Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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A group acting freely on a positive even sphere has at most two elements

Statement

If a group Γ acts freely by homeomorphisms on S2m with m1, then Γ2. If it is nontrivial, it is isomorphic to Z/2Z. The antipodal action realizes the nontrivial case.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For n1, any continuous fixed-point-free map f:SnSn has degree (1)n+1. Consequently, a self-map of any other degree has a fixed point. (A fixed point free sphere map has antipodal degree)

[F2]

For n1 and continuous sphere self-maps f,g, homotopic maps have the same degree and deg(gf)=deg(g)deg(f). Every homotopy equivalence SnSn has degree 1 or 1. (Degree is homotopy invariant and multiplicative under composition)

[F3]

On SnRn+1 for n1, the identity, a constant map, any single coordinate reflection, and the antipodal map have degrees 1, 0, 1, and (1)n+1 respectively. (Degree of identity constant reflection and antipodal sphere maps)

Proof

1.1

Let ag be the homeomorphism associated to gΓ. F2 makes d(g)=deg(ag) a homomorphism Γ{1,1}, since agh=agah and a homeomorphism is a homotopy equivalence.

F2
2.1

For every ge, freeness says ag has no fixed point. F1, in positive even dimension, gives d(g)=1. Thus kerd={e}, so d is injective and Γ2, including the trivial group. A nontrivial subgroup of {1,1} is the entire two-element group.

F1step 1.1algebra
3.1

The antipodal involution squares to the identity and has no fixed point on a unit sphere: x=x would imply x=0. Together with the identity it therefore gives a free two-element action, of nonidentity degree 1 by F3.

F3algebra

Depends on

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Sources