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The objectwise cokernel presheaf can fail to be a sheaf

Statement refuted

For a morphism of sheaves of abelian groups, the objectwise cokernel presheaf is automatically a sheaf.

Facts & Assumptions

Given: The circle X=S1, the sheaf C of continuous real-valued functions, and the subsheaf Z‾ of locally constant integer-valued functions.

[F1]

Cokernel sheaves are obtained by sheafifying the objectwise cokernel presheaf (Kernel sheaves are objectwise, while cokernels and images are sheafified).

Counterexample

technique · direct
1.1givenconstruct

Let P be the presheaf cokernel of the inclusion Z‾↪C, so P(V)=C(V)/Z‾(V) for each open V⊆S1. Cover S1 by the arcs U0=S1∖{(−1,0)} and U1=S1∖{(1,0)}, and choose continuous angle functions θ0:U0→(−1/2,1/2) and θ1:U1→(0,1) with e2πiθi(z)=z. On U0∩U1, the difference θ1−θ0 is locally constant integer-valued, so the classes [θ0]∈P(U0) and [θ1]∈P(U1) agree on the overlap.

2.1step 1.1contradiction

If these local classes came from a global class [g]∈P(S1), then on each arc Ui the difference g−θi would be integer-valued and continuous, hence constant because Ui is connected. On the two connected components of U0∩U1, this would force the same constant difference to be both 0 and 1, which is impossible. Therefore the compatible local classes of step 1.1 do not glue in the presheaf P.

3.1F1step 2.1∎

So the objectwise cokernel presheaf is not a sheaf. By [F1], this is exactly why one sheafifies it to obtain the true cokernel sheaf. The statement is false.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources