Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-21
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Zero derivative need not give constancy on a disconnected open set

Statement refuted

If a differentiable real function has derivative zero at every point of an open domain, then it is constant on that domain.

The counterexample below establishes the true witness clause: The total derivative of f is zero at every point of U, but f is not constant on U.

Facts & Assumptions

Given: Let U=(−2,−1)∪(1,2) and define f:U→R to equal 1 on (−2,−1) and −1 on (1,2).

[L1]

The total derivative Df(a) is the linear map whose remainder in the first-order approximation is little-oh of the displacement (The total (Fréchet) derivative Df(a) as the linear first-order approximation with o(∥h∥2) remainder).

Counterexample

technique · direct
1.1L1given

Every point of U has a neighbourhood contained in exactly one component, and f is constant there. The zero linear map therefore leaves a zero remainder in [L1], so Df(a)=0 for every a∈U.

2.1step 1.1given∎

The values at −3/2 and 3/2 are respectively 1 and −1. Thus the total derivative of f is zero at every point of U, but f is not constant on U.

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources