p for every j≥1, and p-restricted when λi−λi+1<p for every i≥1, with the sequence padded by zeros; and λ is p-restricted if and only if λ′ is p-regular (p-regular and p-restricted partitions).

[F2]

The conjugate partition has parts λj′=#{i:λi≥j}; in particular the conjugate of a one-part partition is a column and conversely (Partitions, English diagrams, and conjugation).

[F3]

For a p-regular partition λ the James simple module Dλ and the dual-label simple module D(λ′) are related by Dλ≅D(λ′)⊗sgn⁡ (p-regular and p-restricted labels under transpose and sign).

[F4]

The sign representation is the one-dimensional representation on which σ acts by sgn⁡(σ)=±1; over a field of characteristic 2 one has −1=1, so the sign representation is the trivial representation (The sign representation of Sn and the restriction Res⁡HG(V) of a representation to a subgroup).

Counterexample

technique · direct
1.1givenF1algebra

For λ=(2) one has z2(λ)=1<2, so (2) is 2-regular; and λ1−λ2=2−0=2, which is not <2, so (2) is not 2-restricted. Thus (2) is 2-regular but not 2-restricted.

1.2givenF1algebra

For λ=(1,1) one has z1(λ)=2, which is not <2, so (1,1) is not 2-regular; and the padded differences are λ1−λ2=1−1=0<2 and λ2−λ3=1−0=1<2, so (1,1) is 2-restricted. Thus (1,1) is 2-restricted but not 2-regular.

2.1givenF1F2step 1.1step 1.2algebra

By [F2], (2)′=(1,1) and (1,1)′=(2): the diagram of (2) has two columns of height 1, and the diagram of (1,1) has one column of height 2. This is exactly the conjugation exchange of [F1] that matches the two partitions of steps 1.1 and 1.2.

3.1givenF1F3F4step 1.1step 1.2step 2.1∎

Steps 1.1 and 1.2 exhibit partitions of the same integer 2 that lie in exactly one of the two classes: (2) is 2-regular and not 2-restricted, while (1,1) is 2-restricted and not 2-regular. Hence the two families do not coincide, and labelling by one of them is not labelling by the other. Moreover the two labels describe the same simple module: by [F3] applied to the 2-regular partition (2), whose conjugate (1,1) is 2-restricted, D(2)≅D((1,1))⊗sgn⁡≅D((1,1)), the last step because the sign representation is trivial in characteristic 2 by [F4]. So a statement about the p-restricted label D(μ) cannot be applied to the James label Dλ without transposing the partition (and, in odd characteristic, inserting the sign twist); the change of partition is present already at p=2, where the sign twist itself is invisible.

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