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A locally principal subscheme need not be an effective Cartier divisor

Statement refuted

The claim refuted is: every closed subscheme that is locally cut out by principal ideals is an effective Cartier divisor. Let k be a field and let X=Spec⁡A with A=k[ϵ]/(ϵ2) be the dual-numbers scheme. The closed subscheme Z=V(ϵ) is cut out on the single affine chart X by the principal ideal (ϵ), but ϵ is a zero divisor, ϵ⋅ϵ=0 with ϵ≠0; every generator of (ϵ) is such a multiple, hence a zero divisor, so the ideal has no regular generator and Z is not an effective Cartier divisor.

Facts & Assumptions

Given: A field k, the ring A=k[ϵ]/(ϵ2) with ϵ2=0 and ϵ≠0, the affine scheme X=Spec⁡A, and the closed subscheme Z=V(ϵ) cut out by the principal ideal (ϵ)⊆A.

[F1]

X=Spec⁡A is the dual-numbers scheme of k (The affine scheme of dual numbers); its global sections are OX(X)=A, whose elements are the classes a+bϵ with a,b∈k and with ϵ2=0 and ϵ≠0.

[F2]

Closed subschemes of X=Spec⁡A are, up to unique isomorphism over X, exactly the morphisms Spec⁡(A/I)↪Spec⁡A for ideals I⊆A; in particular Z=V(ϵ) is the closed subscheme Spec⁡(A/(ϵ)) cut out by the principal ideal (ϵ) (Closed immersions into affine schemes are quotient spectra).

[F3]

A Cartier divisor on X is a section of the quotient sheaf KX×/OX× of Sheaf total quotient rings; an effective Cartier divisor admits a local-equation representation (Ui,fi) with fi∈OX(Ui) whose germs are regular sections, that is, multiplication by each germ (fi)x is injective on OX,x. In particular, on the affine chart X a local equation is an element f∈A such that multiplication by f on A is injective (Effective cartier divisor).

[F4]

Part 1 of Effective Cartier divisors are closed subschemes cut out by regular equations attaches to every effective Cartier divisor D on X a closed subscheme ZD whose ideal sheaf ID is the kernel of OX→(iD)∗OZD, and for every local-equation datum {(Ui,fi)} of D one has ID∣Ui=fiOUi. Part 2 states the converse: a closed subscheme locally cut out by nonzerodivisors is of the form ZD for an effective Cartier divisor D.

Counterexample

1.1F1

The ring A=k[ϵ]/(ϵ2) is local with maximal ideal (ϵ), and its units are exactly the elements a+bϵ with a≠0. Indeed A/(ϵ)≅k is a field, so (ϵ) is maximal; if a≠0 then (a+bϵ)(a−1−ba−2ϵ)=1+ba−1ϵ−ba−1ϵ=1, so a+bϵ is a unit; conversely an element bϵ of (ϵ) is not a unit because A/(ϵ)≅k kills it.

1.2F1

The element ϵ is a zero divisor of A: ϵ≠0 by hypothesis and ϵ⋅ϵ=ϵ2=0, so multiplication by ϵ on A sends the nonzero element ϵ to 0 and is not injective. The same computation gives aϵ⋅ϵ=0 for every a∈k.

2.1step 1.1step 1.2

The generators of the ideal (ϵ) are exactly the elements aϵ with a≠0: an element of (ϵ) is c+dϵ times ϵ, which equals cϵ because ϵ2=0; if a≠0 then ϵ=a−1(aϵ) lies in (aϵ), so (aϵ)=(ϵ), and conversely a generator f=(c+dϵ)ϵ=cϵ of (ϵ) satisfies ϵ∈(f)=(cϵ) only if c≠0. By step 1.2 every such generator is a zero divisor.

3.1F2F3F4step 2.1

The closed subscheme Z=V(ϵ) is not an effective Cartier divisor on X. Suppose it were, say Z=ZD for an effective Cartier divisor D. By [F4] the ideal sheaf ID equals the ideal sheaf of Z, which on the single chart X is (ϵ); since X has only one point, its only nonempty open is X, so an effective datum supplies an equation f∈A=OX(X); by [F4] we have ID∣X=fA, so f generates (ϵ). By step 2.1 the element f is a zero divisor, so multiplication by f on A is not injective and f is not a regular section; this contradicts the effectiveness requirement of [F3].

4.1step 1.1step 1.2step 2.1step 3.1∎

Therefore Z=V(ϵ) is locally principal, being cut out on its unique affine chart by the principal ideal (ϵ), yet it is not an effective Cartier divisor, because no generator of that ideal is a nonzerodivisor. This refutes the claim that local principality alone makes a closed subscheme an effective Cartier divisor.

The obstruction is the nilpotent structure of A: the vanishing scheme Z=Spec⁡k is a single reduced point, but the scheme X is non-reduced and the equation of the point is a zero divisor. On an integral scheme a nonzero regular function on a nonempty open has a nonzero germ in every local domain, so it is a nonzerodivisor (Effective cartier divisor). The example shows that the nonzerodivisor hypothesis cannot be dropped in the converse construction of an effective Cartier divisor from a locally principal closed subscheme (Effective Cartier divisors are closed subschemes cut out by regular equations). It does not test dropping effectiveness for an existing Cartier divisor: on this X every nonzerodivisor is a unit, so KX=OX and every Cartier divisor is zero.

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