Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The maximal function of 1[0,1] is not integrable

Statement refuted

Assume the Axiom of Countable Choice (The Axiom of Countable Choice (ACω)).

The centered maximal function of 1[0,1] belongs to L1(R).

Facts & Assumptions

Given: The Axiom of Countable Choice and the function f=1[0,1] on R.

[L1]

The centered maximal function is Mf(x)=supr>012rxrx+rf(y)dy. (The centered and uncentered Hardy-Littlewood maximal functions)

Counterexample

technique · direct
1.1

Let x1 and take the centered interval [0,2x], which has centre x [L1, given, algebra] and contains [0,1]. Then [L1] gives Mf(x)12x011dy=12x.

L1givenalgebra
2.1

Therefore [step 1.1, algebra] 1RMf(x)dx121Rdxx=12logR(R>1). Letting R shows 1Mf(x)dx=+. Hence MfL1(R).

step 1.1algebra
3.1

So the displayed claim is false.

step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources