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How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Homology Axioms Degree and Classical Applications

1 · Prerequisites

2 · Summary

Ordinary homology is characterized on CW pairs by its axioms and a specified coefficient group. The comparison proceeds from oriented simplices to finite CW pairs, cellular complexes, and the skeletal telescope. Sphere degree then supplies local multiplicity formulas and classical applications: no retraction, Brouwer fixed points, tangent fields, and invariance of Euclidean dimension.

3 · Logical flowchart

4 · Definitions, theorems and proofs

DefinitionDefinition: AI-adaptedProof: Not applicablejudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Unreduced homology theory on cw pairs

Definition

A CW pair is (X,A) with A a CW subcomplex of X, as in Skeleta, CW subcomplexes, and relative CW complexes. Morphisms are all continuous maps of pairs, not just cellular maps. An ordinary unreduced homology theory assigns covariant functors hn from CW pairs to abelian groups, for every nZ, and natural homomorphisms :hn(X,A)hn1(A), where hn(X)=hn(X,), satisfying:

  • Homotopic maps of pairs induce equal homomorphisms.
  • The inclusion maps and form an exact sequence hn(A)hn(X)hn(X,A)hn1(A).
  • For CW subcomplexes U,V of X=UV, inclusion induces hn(U,UV)hn(X,V).
  • For a point , hn()=0 when n0; write G=h0().
  • For every set-indexed family of CW pairs, including the empty family, the inclusions induce αhn(Xα,Aα)hn(αXα,αAα).

Thus hn()=0. No finite-dimensionality or finite-cell restriction is implicit.

TheoremStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Singular homology satisfies homotopy exactness and excision

Statement

For every fixed abelian group G, singular homology Hn(,;G), extended by zero in negative degrees, satisfies homotopy invariance, pair exactness, naturality of the connecting maps, and CW excision in Unreduced homology theory on cw pairs.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

A CW pair is (X,A) with A a CW subcomplex of X, as in def-skeleta-cw-subcomplex-and-relative-cw-complex. Morphisms are all continuous maps of pairs, not just cellular maps. An ordinary unreduced homology theory assigns covariant functors hn from CW pairs to abelian groups, for every nZ, and natural homomorphisms :hn(X,A)hn1(A), where hn(X)=hn(X,), satisfying: - Homotopic maps of pairs induce equal homomorphisms. - The inclusion maps and form an exact sequence hn(A)hn(X)hn(X,A)hn1(A). - For CW subcomplexes U,V of X=UV, inclusion induces hn(U,UV)hn(X,V). - For a point , hn()=0 when n0; write G=h0(). - For every set-indexed family of CW pairs, including the empty family, the inclusions induce αhn(Xα,Aα)hn(αXα,αAα). Thus hn()=0. No finite-dimensionality or finite-cell restriction is implicit. (Unreduced homology theory on cw pairs)

[F2]

If f,g:XY are homotopic continuous maps, then for every n0 and every abelian group G the induced homomorphisms on singular homology agree: Hn(f#)=Hn(g#):Hnsing(X;G)Hnsing(Y;G). (Homotopic maps induce the same map on singular homology)

[F3]

For AX there is an exact sequence Hn(A;G)Hn(X;G)Hn(X,A;G)δHn1(A;G)Hn1(X;G). (Long exact sequence of a pair)

[F4]

A map of pairs f:(X,A)(Y,B) induces a commuting morphism from the long exact sequence of (X,A) to that of (Y,B), including the connecting maps. (Naturality of the pair long exact sequence)

[F5]

If ZX and ZintX(A), then inclusion (XZ,AZ)(X,A) induces isomorphisms Hn(XZ,AZ;G)Hn(X,A;G) for every n. (Excision for singular homology)

[F6]

If (X,A) is a relative CW complex, then AX has the homotopy extension property; in particular it is a cofibration. (Relative CW inclusions are cofibrations)

Proof

1.1

The singular pair sequence is exact and its connecting maps commute with every map of pairs, by F3 and F4. These assertions hold for arbitrary subspaces and hence for CW pairs.

F3F4
1.2

For a homotopy of pairs, the prism chain homotopy on C(X;G) preserves C(A;G): every prism simplex over a simplex in A stays in the target subspace. It therefore descends to relative chain quotients. The identity f#g#=P+P gives relative homotopy invariance, with the same absolute conclusion as F2. Negative degrees are zero.

F2given
1.3

Put W=UV and form D=UW(W×[0,1])WV, attaching W×{0} to U and W×{1} to V. Its collapse c:DUV is a homotopy equivalence relative to V. Here is the cofibration argument: write D=(UWW×[0,1])WV. The mapping cylinder of the inclusion WU retracts onto U, and the HEP for (U,W) extends the path of W from the zero end to the one end to a map U×[0,1]UWW×[0,1]. The resulting end map fixes the attaching copy of W at the one end. The cylinder collapse and this end map are inverse up to homotopies fixed on that attaching copy, by contracting the traversed interval followed by its reverse. The HEP for the cylinder pair extends this contraction. Gluing V by its identity gives the claimed relative equivalence. This uses F6 for the two CW inclusions.

F6
2.1

In D set O=U(W×[0,2/3)) and N=V(W×(1/3,1]). They are open and cover D. The closure of DO is contained in N. Excision therefore identifies Hn(O,ON;G) with Hn(D,N;G). Retraction of N to V and the pair exact sequence identify the latter with Hn(D,V;G). The collapse OU restricts on ON=W×(1/3,2/3) to projection onto W. Both absolute maps are homotopy equivalences, so their commuting pair exact sequences give an isomorphism Hn(O,ON;G)Hn(U,W;G) by the exact-sequence injectivity and surjectivity chase. No inverse map of these pairs is needed. All maps commute with collapse to (UV,V), so the resulting isomorphism is the homomorphism of the original inclusion.

F5F3F4step 1.2step 1.3
3.1

These are exactly the four structural requirements in F1. If either subcomplex or their intersection is empty the cylinder construction has the corresponding empty pieces; excision and the relative chain quotients still give the same conclusion.

F1step 1.1step 1.2step 2.1
TheoremStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Singular homology satisfies dimension and arbitrary additivity

Statement

For any abelian group G, H0(;G)G and Hn(;G)=0 for every integer n0. For every set-indexed family of pairs the canonical map αHn(Xα,Aα;G)Hn(αXα,αAα;G) is an isomorphism. Together with the structural axioms, singular homology is an ordinary theory with coefficient group G.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

A CW pair is (X,A) with A a CW subcomplex of X, as in def-skeleta-cw-subcomplex-and-relative-cw-complex. Morphisms are all continuous maps of pairs, not just cellular maps. An ordinary unreduced homology theory assigns covariant functors hn from CW pairs to abelian groups, for every nZ, and natural homomorphisms :hn(X,A)hn1(A), where hn(X)=hn(X,), satisfying: - Homotopic maps of pairs induce equal homomorphisms. - The inclusion maps and form an exact sequence hn(A)hn(X)hn(X,A)hn1(A). - For CW subcomplexes U,V of X=UV, inclusion induces hn(U,UV)hn(X,V). - For a point , hn()=0 when n0; write G=h0(). - For every set-indexed family of CW pairs, including the empty family, the inclusions induce αhn(Xα,Aα)hn(αXα,αAα). Thus hn()=0. No finite-dimensionality or finite-cell restriction is implicit. (Unreduced homology theory on cw pairs)

[F2]

For every fixed abelian group G, singular homology Hn(,;G), extended by zero in negative degrees, satisfies homotopy invariance, pair exactness, naturality of the connecting maps, and CW excision in def-unreduced-homology-theory-on-cw-pairs. (Singular homology satisfies homotopy exactness and excision)

[F3]

For a topological space X and an abelian group G, the singular chain groups and boundary maps of def-singular-boundary-operator form the singular chain complex C(X;G):=(Cn(X;G)nCn1(X;G)), because thm-the-singular-boundary-squares-to-zero gives n1n=0. Its degree-n cycles and boundaries are Znsing(X;G):=kern,Bnsing(X;G):=imn+1, in the sense of def-cycle-and-boundary-subobjects-of-a-complex. The nth singular homology group is the homology object of this chain complex: Hnsing(X;G):=Znsing(X;G)/Bnsing(X;G), equivalently Hn(C(X;G)) in the notation of def-homology-object-of-a-chain-complex. When the coefficient group is Z, write simply Cn(X) and Hn(X) when no confusion can arise. (The singular chain complex and singular homology)

[F4]

Let X=αAXα be a disjoint union of topological spaces, and let G be an abelian group. Then for every n0, Hnsing(X;G)αAHnsing(Xα;G). (The singular homology of a disjoint union is the direct sum)

Proof

1.1

In the point complex there is one singular simplex in every nonnegative degree. The boundary on its copy of G is multiplication by j=0n(1)j: it is the identity for positive even n and zero for odd n; 0=0. Thus its homology is G in degree zero and zero in every other degree, also when G=0.

F3algebra
1.2

A singular simplex has connected domain and hence its image lies in a single summand of a disjoint union. The chain complex of a union is consequently the direct sum of the chain complexes; this is the chain mechanism underlying F4. Taking the quotient by the corresponding subspace chains gives the direct sum of the relative chain complexes.

F4F3
2.1

A finite-support tuple is a cycle exactly when every coordinate is a cycle. It is a boundary exactly when every coordinate is a boundary: choose a bounding chain in each of its finitely many nonzero coordinates. Thus homology commutes with this direct sum. This includes the empty family, whose chain complex is zero, and a singleton family. With F2 this verifies all axioms of F1.

F1F2step 1.1step 1.2
DefinitionDefinition: AI-adaptedProof: Not applicablejudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Reduced homology theory and augmentation

Definition

For an unreduced theory h and a nonempty based CW space (X,x0) with x0 a vertex, set h~n(X)=ker(hn(X)phn()). The basepoint inclusion s satisfies ps=id and splits this augmentation. The underlying ordinary theory is as in Unreduced homology theory on cw pairs.

Independently, a reduced ordinary theory on based CW spaces consists of homotopy-invariant covariant functors h~n, natural suspension isomorphisms σ:h~n(X)h~n+1(ΣX), exact cofiber sequences, and arbitrary wedge additivity. More explicitly, for every based CW inclusion AX, h~n(A)h~n(X)h~n(X/A) is exact; the boundary in the extended sequence is the cofiber map to ΣA followed by σ1. The suspension here is reduced suspension. The dimension axiom is h~n(S0)=0 for n0, with h~0(S0)=G. Wedge additivity includes the empty wedge and gives h~n()=0.

The empty space is not a based object. If its reduced groups are mentioned, this library uses H~n(;G)=0 in all degrees, as in Augmentation at 0-simplices and reduced singular homology. The augmented-chain convention H~1(;G)=G is a different extension and is not used here.

PropositionStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Unreduced pair and reduced quotient axioms are equivalent on cw pairs

Statement

Ordinary unreduced theories on CW pairs and reduced ordinary theories on based CW spaces with vertex basepoints determine one another, naturally and compatibly with morphisms and coefficients. For A the correspondence gives hn(X,A)h~n(X/A); for A= it gives hn(X)h~n(X+), where X+=X{}.

Under this correspondence, pair boundaries are cofiber boundaries followed by inverse suspension, and arbitrary disjoint-sum additivity corresponds to arbitrary wedge additivity. For a CW triple BAX there is a natural exact sequence hn(A,B)hn(X,B)hn(X,A)hn1(A,B), whose last map is the pair boundary followed by hn1(A)hn1(A,B).

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

A CW pair is (X,A) with A a CW subcomplex of X, as in def-skeleta-cw-subcomplex-and-relative-cw-complex. Morphisms are all continuous maps of pairs, not just cellular maps. An ordinary unreduced homology theory assigns covariant functors hn from CW pairs to abelian groups, for every nZ, and natural homomorphisms :hn(X,A)hn1(A), where hn(X)=hn(X,), satisfying: - Homotopic maps of pairs induce equal homomorphisms. - The inclusion maps and form an exact sequence hn(A)hn(X)hn(X,A)hn1(A). - For CW subcomplexes U,V of X=UV, inclusion induces hn(U,UV)hn(X,V). - For a point , hn()=0 when n0; write G=h0(). - For every set-indexed family of CW pairs, including the empty family, the inclusions induce αhn(Xα,Aα)hn(αXα,αAα). Thus hn()=0. No finite-dimensionality or finite-cell restriction is implicit. (Unreduced homology theory on cw pairs)

[F2]

For an unreduced theory h and a nonempty based CW space (X,x0) with x0 a vertex, set h~n(X)=ker(hn(X)phn()). The basepoint inclusion s satisfies ps=id and splits this augmentation. The underlying ordinary theory is as in def-unreduced-homology-theory-on-cw-pairs. Independently, a reduced ordinary theory on based CW spaces consists of homotopy-invariant covariant functors h~n, natural suspension isomorphisms σ:h~n(X)h~n+1(ΣX), exact cofiber sequences, and arbitrary wedge additivity. More explicitly, for every based CW inclusion AX, h~n(A)h~n(X)h~n(X/A) is exact; the boundary in the extended sequence is the cofiber map to ΣA followed by σ1. The suspension here is reduced suspension. The dimension axiom is h~n(S0)=0 for n0, with h~0(S0)=G. Wedge additivity includes the empty wedge and gives h~n()=0. The empty space is not a based object. If its reduced groups are mentioned, this library uses H~n(;G)=0 in all degrees, as in def-zero-simplex-augmentation-and-reduced-singular-homology. The augmented-chain convention H~1(;G)=G is a different extension and is not used here. (Reduced homology theory and augmentation)

[F3]

If (X,A) is a relative CW complex, then AX has the homotopy extension property; in particular it is a cofibration. (Relative CW inclusions are cofibrations)

Proof

1.1

Start with F1. The splitting ps=1 identifies hn(X,) with kerp by the exact sequence of (X,): s is injective in every degree, so its cokernel is hn(X,), and the splitting identifies that cokernel with the kernel. This is natural for based maps and is the reduced group of F2.

F1F2
2.1

For a CW inclusion i:AX with A, form the unreduced cone attachment Ci=XACA. CW excision gives hn(X,A)hn(Ci,CA). Since CA contracts to its apex, pair exactness identifies the latter with h~n(Ci). Collapse CA to the apex. This gives a homotopy equivalence CiX/A: extend the contraction of CA over Ci using F3; the terminal extension factors through the quotient, and its quotient homotopy and original homotopy exhibit the two inverse composites. Thus hn(X,A)h~n(X/A). For empty A, add a disjoint basepoint first, obtaining hn(X)hn(X+,). This also sends the empty pair to zero.

F1F3step 1.1
3.1

The reduced cone sequence and contractibility of the reduced cone give h~n+1(ΣY)h~n(Y); take its inverse as the suspension map. To recover the unreduced boundary for nonempty A, view Ci as the based cofiber of A+X+, with the cone apex as basepoint. Collapse X together with that apex to obtain CiΣA+; both cone ends are now identified, as required for reduced suspension of A+. Naturality of the pair sequences for (Ci,X{apex}) and the cone pair shows that the original connecting homomorphism is this induced cofiber map followed by inverse suspension into h~n1(A+)hn1(A). Thus the cofiber exact sequence is exactly the pair sequence, with its signs fixed by this convention. Dimension on S0 follows from the split two-point augmentation.

F1step 1.1step 2.1
4.1

Conversely, from F2 define hn(X,A)=h~n(X+/A+) and hn(X)=h~n(X+). When A is nonempty the quotient is X/A; when A is empty it is X+. Replacing the inclusion A+X+ by its mapping cylinder, its cofiber is homotopy equivalent to this quotient by the contraction argument above. Repeating the cone construction gives the sequence A+X+CiΣA+ΣX+. Each successive pair of maps is, up to homotopy, a CW inclusion and its quotient: after attaching the next cone, the previously attached contractible cone collapses by F3. The reduced exactness axiom and suspension therefore give the pair LES in every integer degree, with boundary as just specified. All these constructions respect maps, so the boundary is natural.

F2F3step 2.1step 3.1
5.1

For X=UV, the map U+/(UV)+X+/V+ is a homeomorphism of based CW spaces, so reduced homotopy invariance yields CW excision. A quotient of a disjoint union of pairs is the wedge of their based quotients, with the CW weak topology; reduced wedge additivity hence gives unreduced disjoint-sum additivity. In the other direction, apply unreduced additivity to (Xα,{xα}) and the quotient formula to obtain wedge additivity. The empty wedge is a point and both empty sums are zero. The formulas also give h0()=h~0(S0)=G and the dimension vanishing.

F1F2step 2.1step 4.1
6.1

The two recipes are inverse through the natural quotient and splitting isomorphisms above. A morphism commuting with pair boundaries commutes with the cone suspension isomorphisms, and conversely a reduced morphism commuting with suspension commutes with the reconstructed boundaries. Finally, apply the reduced cofiber sequence to A+/B+X+/B+, whose quotient is X+/A+. This gives the triple sequence. The cone map factors the usual pair boundary followed by the quotient of A, by naturality of the cone construction. This proves its stated formula as well as exactness, including A=B, B=, and A=X.

step 2.1step 3.1step 4.1step 5.1
DefinitionDefinition: AI-adaptedProof: Not applicablejudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Coefficient normalized morphism of ordinary homology theories

Definition

For ordinary theories h,k as in Unreduced homology theory on cw pairs, a morphism η:hk consists of homomorphisms ηn(X,A):hn(X,A)kn(X,A), natural for all maps of CW pairs and all nZ, satisfying kηn=ηn1h.

For a specified homomorphism u:h0()k0(), the morphism is coefficient-normalized by u if η0()=u. A comparison equivalence has every component invertible and is normalized by a specified coefficient isomorphism. Neither the existence nor uniqueness of such an extension is part of this definition.

LemmaStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Any ordinary homology theory computes relative cell groups from its coefficient group

Statement

Let h be an ordinary theory with coefficient group G=h0(). For every n0 and kZ, hk(Dn,Sn1){Gk=n,0kn. At n=0 the pair means (,). Also h~k(Sn)G for k=n and zero otherwise, including n=0. Choose the disk identifications by ordered orientations and iterated cone boundaries, so they commute with these boundaries.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

Ordinary unreduced theories on CW pairs and reduced ordinary theories on based CW spaces with vertex basepoints determine one another, naturally and compatibly with morphisms and coefficients. For A the correspondence gives hn(X,A)h~n(X/A); for A= it gives hn(X)h~n(X+), where X+=X{}. Under this correspondence, pair boundaries are cofiber boundaries followed by inverse suspension, and arbitrary disjoint-sum additivity corresponds to arbitrary wedge additivity. For a CW triple BAX there is a natural exact sequence hn(A,B)hn(X,B)hn(X,A)hn1(A,B), whose last map is the pair boundary followed by hn1(A)hn1(A,B). (Unreduced pair and reduced quotient axioms are equivalent on cw pairs)

Proof

1.1

The dimension axiom gives the assertion for (,). On S0={,+} the split augmentation is addition hk()hk()hk(), with kernel g(g,g). Thus the reduced sphere assertion starts in degree zero, with the displayed difference orientation.

F1algebra
2.1

For a nonempty sphere, the contractible cone has zero reduced groups. Its exact sequence identifies the relative cone group in degree k with h~k1 of its base, including degree one where this is a reduced zero-degree group. The quotient is the suspension sphere. Iterating F1's natural suspension gives h~k(Sn)hkn().

F1step 1.1
3.1

For n1, apply the same cone boundary to (Dn,Sn1). The dimension axiom makes hkn() vanish unless k=n, including all negative k. Fix orientations by these boundary identifications starting with (g,g) on S0. They remain valid for G=0.

F1step 1.1step 2.1
LemmaStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Any ordinary homology theory has a cellular chain complex on a cw pair

Statement

For a CW pair (X,A) and an ordinary theory h with coefficient G, put F1=A and Fr=AXr for r0. Set Crh(X,A)=hr(Fr,Fr1)(r0),Crh=0(r<0). Each Crh is the direct sum of copies of G indexed by the relative r-cells. Define d0=0 and for r1 let dr be the triple boundary to hr1(Fr1,A) followed by its map to hr1(Fr1,Fr2). Then dr1dr=0, naturally for cellular maps of CW pairs.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

Let h be an ordinary theory with coefficient group G=h0(). For every n0 and kZ, hk(Dn,Sn1){Gk=n,0kn. At n=0 the pair means (,). Also h~k(Sn)G for k=n and zero otherwise, including n=0. Choose the disk identifications by ordered orientations and iterated cone boundaries, so they commute with these boundaries. (Any ordinary homology theory computes relative cell groups from its coefficient group)

[F2]

Ordinary unreduced theories on CW pairs and reduced ordinary theories on based CW spaces with vertex basepoints determine one another, naturally and compatibly with morphisms and coefficients. For A the correspondence gives hn(X,A)h~n(X/A); for A= it gives hn(X)h~n(X+), where X+=X{}. Under this correspondence, pair boundaries are cofiber boundaries followed by inverse suspension, and arbitrary disjoint-sum additivity corresponds to arbitrary wedge additivity. For a CW triple BAX there is a natural exact sequence hn(A,B)hn(X,B)hn(X,A)hn1(A,B), whose last map is the pair boundary followed by hn1(A)hn1(A,B). (Unreduced pair and reduced quotient axioms are equivalent on cw pairs)

[F3]

Write Xn for the union of cells of dimension at most n, with X1=. A CW subcomplex AX is a union of open cells such that, whenever A contains an open cell e, it contains the whole closure e. A relative CW complex (X,A) is formed from the subcomplex A by attaching cells in stages; thus AX is a cellular inclusion. (Skeleta, CW subcomplexes, and relative CW complexes)

Proof

1.1

By the skeletal definition F3, collapsing Fr1 leaves a wedge of one r-sphere per relative cell, using the disjoint-basepoint convention when Fr1 is empty. Quotient identification and arbitrary wedge additivity in F2, followed by F1, show hk(Fr,Fr1) is zero for kr and the stated direct sum for k=r. This includes no cells and zero-dimensional cells.

F1F2F3
1.2

Write δr:hr(Fr,Fr1)hr1(Fr1,A) for the triple boundary and ρr:hr(Fr,A)hr(Fr,Fr1) for the quotient map. The differential is dr=ρr1δr. Exactness of the triple (Fr1,Fr2,A) gives δr1ρr1=0.

F2
2.1

Consequently dr1dr=ρr2(δr1ρr1)δr=0 for r2; for r=1 it holds because d0=0. A cellular map preserves each Fr and all natural triple maps, so it commutes with these differentials. No sphere-map incidence identification has been used.

F2step 1.2algebra
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Finite dimensional skeletal exactness computes axiomatic homology

Statement

For every finite-dimensional CW pair (X,A) and ordinary theory h, there is a canonical isomorphism hn(X,A)Hn(Ch(X,A)) for every integer n, natural for cellular maps. It is the skeletal lift isomorphism described below and commutes with the homology connecting maps of pairs. The number of cells need not be finite.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For a CW pair (X,A) and an ordinary theory h with coefficient G, put F1=A and Fr=AXr for r0. Set Crh(X,A)=hr(Fr,Fr1)(r0),Crh=0(r<0). Each Crh is the direct sum of copies of G indexed by the relative r-cells. Define d0=0 and for r1 let dr be the triple boundary to hr1(Fr1,A) followed by its map to hr1(Fr1,Fr2). Then dr1dr=0, naturally for cellular maps of CW pairs. (Any ordinary homology theory has a cellular chain complex on a cw pair)

Proof

1.1

Use the filtration and notation of F1. Write Eqr=hq(Fr,A). The triple sequence and concentration of hq(Fr,Fr1) in degree r give Eqr=0 for q<0 or q>r, inductively from Eq1=0. They also give Eqr1Eqr an isomorphism for q<r1, and a surjection for q=r1. Since the filtration terminates, Enn+1hn(X,A), taking Fr=X above the top dimension.

F1
2.1

For n0, ρn:EnnCnh is injective since Enn1=0. Likewise ρn1:En1n1Cn1h is injective when n1. Exactness then yields ρn(Enn)=kerdn; for n=0 this says E00=C0h since E1=0.

F1step 1.1
3.1

The surjection i:EnnEnn+1 has kernel imδn+1. Since ρnδn+1=dn+1, define α(x)=[ρn(y)] for any lift i(y)=x. Two lifts differ by a δn+1 image, so the class is independent. Every cycle is ρn(y) by the preceding step, giving surjectivity. If ρn(y)=dn+1(z), injectivity of ρn implies y=δn+1(z) and hence x=0, proving injectivity.

F1step 2.1
4.1

Every map of the filtered exact diagrams carries a lift to a lift and commutes with ρ,δ,i, so it commutes with α. This proves cellular naturality and uniqueness of the isomorphism defined by the lift rule. For pair boundaries use the same construction on the cofiber sequence A+X+X+/A+ΣA+. Give each suspension cell the cone orientation. Its cellular chain group in degree n+1 is the reduced degree-n group of A+, and its boundary is the suspended boundary with the cone sign convention. The cofiber map sends a relative cellular cycle represented by a chain c of X to the suspended class of dcCn1h(A): the faces outside A cancel because c was a relative cycle. In the exact diagram this is exactly the triple connecting map. Desuspending therefore identifies the axiomatic pair boundary with the chain connecting map [c][dc]. The lift construction commutes with suspension because its ρ and δ maps do.

F1step 3.1
5.1

The direct-sum decomposition by relative cells splits 0Ch(A)Ch(X)Ch(X,A)0 degreewise, so the preceding chain-boundary formula is defined for arbitrary G, without a flatness assumption. Negative degrees are zero by the first step. Empty pairs and pairs with no relative cells give zero on both sides.

F1step 1.1step 4.1
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Oriented simplex comparison for an ordinary homology theory

Statement

For finite simplicial pairs (K,L) and any ordinary theory h with coefficient group G, ordered simplex classes identify Ch(K,L)Csimp(K,L;Z)G, with the alternating face differential. Consequently they give a coefficient-normalized isomorphism hn(K,L)Hn(K,L;G), natural for simplicial maps and compatible with pair boundaries. No flatness of G is assumed.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For every finite-dimensional CW pair (X,A) and ordinary theory h, there is a canonical isomorphism hn(X,A)Hn(Ch(X,A)) for every integer n, natural for cellular maps. It is the skeletal lift isomorphism described below and commutes with the homology connecting maps of pairs. The number of cells need not be finite. (Finite dimensional skeletal exactness computes axiomatic homology)

[F2]

For an abstract simplicial complex K and an integer n0, the simplicial chain group Cn(K) is the free abelian group generated by the oriented n-simplices of K, subject to the relation [vπ(0),,vπ(n)]=sgn(π)[v0,,vn] for every permutation π of the vertices of a simplex. For n<0, set Cn(K)=0. The boundary operator n:Cn(K)Cn1(K) is 0=0 in degree 0. For n1, it is defined on an oriented simplex by n[v0,,vn]=i=0n(1)i[v0,,vi^,,vn]. The well-definedness of this formula with respect to the chosen oriented representative is recorded in lem-simplicial-boundary-is-independent-of-oriented-representative through justified_by. (Simplicial chain groups and the boundary operator)

[F3]

If πSn+1 is odd, then [vπ(0),,vπ(n)]=[v0,,vn] as oriented simplices. (An odd permutation reverses the sign of an oriented simplex)

[F4]

For every simplicial complex K, the natural simplicial-to-singular chain map induces Hnsimp(K;G)Hn(K;G) for all n. (Simplicial and singular homology agree)

Proof

1.1

A vertex has its prescribed coefficient map Gh0(). Inductively orient an ordered simplex σ=[v0,,vr] by the relative class whose boundary is the alternating oriented boundary of σ. To justify the induction without assuming integer action, let T be the union of all its faces except the face opposite v0. It is a cone on the boundary of that opposite face and contracts. The exact sequence of (σ,T) identifies h~r1(σ) with hr1(σ,T), which by excision is the relative group of that opposite face. This specifies uniquely the boundary class from the already oriented face and its coefficient g. The cone pair boundary then specifies uniquely the relative r-class. For r=1 this is (g,g) at the two endpoints.

F1given
2.1

The coefficient of the opposite face is g. At every common codimension-two face the boundary of this boundary is zero by the triple sequence; thus the two incident face coefficients must cancel with their inductively fixed signs. The adjacency graph of the faces of a simplex is connected, so this forces all coefficients to be (1)jg on the face omitting vj. For r=1 the augmentation-kernel calculation supplies the same cancellation. Thus the induced differential is exactly the alternating formula of F2.

F1F2step 1.1
3.1

Permuting the vertices sends the alternating boundary class to its permutation sign times the old class, by induction on faces; injectivity of the relative-simplex boundary fixes the same sign upstairs. Adjacent transpositions generate all permutations, matching the oriented relation F3. A simplicial map injective on the vertices of a simplex hence acts by this signed ordered-image map. If its image has lower dimension, it factors through that lower-dimensional simplex and its relative degree-r homology vanishes by F1. This proves simplicial naturality, including degenerate simplicial images.

F1F3step 1.1step 2.1
4.1

Summing over the simplices outside L yields the asserted chain isomorphism, with no tensoring of an exact sequence required: both sides are direct sums of copies of G and the differential is already the same signed matrix. Apply the skeletal homology computation F1. The simplicial-to-singular comparison F4 extends to a finite pair by the natural short exact sequences of simplicial and singular chains and the resulting pair exact sequences: the absolute isomorphisms for K,L give the relative isomorphism by the usual injectivity/surjectivity exact-sequence chase. This yields the desired comparison, commuting with boundaries and normalized on a vertex. Empty complexes, K=L, and dimension zero all give the same direct-sum formulas.

F1F4step 2.1step 3.1
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Finite simplicial approximation for homology comparison

Statement

For finite simplicial pairs (K,L) and (P,Q), every continuous map f:(K,L)(P,Q) is homotopic through maps of pairs to a simplicial map (sdrK,sdrL)(P,Q) for some r0.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

Let (V,K) and (W,L) be abstract simplicial complexes. A function f:VW is a simplicial map if f(σ):={f(v):vσ} is a simplex of L whenever σ is a simplex of K. The geometric realization of f is the map f:KL defined by f(α)(w):=vf1(w)α(v). Because α has finite support, the sum is finite. The support of f(α) is contained in f(supp(α)), so it is again a simplex of L. (A simplicial map and its geometric realization)

[F2]

For an affine n-simplex of finite diameter and n>0, every simplex in its r-fold barycentric subdivision has diameter at most (n/(n+1))r times the original diameter. Hence the mesh tends to zero. (Mesh tends to zero under iterated subdivision)

[F3]

Let (X,d) be a compact metric space (def-metric-compactness, def-metric-space) and let U be an open cover of X. Then there is a real δ>0, a Lebesgue number for U, such that every nonempty AX with diam(A)<δ (def-metric-bounded-diameter) satisfies AU for some UU. Diameters of nonempty subsets of X are defined because a compact space is bounded (thm-compact-subset-is-closed-and-bounded) and a subset of a bounded set is bounded. No choice principle is used. (Every open cover of a compact metric space has a Lebesgue number: a δ>0 such that every nonempty subset of diameter less than δ lies inside a single member of the cover)

Proof

1.1

Realize the finite complexes in their barycentric Euclidean spaces. The open star of a vertex w consists of points whose w coordinate is positive. If several open stars intersect, their vertices belong to the support simplex of any point in the intersection; hence they span a simplex. This is the star criterion for a vertex map to extend as in F1.

F1given
1.2

For every aL, some vertex w of Q has positive coordinate at f(a). The open set f1(stPw) therefore contains a metric ball B(a,2ϵa). Finitely many B(a,ϵa) cover the compact set L. Choose η>0 smaller than all their radii. Every set of diameter less than η containing a vertex vL lies in one of the corresponding B(a,2ϵa), since v lies in its inner ball. Thus any sufficiently small closed star at a vertex of L maps into the star of a vertex of Q. If L is empty this constraint is absent.

givenchoose
2.1

The preimages of all vertex stars in P cover the compact K. F3 gives a Lebesgue number λ>0. By F2 choose a common iterated subdivision whose simplex diameters are less than min(η,λ)/3, omitting η if L is empty. A closed vertex star has diameter at most twice the mesh. At vertices of the subdivided L make the constrained choice of the preceding step; elsewhere use λ. If K is zero-dimensional the stars are singletons and no subdivision is needed; if K is empty the assertion is vacuous.

F2F3step 1.2
3.1

Call the chosen vertex map g. For a point x in a source simplex with support vertices vj, f(x) belongs to every stPg(vj). The star criterion proves that these vertices lie in the support simplex of f(x). Thus g extends simplicially and H(x,t)=(1t)f(x)+tg(x) stays in that same target simplex. It is continuous in the ambient finite-dimensional vector space. If xL, its support simplex under f lies in Q, and so does the whole segment. Its endpoints are f and g, giving the required homotopy of pairs even if several chosen vertices coincide.

F1step 1.1step 2.1
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Subdivision compatible continuous polyhedral homology comparison

Statement

The ordered-simplex comparison for an ordinary homology theory on finite simplicial pairs is unchanged by finite subdivision. It is natural for every continuous map of finite simplicial pairs and commutes with pair connecting homomorphisms.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For finite simplicial pairs (K,L) and any ordinary theory h with coefficient group G, ordered simplex classes identify Ch(K,L)Csimp(K,L;Z)G, with the alternating face differential. Consequently they give a coefficient-normalized isomorphism hn(K,L)Hn(K,L;G), natural for simplicial maps and compatible with pair boundaries. No flatness of G is assumed. (Oriented simplex comparison for an ordinary homology theory)

[F2]

For finite simplicial pairs (K,L) and (P,Q), every continuous map f:(K,L)(P,Q) is homotopic through maps of pairs to a simplicial map (sdrK,sdrL)(P,Q) for some r0. (Finite simplicial approximation for homology comparison)

Proof

1.1

Let K be a finite subdivision of K, with L the induced subdivision of L. The identity realization map is cellular from the old filtration to the new one, since Kr(K)r. On an ordered old r-simplex, the sum of its new oriented r-simplices has all interior faces cancelled in pairs and has boundary the subdivided old boundary. Starting with vertices and using the boundary characterization in F1, it represents the old relative simplex class: the boundary map for the disk pair is injective, with reduced target for r=1. Thus the induced cellular map is the signed subdivision chain map, with coefficient g unchanged.

F1
2.1

The same argument applies to singular homology with G coefficients. Hence the comparison square for the identity between the two triangulations commutes on their relative cell groups and on the skeletal lift isomorphisms. It follows that the homology comparison agrees before and after subdivision. Two successive subdivisions are covered by repetition; two finite linear subdivisions have a common refinement, obtained by triangulating their finite convex intersection cells in increasing face dimension. Applying the same argument to that refinement gives independence of its choice.

F1step 1.1
3.1

For a continuous map of finite pairs choose a simplicial approximation after a common barycentric subdivision of the source, by F2. F1 gives naturality for that simplicial map, the preceding step identifies the subdivided comparison with the original one, and homotopy invariance replaces the approximation by the given map in both theories. Thus the comparison is natural for the actual continuous map and cannot depend on the approximation chosen.

F1F2step 2.1
4.1

The pair-boundary square already commutes for the ordered-simplex comparison in F1. Subdivision and its comparison are maps of pairs and preserve the cone orientation, so they preserve that square. Therefore the resulting continuous natural comparison commutes with pair boundaries as claimed. Empty pairs and zero-dimensional triangulations use the same vertex/direct-sum comparison.

F1step 2.1step 3.1
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Cw homotopy equivalence inclusions are strong deformation retracts

Statement

If AX is a CW subcomplex and its inclusion is a homotopy equivalence, then X strongly deformation retracts onto A. Moreover, if (Y,B) is a CW pair and u0,u1:BZ are homotopic, then the adjunction spaces Zu0Y and Zu1Y are homotopy equivalent relative to their common subspace Z.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

If (X,A) is a relative CW complex, then AX has the homotopy extension property; in particular it is a cofibration. (Relative CW inclusions are cofibrations)

Proof

1.1

First prove the relative inverse assertion: if f:(X,A)(Y,A) is a homotopy equivalence, equals the identity on A, and both inclusions have HEP, let g be an inverse and ht:gfidX. Extend htA over Y by HEP, starting at g, to obtain gt with g1A=id. CW inclusions have the needed HEP by F1.

F1given
2.1

Concatenate the homotopy g12tf for 0t1/2 with h2t1 for 1/2t1. It runs from g1f to the identity, and on A is a path followed by its reverse. Such a loop contracts relative to its endpoints: if its first-half path is γ, replace γ(min(2t,22t)) by γ((1u)min(2t,22t)). HEP for (X×I,A×I) extends this homotopy of homotopies. Following the left, top, and right sides of the parameter square now gives g1fidX relative to A. This product HEP follows by taking the product of the HEP retraction X×IX×{0}A×I with the other interval.

F1step 1.1
3.1

Repeat the preceding adjustment with g1 and f interchanged, obtaining f1 fixed on A with f1g1idY relative to A. Then f1f1g1ff relative to A, so fg1idY relative to A. Apply this result with the map AX: its relative inverse is a retraction, and the relative inverse homotopy is precisely a strong deformation retraction. If A is empty, the existence of an inverse forces X empty.

step 1.1step 2.1
4.1

For a homotopy U:B×IZ from u0 to u1, use the common space W=ZU(Y×I). The CW prism retraction of Y×I onto Y×{0}B×I fixes B×I and descends to a strong deformation retraction of W onto the first adjunction space, fixed on Z. The reversed prism gives the second retraction. These prism retractions can be built cellwise using radial projection of Dr×I onto its bottom and sides; concatenate over dimensions with the CW weak topology, as in the HEP construction. Composing the two inclusions and retractions gives inverse homotopy equivalences relative to Z.

F1algebra
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Finite cw pairs admit finite simplicial homotopy models

Statement

Every finite CW pair (X,A) is homotopy equivalent as a pair to a finite simplicial pair (K,L). In particular there are maps of pairs in both directions whose composites are homotopic to the identities through maps preserving the designated subspaces.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For finite simplicial pairs (K,L) and (P,Q), every continuous map f:(K,L)(P,Q) is homotopic through maps of pairs to a simplicial map (sdrK,sdrL)(P,Q) for some r0. (Finite simplicial approximation for homology comparison)

[F2]

If AX is a CW subcomplex and its inclusion is a homotopy equivalence, then X strongly deformation retracts onto A. Moreover, if (Y,B) is a CW pair and u0,u1:BZ are homotopic, then the adjunction spaces Zu0Y and Zu1Y are homotopy equivalent relative to their common subspace Z. (Cw homotopy equivalence inclusions are strong deformation retracts)

[F3]

Let (V,K) be an abstract simplicial complex. Its geometric realization K is the set of functions α:V[0,1] such that: 1. α(v)=0 for all but finitely many vV; 2. vVα(v)=1; 3. the support supp(α):={vV:α(v)0} is a simplex of K. For each simplex σ={v0,,vn} of K, write σ:={αK:supp(α)σ}. Sending α to the barycentric tuple (α(v0),,α(vn)) identifies σ with the geometric simplex spanned by the standard basis vectors indexed by v0,,vn, so σ carries its Euclidean simplex topology. We give K the weak topology with respect to these simplex inclusions: a subset UK is declared open exactly when Uσ is open in σ for every simplex σ of K. (The geometric realization of an abstract simplicial complex)

Proof

1.1

We first describe a finite simplicial replacement for the cylinder of a simplicial map f:PQ. Start with Q and an edge from each vertex v of P to f(v), using disjoint domain vertices. Having constructed the part over σ for a simplex σ with image face τ, adjoin the cone on M(fσ:στ) with a fresh apex. This contains the subdivided simplex as the cone on its subdivided boundary. The base already retracts to the contractible simplex τ, so both base and cone are contractible; the inclusion is a CW homotopy equivalence and F2 gives a strong deformation retraction to the base. Attach these finite pieces along their specified faces. Fresh vertices and the shared face construction make the intersections exactly subcomplexes in the sense of F3.

F2F3
2.1

Successively retract the cone pieces in decreasing dimension. The resulting retraction r:M(f)Q carries each domain simplex into its image face τ, so rP is homotopic there to f by straight lines. Extend that endpoint adjustment over M(f), fixed on Q, by the CW HEP used in F2. Thus the domain inclusion is homotopic in M(f) to f with the prescribed endpoint. Adjoin a cone on the subdivided copy of P; the result C(f) is a finite simplicial complex. This construction does not assume the ordinary mapping cylinder itself is simplicial.

F2step 1.1
3.1

Here is the induction with subpairs retained. Begin with the finitely many vertices of A, and adjoin its cells in increasing dimension. At each stage retain a common CW space Z having both the current CW space and its simplicial model Y as deformation retracts. Given finitely many new attaching maps Sr1Xold, retract to Y and approximate simplicially by F1 after finitely many subdivisions of the sphere domains. For r=0, just adjoin isolated vertices. For r1, adjoin the complexes M(f) to Z along Y. Each added subdivided sphere is homotopic in this common space to its original attaching map, by the old retraction homotopy, the simplicial approximation homotopy, and the cylinder homotopy just built.

F1F2step 2.1
4.1

For each of these homotopies glue Dr×I along its boundary cylinder. The bottom contains the original attached cell, and the top contains the cone on the new sphere; the top simplicial space is YC(f) over all the new cells. The prism retractions in F2 give deformation retractions to the two end adjunctions. The old retractions extend over an attaching disk by first extending the boundary homotopy over its collar; this is again the relative prism construction, fixed on the unaltered old end. Hence the new common space has both new ends as deformation retracts. This is a finite construction and preserves the earlier common subspace wherever no new cell is being attached.

F2step 3.1
5.1

After finishing A, keep its common space ZA and its two retracts A and L. Now repeat the same construction for the cells of XA in increasing dimension, with ZA designated as the subspace throughout. The homotopies on ZA are exactly its old retraction homotopies and remain within ZA; every prism newly attached for a cell outside A leaves this designated subspace alone. Thus the final common pair (Z,ZA) retracts as a pair to (X,A) and to a finite simplicial pair (K,L). Composing its retractions gives the required pair homotopy equivalence. Empty A uses ZA=, and empty X gives the empty simplicial pair.

F2step 4.1
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Coefficient comparison on finite cw pairs

Statement

For ordinary homology theories h,k and a specified isomorphism u:h0()k0(), there is a unique natural equivalence on finite CW pairs normalized by u and commuting with connecting homomorphisms.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

The ordered-simplex comparison for an ordinary homology theory on finite simplicial pairs is unchanged by finite subdivision. It is natural for every continuous map of finite simplicial pairs and commutes with pair connecting homomorphisms. (Subdivision compatible continuous polyhedral homology comparison)

[F2]

Every finite CW pair (X,A) is homotopy equivalent as a pair to a finite simplicial pair (K,L). In particular there are maps of pairs in both directions whose composites are homotopic to the identities through maps preserving the designated subspaces. (Finite cw pairs admit finite simplicial homotopy models)

[F3]

For ordinary theories h,k as in def-unreduced-homology-theory-on-cw-pairs, a morphism η:hk consists of homomorphisms ηn(X,A):hn(X,A)kn(X,A), natural for all maps of CW pairs and all nZ, satisfying kηn=ηn1h. For a specified homomorphism u:h0()k0(), the morphism is coefficient-normalized by u if η0()=u. A comparison equivalence has every component invertible and is normalized by a specified coefficient isomorphism. Neither the existence nor uniqueness of such an extension is part of this definition. (Coefficient normalized morphism of ordinary homology theories)

[F4]

For any abelian group G, H0(;G)G and Hn(;G)=0 for every integer n0. For every set-indexed family of pairs the canonical map αHn(Xα,Aα;G)Hn(αXα,αAα;G) is an isomorphism. Together with the structural axioms, singular homology is an ordinary theory with coefficient group G. (Singular homology satisfies dimension and arbitrary additivity)

[F5]

For finite simplicial pairs (K,L) and any ordinary theory h with coefficient group G, ordered simplex classes identify Ch(K,L)Csimp(K,L;Z)G, with the alternating face differential. Consequently they give a coefficient-normalized isomorphism hn(K,L)Hn(K,L;G), natural for simplicial maps and compatible with pair boundaries. No flatness of G is assumed. (Oriented simplex comparison for an ordinary homology theory)

Proof

1.1

Let G=h0(), G=k0(). Singular homology with either coefficient is an ordinary theory by F4. On a finite simplicial pair, F5 supplies coefficient-normalized isomorphisms from h and k to singular homology with G and G. By F1 these isomorphisms are natural for all continuous maps of finite simplicial pairs, not only simplicial maps, and commute with pair boundaries. The coefficient chain map 1u is invertible and commutes with the boundary because the latter uses integer coefficients. Composing these comparisons gives η normalized by u on finite simplicial pairs.

F1F3F4F5
2.1

For a finite CW pair choose a finite simplicial homotopy model a:P(X,A) with pair homotopy inverse b, by F2, and define ηX,A=k(a)ηPh(b). Homotopy invariance makes h(a),k(a) isomorphisms. If a:P(X,A) is another model, compare by the continuous pair map ba:PP. Naturality on polyhedra and the homotopy-inverse identities imply the two transported maps agree.

F1F2step 1.1
3.1

For a continuous map f:(X,A)(Y,B), insert the pair map bYfaX between the models in the preceding formula. Polyhedral naturality cancels the intervening homotopy-inverse composites and gives k(f)ηX,A=ηY,Bh(f). Pair-boundary compatibility follows in the same way by applying naturality of each pair sequence to a and b.

F1F3step 2.1
4.1

A normalized boundary-compatible morphism is forced on relative ordered simplices by their boundary isomorphisms and its prescribed value on vertices. It is then forced on direct sums of those cell groups by the inclusion maps, and on a finite simplicial pair by the skeletal lift rule: ρ(y) must map to the corresponding ρ of the image lift. Thus it coincides with the constructed comparison there. Transport along a model forces it on every finite CW pair. The empty pair gives only the zero map and a point gives exactly u.

F1F2F3step 1.1step 2.1
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Sphere endomorphisms act by the same integer in every ordinary theory

Statement

Let n0 and u:SnSn be continuous. If u on H~n(Sn;Z) is multiplication by d, then u on h~n(Sn)G for every ordinary theory h is didG. The identifications use the same oriented sphere generator; for n=0 use the difference of the two point classes.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For ordinary homology theories h,k and a specified isomorphism u:h0()k0(), there is a unique natural equivalence on finite CW pairs normalized by u and commuting with connecting homomorphisms. (Coefficient comparison on finite cw pairs)

[F2]

Let h be an ordinary theory with coefficient group G=h0(). For every n0 and kZ, hk(Dn,Sn1){Gk=n,0kn. At n=0 the pair means (,). Also h~k(Sn)G for k=n and zero otherwise, including n=0. Choose the disk identifications by ordered orientations and iterated cone boundaries, so they commute with these boundaries. (Any ordinary homology theory computes relative cell groups from its coefficient group)

[F3]

For n1, H~k(Sn;G) is G for k=n and 0 otherwise. For S0, H~0(S0;G)G and all other reduced groups vanish. Thus H0(Sn;G)G for n1, whereas H0(S0;G)GG. (Homology of spheres)

Proof

1.1

The sphere is a finite CW complex. F1, applied with the identity of G, identifies h naturally with singular homology with G on it; the point splitting identifies their reduced groups as well. F2 and F3 identify those groups with G in the stated dimension.

F1F2F3
2.1

For a triangulated oriented sphere the top integral cycle is the sum of its consistently oriented top simplices. The equation for a top cycle forces the coefficients of adjacent simplices to agree, so with any abelian G every reduced top cycle is this same fundamental cycle with a common coefficient g. There are no chains one degree higher in this triangulation. After simplicial approximation and subdivision, the integer matrix of the sphere map therefore sends that coefficient to dg, because its action on the integral fundamental cycle is d. This is the coefficient-chain comparison used in F1, and does not assert that tensor product preserves arbitrary exact sequences.

F1step 1.1
3.1

When n=0, the reduced generator is [+][]. The identity, transposition and two constant maps act on it by 1,1,0,0, respectively; the same computation on (g,g) gives g,g,0,0. This proves the assertion also for S0 and completes all cases, including G=0 and d=0.

F2F3algebra
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Axiomatic cellular boundaries are integral incidence matrices with coefficients

Statement

For a CW pair (X,A), an ordinary theory h with coefficient G, and chosen cell orientations, the complex Ch(X,A) is canonically Ccell(X,A;Z)G. Its differential is the integral incidence matrix acting on G. In degree one the entries are signed terminal-minus-initial endpoints. The direct-sum matrices have finite support in each column.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For a CW pair (X,A) and an ordinary theory h with coefficient G, put F1=A and Fr=AXr for r0. Set Crh(X,A)=hr(Fr,Fr1)(r0),Crh=0(r<0). Each Crh is the direct sum of copies of G indexed by the relative r-cells. Define d0=0 and for r1 let dr be the triple boundary to hr1(Fr1,A) followed by its map to hr1(Fr1,Fr2). Then dr1dr=0, naturally for cellular maps of CW pairs. (Any ordinary homology theory has a cellular chain complex on a cw pair)

[F2]

Let n0 and u:SnSn be continuous. If u on H~n(Sn;Z) is multiplication by d, then u on h~n(Sn)G for every ordinary theory h is didG. The identifications use the same oriented sphere generator; for n=0 use the difference of the two point classes. (Sphere endomorphisms act by the same integer in every ordinary theory)

[F3]

For n2 and oriented cells eαn and eβn1, collapse the complement of eβn1 in Xn1 and compose the attaching map of eαn with the resulting quotient to Sn1. Its induced endomorphism of oriented H~n1(Sn1;Z) is multiplication by a unique integer, denoted [eαn:eβn1]. For n=1, orient the characteristic interval of eα1 from 1 to +1 and, for a vertex v=eβ0, set [eα1:v]=1{χα(+1)=v}1{χα(1)=v}. Thus an oriented edge contributes its terminal vertex minus its initial vertex, and a loop with both endpoints at one vertex has incidence number zero there. (Incidence number of two CW cells)

[F4]

Let X be a CW complex. For n1, in the integral cellular chain groups with the chosen cell orientations, dneαn=β[eαn:eβn1]eβn1. (Cellular boundary is the incidence degree matrix)

Proof

1.1

By F1 the chain groups are direct sums of copies of G on relative cells. For a source r-cell and target (r1)-cell with r2, project the boundary homomorphism onto the target summand. Naturality of the characteristic disk pair identifies this component with the attaching map followed by collapse onto the target cell sphere and the natural disk boundary identifications. The corresponding integer for integral singular homology is precisely the incidence number of F3 and F4.

F1F3F4
2.1

F2 says that this same sphere endomorphism acts on coefficient G by that integer times the identity. For r=1, the boundary of the oriented interval is (g,g) at its two ends, so an edge contributes g at the terminal vertex and g at the initial vertex. If the endpoints coincide they cancel; endpoints in A vanish in the relative complex.

F2F3step 1.1
3.1

Each characteristic boundary has image in the finite union of closed cells supplied by closure finiteness, so only finitely many target cells can contribute to its column. Thus these components define a map of direct sums. At degree zero the outgoing differential is zero. The bases and component calculations identify the entire complex with the displayed tensor complex, for arbitrary G, including G=0 and pairs with no relative cells.

F1step 1.1step 2.1
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Finite dimensional axiomatic homology has finite subcomplex support

Statement

For a finite-dimensional CW pair (X,A) and ordinary h, the canonical map colimKX finite subcomplexhn(K,KA)hn(X,A) is an isomorphism for every integer n.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For every finite-dimensional CW pair (X,A) and ordinary theory h, there is a canonical isomorphism hn(X,A)Hn(Ch(X,A)) for every integer n, natural for cellular maps. It is the skeletal lift isomorphism described below and commutes with the homology connecting maps of pairs. The number of cells need not be finite. (Finite dimensional skeletal exactness computes axiomatic homology)

[F2]

For a CW pair (X,A), an ordinary theory h with coefficient G, and chosen cell orientations, the complex Ch(X,A) is canonically Ccell(X,A;Z)G. Its differential is the integral incidence matrix acting on G. In degree one the entries are signed terminal-minus-initial endpoints. The direct-sum matrices have finite support in each column. (Axiomatic cellular boundaries are integral incidence matrices with coefficients)

[F3]

If K is compact and f:KX is continuous into a CW complex, then f(K) lies in a finite CW subcomplex of X. (The image of a compact space lies in a finite CW subcomplex)

Proof

1.1

By F1 and F2, compute each of these groups using its oriented cellular direct-sum complex with coefficients G. Subcomplex inclusion preserves the basis cells and their incidence coefficients. The inclusion from a finite subcomplex therefore gives the actual inclusion of its relative cellular chains into those of (X,A).

F1F2
2.1

A cycle in the latter complex has finite support. Include the closures of its support cells in a finite CW subcomplex K: each closed cell is the compact image of a disk, and F3 places it in a finite subcomplex; a finite union of these remains finite. The cycle equation is unchanged in this subcomplex, so its homology class comes from K.

F3step 1.1
3.1

If a class from K maps to zero, its representing cycle bounds a finite-support cellular chain in X. Enlarge K to a finite subcomplex containing the closures of that chain's support cells. There the same boundary equation already witnesses zero. This is exactly injectivity of the colimit map. Finite unions show the indexing collection is directed, with the empty subcomplex included; zero complexes and negative degrees cause no exception.

F3step 1.1step 2.1
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

A comparison isomorphism propagates over one skeleton stage

Statement

Let η:hk be an existing morphism of ordinary theories, natural on CW pairs and commuting with connecting maps. For a CW skeleton stage Fr1Fr, if ηq(Fr1) and ηq(Fr,Fr1) are isomorphisms for every q, then ηq(Fr) is an isomorphism for every q.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For ordinary theories h,k as in def-unreduced-homology-theory-on-cw-pairs, a morphism η:hk consists of homomorphisms ηn(X,A):hn(X,A)kn(X,A), natural for all maps of CW pairs and all nZ, satisfying kηn=ηn1h. For a specified homomorphism u:h0()k0(), the morphism is coefficient-normalized by u if η0()=u. A comparison equivalence has every component invertible and is normalized by a specified coefficient isomorphism. Neither the existence nor uniqueness of such an extension is part of this definition. (Coefficient normalized morphism of ordinary homology theories)

[F2]

For a CW pair (X,A) and an ordinary theory h with coefficient G, put F1=A and Fr=AXr for r0. Set Crh(X,A)=hr(Fr,Fr1)(r0),Crh=0(r<0). Each Crh is the direct sum of copies of G indexed by the relative r-cells. Define d0=0 and for r1 let dr be the triple boundary to hr1(Fr1,A) followed by its map to hr1(Fr1,Fr2). Then dr1dr=0, naturally for cellular maps of CW pairs. (Any ordinary homology theory has a cellular chain complex on a cw pair)

[F3]

Let An1AnAn+1An+2An+3 and Bn1BnBn+1Bn+2Bn+3 be long exact sequences in an abelian category, together with a morphism of these sequences. If the four comparison maps at An1,An,An+2,An+3 are isomorphisms, then the comparison map An+1Bn+1 is an isomorphism. (Five lemma for a morphism of long exact sequences)

Proof

1.1

F1 means that η gives a commuting morphism of the pair long exact sequences. The skeletal pair of F2 has the five consecutive terms hq+1(Fr,Fr1)hq(Fr1)hq(Fr)hq(Fr,Fr1)hq1(Fr1), and the analogous row for k.

F1F2
2.1

The four comparison homomorphisms surrounding the middle term are isomorphisms by the stated hypotheses. Apply F3 to these five terms to conclude that the already specified middle homomorphism ηq(Fr) is an isomorphism. Since q was arbitrary this proves the result in all degrees, even at the empty bottom skeleton. This argument propagates invertibility; it does not construct η.

F3step 1.1given
TheoremStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Eilenberg steenrod uniqueness on finite dimensional cw pairs

Statement

For ordinary homology theories h,k and a specified isomorphism u:h0()k0(), there is a unique boundary-compatible natural equivalence on finite-dimensional CW pairs normalized by u. Infinitely many cells in bounded dimensions are allowed.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For ordinary homology theories h,k and a specified isomorphism u:h0()k0(), there is a unique natural equivalence on finite CW pairs normalized by u and commuting with connecting homomorphisms. (Coefficient comparison on finite cw pairs)

[F2]

For a finite-dimensional CW pair (X,A) and ordinary h, the canonical map colimKX finite subcomplexhn(K,KA)hn(X,A) is an isomorphism for every integer n. (Finite dimensional axiomatic homology has finite subcomplex support)

[F3]

Let η:hk be an existing morphism of ordinary theories, natural on CW pairs and commuting with connecting maps. For a CW skeleton stage Fr1Fr, if ηq(Fr1) and ηq(Fr,Fr1) are isomorphisms for every q, then ηq(Fr) is an isomorphism for every q. (A comparison isomorphism propagates over one skeleton stage)

Proof

1.1

F1 constructs the normalized comparison on every finite CW pair and makes it natural for inclusions of finite subcomplex pairs. By F2, take the colimit of these maps over all finite KX to define an isomorphism on a finite-dimensional pair (X,A). Its inverse is the colimit of the inverse comparisons.

F1F2
2.1

Every finite K is compact, so a continuous map f:(X,A)(Y,B) carries K into a finite subcomplex MY by compact-cell support as used in F2. The restricted map (K,KA)(M,MB) is a map of finite pairs. Naturality there, followed by the two colimit maps, gives naturality on the class represented in K. Every class has such a representative, proving naturality for all continuous maps.

F1F2step 1.1
3.1

The boundary of a class supported on K is supported on KA, and F1 makes the boundary square commute on that finite pair. Therefore it commutes on the colimit. Any other normalized natural morphism agrees on every finite pair by F1, and hence on every class by F2. At a point its component remains u. The one-stage five-lemma principle F3 also propagates invertibility of this already constructed morphism through each finite skeletal stage; it is not needed to invent the comparison maps.

F1F2F3step 1.1step 2.1
PropositionStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Ordinary homology theories have mayer vietoris for cw covers

Statement

Let X=UV be a cover by CW subcomplexes and W=UV. Every ordinary homology theory has a natural exact sequence hn(W)(i,j)hn(U)hn(V)a+bhn(X)Δhn1(W), where all four maps i,j,a,b are inclusions. The same sequence holds for a CW pair (X,C) covered by (U,CU) and (V,CV), with the corresponding relative groups.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

Ordinary unreduced theories on CW pairs and reduced ordinary theories on based CW spaces with vertex basepoints determine one another, naturally and compatibly with morphisms and coefficients. For A the correspondence gives hn(X,A)h~n(X/A); for A= it gives hn(X)h~n(X+), where X+=X{}. Under this correspondence, pair boundaries are cofiber boundaries followed by inverse suspension, and arbitrary disjoint-sum additivity corresponds to arbitrary wedge additivity. For a CW triple BAX there is a natural exact sequence hn(A,B)hn(X,B)hn(X,A)hn1(A,B), whose last map is the pair boundary followed by hn1(A)hn1(A,B). (Unreduced pair and reduced quotient axioms are equivalent on cw pairs)

Proof

1.1

Let qU:hn(U)hn(U,W) and qV:hn(X)hn(X,V) be the pair maps, and let e:hn(U,W)hn(X,V) be the excision isomorphism. F1 supplies these pair sequences and their naturality, including Ve=jU. Define Δ=Ue1qV. The three successive composites in the asserted sequence vanish by these identities and pair exactness.

F1
2.1

If Δx=0, write z=e1qVx. Then Uz=0, so z=qUu for some uhn(U). Thus qV(xau)=0, giving xau=bv for some vhn(V). This proves exactness at hn(X).

F1step 1.1
2.2

If au+bv=0, then eqUu=0, so u=iw. Now b(jw+v)=0, hence jw+v=Vt for some thn+1(X,V). Write t=ez. Then jw+v=jUz. Set w=wUz. Pair exactness gives iw=u and the displayed equation gives jw=v. This proves exactness at the direct sum.

F1step 1.1
2.3

If iw=jw=0, choose zhn+1(U,W) with Uz=w. Then Vez=jw=0, so ez=qVx for some xhn+1(X). Consequently Δx=w, proving exactness at hn(W). All the maps defining Δ are natural, including the inverse of the natural isomorphism e, so this is a natural sequence.

F1step 1.1
3.1

For a subcomplex C, work in the based quotient X+/C+ with its cover by the images of U+ and V+. These are the based quotients by (CU)+ and (CV)+; their intersection is W+/(CW)+. Use the reduced version of the same chase, or subtract the split basepoint sequence from the unreduced one. The quotient identification in F1 converts every term to the asserted relative term. Empty members, empty intersections, and C=X give the corresponding zero terms without changing the chase.

F1step 2.1step 2.2step 2.3
DefinitionDefinition: AI-adaptedProof: Not applicablejudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Skeletal mapping telescope of a cw pair

Definition

For a CW pair (X,A) let Xi be its i-skeleton and Ai=AXi, following Skeleta, CW subcomplexes, and relative CW complexes. Its skeletal mapping telescope is the CW pair TX=i0Xi×[i,),TA=i0Ai×[i,). Give [0,) vertices at the nonnegative integers and use the CW weak topology on these subcomplexes of X×[0,). Projection p(x,t)=x defines a continuous map (TX,TA)(X,A). The telescope of the empty space is empty.

LemmaStatement: AI-adaptedProof: AI-adaptedaudited 2026-09-07Open item page →

The skeletal telescope projects by a homotopy equivalence of pairs

Statement

For every CW pair (X,A), the skeletal telescope projection p:(TX,TA)(X,A) is a homotopy equivalence of pairs.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For a CW pair (X,A) let Xi be its i-skeleton and Ai=AXi, following def-skeleta-cw-subcomplex-and-relative-cw-complex. Its skeletal mapping telescope is the CW pair TX=i0Xi×[i,),TA=i0Ai×[i,). Give [0,) vertices at the nonnegative integers and use the CW weak topology on these subcomplexes of X×[0,). Projection p(x,t)=x defines a continuous map (TX,TA)(X,A). The telescope of the empty space is empty. (Skeletal mapping telescope of a cw pair)

[F2]

If (X,A) is a relative CW complex, then AX has the homotopy extension property; in particular it is a cofibration. (Relative CW inclusions are cofibrations)

Proof

1.1

In X×[0,) put Yi=TXX×[i,) and Bi=Xi×[i,i+1]X×{i+1}. Then Y0=X×[0,) and iYi=TX. We construct a slab strong deformation retraction onto Bi that preserves every skeleton and A. Extending such a retraction by the identity on the rest of Yi gives YiYi+1: its intersection with the rest is contained in Bi.

F1given
2.1

Here is the controlled prism construction underlying the CW homotopy extension property. Rescale the slab coordinate to u[0,1]. On Dn×[0,1] project radially from (0,1) onto En=Dn×[0,1]Dn×{1}. Explicitly put λ(x,u)=2/max(2x,u+1) and r(x,u)=(λx,1+λ(u+1)). We have 1λ2; the image lies on the side or top and r fixes En. The straight-line homotopy rs=(1s)id+sr stays in the convex prism and fixes En. For a fixed n>i, applying this to all n-cell prisms gives a strong deformation retraction of Xn×[i,i+1] onto Xn1×[i,i+1]Xn×{i+1}. It glues along characteristic boundaries because the entire lower skeleton is fixed during this particular collapse. It also preserves A: an n-cell of A and its attaching boundary both map into A.

F2step 1.1algebra
3.1

For the fixed slab index i, perform the dimension-n collapse during [2(ni),2(ni1)], for n>i, so higher dimensions collapse before lower ones. This specifies a homotopy on each Xd×[i,i+1]: start with the identity until time 2(di) when d>i, then perform the finitely many collapses n=d,d1,,i+1, always fixing the top; for di use the identity throughout. These homotopies agree on lower skeleta because a higher-dimensional collapse fixes its entire lower skeleton. Their endpoints lie in Bi and they fix Bi at every time. They preserve every skeleton and A, and assemble continuously: the restriction to every characteristic disk prism times the homotopy interval is a finite continuous concatenation. Products of a CW complex with the locally finite interval cell structures have their CW weak topology, so these restrictions test continuity, including at time zero. Thus this is the required single slab retraction.

F1step 2.1
4.1

Perform the retraction YiYi+1 during [12i,12(i+1)]. A point initially in Xd×[0,) stays in that skeleton and, by the end of stage d, lies in Yd+1(Xd×[0,))TX. It is fixed thereafter. On each closed cell prism the infinite concatenation is therefore eventually stationary uniformly in its points. Define the time-one value by that stationary value. On each characteristic disk prism times the time interval the homotopy is a finite concatenation followed by a constant homotopy; the same CW product weak topology proves continuity at time one as well.

step 1.1step 3.1
5.1

The whole homotopy fixes TX and preserves A×[0,), ending there in TA. It is a strong deformation retraction of pairs (X×[0,),A×[0,)) onto (TX,TA). The ambient projection is a pair homotopy equivalence, with section at height zero and homotopy (x,t,s)(x,(1s)t). Its composite with the telescope inclusion is the specified projection p, hence p is a pair homotopy equivalence. Empty X, empty A, A=X, and zero-dimensional complexes are included by the same construction.

step 4.1algebra
LemmaStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

A sequential abelian colimit is the cokernel of one minus shift

Statement

For any sequence of abelian groups G0u0G1u1, let D=i0Gi and let s:DD send the ith coordinate by ui into coordinate i+1. Then 0D1sDcolimiGi0 is exact, where the last map sums the canonical maps to the colimit. The maps ui need not be injective.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

Proof

1.1

If (1s)x=0, its coordinate zero is x0=0. Recursively its coordinate i is xiui1xi1=0, forcing xi=0 for every i. Thus 1s is injective, even if some or all transition maps vanish.

givenalgebra
2.1

The quotient D/im(1s) imposes the relations ιi(g)=ιi+1(uig). A homomorphism from this quotient to any abelian group B is exactly a family of homomorphisms vi:GiB satisfying vi+1ui=vi: define the map on a finite-support tuple by the finite sum ivi(xi). This proves the colimit universal property, so the quotient is the colimit and the last map is surjective with the stated kernel. Zero groups and a sequence supported at only one index are included.

step 1.1algebra
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Additivity and compact cell support control the infinite cw colimit

Statement

For every ordinary theory h with arbitrary additivity and every CW pair (X,A), the canonical map colimi0hn(Xi,Ai)hn(X,A) is an isomorphism. So is the canonical colimit over finite subcomplex pairs (K,KA) of X. The latter identification is natural for every continuous map of CW pairs.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

Let X=UV be a cover by CW subcomplexes and W=UV. Every ordinary homology theory has a natural exact sequence hn(W)(i,j)hn(U)hn(V)a+bhn(X)Δhn1(W), where all four maps i,j,a,b are inclusions. The same sequence holds for a CW pair (X,C) covered by (U,CU) and (V,CV), with the corresponding relative groups. (Ordinary homology theories have mayer vietoris for cw covers)

[F2]

For every CW pair (X,A), the skeletal telescope projection p:(TX,TA)(X,A) is a homotopy equivalence of pairs. (The skeletal telescope projects by a homotopy equivalence of pairs)

[F3]

For any sequence of abelian groups G0u0G1u1, let D=i0Gi and let s:DD send the ith coordinate by ui into coordinate i+1. Then 0D1sDcolimiGi0 is exact, where the last map sums the canonical maps to the colimit. The maps ui need not be injective. (A sequential abelian colimit is the cokernel of one minus shift)

[F4]

For a finite-dimensional CW pair (X,A) and ordinary h, the canonical map colimKX finite subcomplexhn(K,KA)hn(X,A) is an isomorphism for every integer n. (Finite dimensional axiomatic homology has finite subcomplex support)

Proof

1.1

Use the telescope from F2. Subdivide its height intervals at half-integers. Let B0=X0×[0,1], and for i1 let Bi=(Xi1×[i1/2,i])(Xi×[i,i+1]). Even Bi form a disjoint-union subcomplex U, and odd Bi form a disjoint-union subcomplex V; they cover the telescope. Their intersection is the disjoint union Ci=Xi×[i+1/2,i+1]. Each Bi retracts onto Xi at height i, and each Ci onto Xi, with all retractions preserving the corresponding pieces of TA.

F2given
2.1

Apply relative Mayer–Vietoris F1 and arbitrary additivity. After the retractions, the overlap map has from the ith summand the identity into stage i and the inclusion-induced map into stage i+1, with opposite signs. Multiplying each odd-indexed overlap summand by 1, and reordering the target even/odd direct sums by stage, identifies it with 1s on ihn(Xi,Ai). These changes of signs leave the outgoing sum map equal to the canonical stage-to-telescope map.

F1step 1.1
3.1

F3 says 1s is injective also in degree n1. Exactness therefore makes the map from the stage direct sum onto telescope homology surjective, with kernel im(1s). Its cokernel is the sequential colimit by F3. F2 identifies telescope homology with hn(X,A) by the actual projection. Its composite on every stage is the canonical inclusion, so the isomorphism obtained is the claimed canonical map.

F2F3step 2.1
4.1

Each skeletal pair is finite-dimensional, so F4 identifies its group with the colimit of the finite subcomplex pairs it contains. Every finite CW subcomplex of X lies in some skeleton, as its finitely many cells have bounded dimensions. Thus the iterated colimit is precisely the colimit over all finite subcomplex pairs, proving that assertion.

F4step 3.1
5.1

A continuous map takes a finite CW subcomplex into a finite subcomplex by compact-cell support, the same fact used in F4. Restrict the map to those finite pairs and use ordinary functoriality; their maps to the full pair commute. Since every class has finite support, this proves naturality for arbitrary maps, without assuming such maps preserve skeleta. Empty X and all zero groups give zero colimits, and all degrees, including negative ones, are covered by the same exact sequences.

F4step 4.1
TheoremStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Eilenberg steenrod uniqueness on all cw pairs

Statement

For any two ordinary homology theories h,k on all CW pairs and a specified coefficient isomorphism u:h0()k0(), there is a unique natural equivalence hk normalized by u and commuting with connecting homomorphisms. In particular, a theory with coefficient group G is naturally equivalent to singular homology with coefficients G, normalized by idG. Arbitrary additivity is part of the hypotheses.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For ordinary homology theories h,k and a specified isomorphism u:h0()k0(), there is a unique boundary-compatible natural equivalence on finite-dimensional CW pairs normalized by u. Infinitely many cells in bounded dimensions are allowed. (Eilenberg steenrod uniqueness on finite dimensional cw pairs)

[F2]

For every ordinary theory h with arbitrary additivity and every CW pair (X,A), the canonical map colimi0hn(Xi,Ai)hn(X,A) is an isomorphism. So is the canonical colimit over finite subcomplex pairs (K,KA) of X. The latter identification is natural for every continuous map of CW pairs. (Additivity and compact cell support control the infinite cw colimit)

[F3]

For any abelian group G, H0(;G)G and Hn(;G)=0 for every integer n0. For every set-indexed family of pairs the canonical map αHn(Xα,Aα;G)Hn(αXα,αAα;G) is an isomorphism. Together with the structural axioms, singular homology is an ordinary theory with coefficient group G. (Singular homology satisfies dimension and arbitrary additivity)

Proof

1.1

On each finite-dimensional pair F1 supplies the unique normalized equivalence. Its components on successive skeleta commute with inclusion by naturality. Taking their colimit and using F2 gives an isomorphism on every CW pair. Equivalently, compute it on finite subcomplex supports, where the same comparison is already prescribed by F1.

F1F2
2.1

For any continuous map of CW pairs, a finite support has a finite image support by F2. The comparison square commutes on these finite pairs by F1, and passing their classes to the full groups proves naturality for the original map. A boundary class has support in the intersection of its finite support with the subspace; the boundary square on that finite pair commutes by F1. Hence the extended maps commute with all pair boundaries.

F1F2step 1.1
3.1

Every other normalized natural morphism agrees on finite pairs by F1 and therefore on all classes by finite support in F2. The component at the point remains the prescribed u, including when both coefficient groups are zero. Singular homology with G is an ordinary theory by F3, so choosing it for k and choosing the identity coefficient map gives the final assertion. The infinite colimit step used arbitrary additivity through F2.

F1F2F3step 1.1step 2.1
DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Degree of a self map of an oriented sphere

Definition

Let n1. Choose a generator [Sn] of Hn(Sn;Z)Z, using Homology of spheres. For a continuous self-map f:SnSn, its degree is the unique integer satisfying f[Sn]=deg(f)[Sn]. The induced map is furnished by Functoriality of relative homology with empty subspaces. Replacing the same generator in source and target by its negative does not change the integer. For a map between separately oriented copies of Sn, use their separately specified generators; reversing just one orientation changes the sign. The unreduced definition here is restricted to n1.

PropositionStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Degree is homotopy invariant and multiplicative under composition

Statement

For n1 and continuous sphere self-maps f,g, homotopic maps have the same degree and deg(gf)=deg(g)deg(f). Every homotopy equivalence SnSn has degree 1 or 1.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

Let n1. Choose a generator [Sn] of Hn(Sn;Z)Z, using cor-homology-of-spheres. For a continuous self-map f:SnSn, its degree is the unique integer satisfying f[Sn]=deg(f)[Sn]. The induced map is furnished by prop-relative-homology-is-functorial-for-maps-of-pairs with empty subspaces. Replacing the same generator in source and target by its negative does not change the integer. For a map between separately oriented copies of Sn, use their separately specified generators; reversing just one orientation changes the sign. The unreduced definition here is restricted to n1. (Degree of a self map of an oriented sphere)

[F2]

If f,g:XY are homotopic continuous maps, then for every n0 and every abelian group G the induced homomorphisms on singular homology agree: Hn(f#)=Hn(g#):Hnsing(X;G)Hnsing(Y;G). (Homotopic maps induce the same map on singular homology)

Proof

1.1

Homotopic maps induce the same homomorphism on integral Hn, so their multiples of the orientation generator agree. This proves homotopy invariance, including constant maps.

F1F2
1.2

Functoriality gives (gf)[Sn]=g(deg(f)[Sn])=deg(f)deg(g)[Sn], so the integers multiply. The identity has degree 1.

F1algebra
2.1

If u is a homotopy inverse of f, then 1=deg(uf)=deg(u)deg(f). The only units of Z are ±1, proving the last assertion without a converse.

step 1.1step 1.2algebra
PropositionStatement: Literature-sourcedProof: AI-adaptedaudited 2026-09-07Open item page →

Suspension preserves sphere map degree

Statement

For n1 and f:SnSn, let Σf be its two-cone (unreduced) suspension. Orient ΣSnSn+1 by the natural suspension isomorphism. Then deg(Σf)=deg(f).

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

Let n1. Choose a generator [Sn] of Hn(Sn;Z)Z, using cor-homology-of-spheres. For a continuous self-map f:SnSn, its degree is the unique integer satisfying f[Sn]=deg(f)[Sn]. The induced map is furnished by prop-relative-homology-is-functorial-for-maps-of-pairs with empty subspaces. Replacing the same generator in source and target by its negative does not change the integer. For a map between separately oriented copies of Sn, use their separately specified generators; reversing just one orientation changes the sign. The unreduced definition here is restricted to n1. (Degree of a self map of an oriented sphere)

[F2]

Let G be an abelian group. For a based well-pointed space X—meaning that the basepoint inclusion {x0}X is a cofibration—reduced singular homology has natural isomorphisms H~n+1(ΣX;G)H~n(X;G) for all integers n. Here ΣX is the suspension with two distinct apices, as in def-adjunction-cone-suspension. (Suspension isomorphism in reduced singular homology)

Proof

1.1

Choose a source basepoint x0 and the target basepoint f(x0). Each sphere is well-pointed at its chosen point: rotate a CW structure with a vertex to that point and use the vertex cofibration. Thus f is a based map between these choices; the underlying two-cone suspension is unchanged. Thus F2 gives a natural isomorphism s:H~n+1(ΣSn;Z)H~n(Sn;Z). Choose the upstairs generator mapping to the downstairs generator.

F2
2.1

Naturality gives s(Σf)=fs. Applied to the upstairs generator, the right side is deg(f) times the downstairs generator. Since s is injective, the upstairs multiple is also deg(f). For n1 these reduced groups equal the top unreduced groups defining degree.

F1step 1.1algebra
PropositionStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Degree of identity constant reflection and antipodal sphere maps

Statement

On SnRn+1 for n1, the identity, a constant map, any single coordinate reflection, and the antipodal map have degrees 1, 0, 1, and (1)n+1 respectively.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

Let n1. Choose a generator [Sn] of Hn(Sn;Z)Z, using cor-homology-of-spheres. For a continuous self-map f:SnSn, its degree is the unique integer satisfying f[Sn]=deg(f)[Sn]. The induced map is furnished by prop-relative-homology-is-functorial-for-maps-of-pairs with empty subspaces. Replacing the same generator in source and target by its negative does not change the integer. For a map between separately oriented copies of Sn, use their separately specified generators; reversing just one orientation changes the sign. The unreduced definition here is restricted to n1. (Degree of a self map of an oriented sphere)

[F2]

For n1 and continuous sphere self-maps f,g, homotopic maps have the same degree and deg(gf)=deg(g)deg(f). Every homotopy equivalence SnSn has degree 1 or 1. (Degree is homotopy invariant and multiplicative under composition)

[F3]

For n1 and f:SnSn, let Σf be its two-cone (unreduced) suspension. Orient ΣSnSn+1 by the natural suspension isomorphism. Then deg(Σf)=deg(f). (Suspension preserves sphere map degree)

[F4]

For any abelian group G, H0(;G)G and Hn(;G)=0 for every integer n0. For every set-indexed family of pairs the canonical map αHn(Xα,Aα;G)Hn(αXα,αAα;G) is an isomorphism. Together with the structural axioms, singular homology is an ordinary theory with coefficient group G. (Singular homology satisfies dimension and arbitrary additivity)

Proof

1.1

The identity fixes the chosen generator. A constant map factors through a point whose Hn is zero because n1. Their degrees are therefore 1 and 0.

F1F4
1.2

On S1 choose the upper and lower semicircle singular paths a,b from the left endpoint to the right endpoint, with parametrizations matched by reflection across the horizontal axis, and put S0 equal to the two endpoints. CW excision and the pair sequences of the two arcs identify H1(S1,S0;Z) with Z[a]Z[b]; the connecting map sends each of [a] and [b] to the same generator [right][left] of H~0(S0;Z). Its kernel is therefore generated by [a][b]. Since H1(S0;Z)=0, exactness identifies H1(S1;Z) with this kernel, so the absolute cycle ab is a fundamental cycle. Reflection interchanges a and b, hence sends that generator to its negative and has degree 1.

F1F4algebra
2.1

Suspending this reflection n1 times gives a coordinate reflection of Sn, still of degree 1 by F3. Every other coordinate reflection is conjugate to it by a coordinate permutation. The conjugating homeomorphism has degree ±1, and multiplicativity cancels its degree with that of its inverse.

F2F3step 1.2
3.1

The antipodal map is the composite of the n+1 coordinate reflections. Its degree is their product (1)n+1. This also covers the starting case n=1.

F2step 2.1
LemmaStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

A map of nonzero degree between spheres is surjective

Statement

A continuous map between oriented n-spheres, n1, whose degree is nonzero must be surjective.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

Let n1. Choose a generator [Sn] of Hn(Sn;Z)Z, using cor-homology-of-spheres. For a continuous self-map f:SnSn, its degree is the unique integer satisfying f[Sn]=deg(f)[Sn]. The induced map is furnished by prop-relative-homology-is-functorial-for-maps-of-pairs with empty subspaces. Replacing the same generator in source and target by its negative does not change the integer. For a map between separately oriented copies of Sn, use their separately specified generators; reversing just one orientation changes the sign. The unreduced definition here is restricted to n1. (Degree of a self map of an oriented sphere)

[F2]

If X is a nonempty contractible topological space, then for every n0 and every abelian group G, Hnsing(X;G)Hnsing(;G), where denotes a one-point space. (Contractible nonempty spaces have the homology of a point)

[F3]

For any abelian group G, H0(;G)G and Hn(;G)=0 for every integer n0. For every set-indexed family of pairs the canonical map αHn(Xα,Aα;G)Hn(αXα,αAα;G) is an isomorphism. Together with the structural axioms, singular homology is an ordinary theory with coefficient group G. (Singular homology satisfies dimension and arbitrary additivity)

Proof

1.1

Suppose a target point p is omitted. After an orthogonal coordinate change put p=(0,,0,1). Stereographic projection sends (u,t) in its complement to u/(1t)Rn; its inverse is z(2z,z21)/(1+z2). Direct substitution verifies both inverses. Linear contraction in Rn shows the complement is nonempty and contractible.

givenalgebra
2.1

The induced map in degree n factors through Hn(Sn{p};Z)=Hn(;Z)=0, by F2 and F3. Hence its degree is zero by F1. This proves that omission of any point contradicts the assumed nonzero degree.

F1F2F3step 1.1
DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Local degree at an isolated preimage

Definition

Let f:SnSn be continuous, n1, with oriented source and target as in Degree of a self map of an oriented sphere. Suppose y=f(x) and x is isolated in f1(y). Choose an open neighborhood U of x with Uf1(y)={x}. The map of pairs (U,U{x})(Sn,Sn{y}) induces a homomorphism between infinite cyclic groups. Its integer multiplier in the generators restricted from the two global orientation classes is the local degree degxf.

Excision Excision for singular homology identifies the domain local group with Hn(Sn,Sn{x};Z); the pair sequence Long exact sequence of a pair supplies the global-to-local identification. The following lemma establishes these identifications and independence of the neighborhood.

LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Local sphere orientations and finite puncture excision

Statement

For n1, Hn(Sn,Sn{x};Z)Z, with generator the restriction of the global sphere orientation. The local degree in Local degree at an isolated preimage is independent of shrinking its neighborhood. For every finite nonempty FSn, Hn(Sn,SnF;Z)xFHn(Sn,Sn{x};Z), and the global orientation maps to the tuple of local orientation generators.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

Let f:SnSn be continuous, n1, with oriented source and target as in def-degree-of-a-self-map-of-an-oriented-sphere. Suppose y=f(x) and x is isolated in f1(y). Choose an open neighborhood U of x with Uf1(y)={x}. The map of pairs (U,U{x})(Sn,Sn{y}) induces a homomorphism between infinite cyclic groups. Its integer multiplier in the generators restricted from the two global orientation classes is the local degree degxf. Excision thm-excision-for-singular-homology identifies the domain local group with Hn(Sn,Sn{x};Z); the pair sequence thm-long-exact-sequence-of-a-pair-in-singular-homology supplies the global-to-local identification. The following lemma establishes these identifications and independence of the neighborhood. (Local degree at an isolated preimage)

[F2]

A map of pairs f:(X,A)(Y,B) induces a commuting morphism from the long exact sequence of (X,A) to that of (Y,B), including the connecting maps. (Naturality of the pair long exact sequence)

[F3]

Let X=αAXα be a disjoint union of topological spaces, and let G be an abelian group. Then for every n0, Hnsing(X;G)αAHnsing(Xα;G). (The singular homology of a disjoint union is the direct sum)

Proof

1.1

A once-punctured sphere is contractible by stereographic projection and linear contraction. In the pair sequence its positive homology vanishes. For n>1 the terms on both sides of the global-to-relative map vanish, giving an isomorphism. For n=1, the last map is H0(S1{x})H0(S1), an isomorphism between the groups of two connected nonempty spaces; exactness gives the same conclusion. This proves the cyclic local group and fixes its generator as in F1.

F1algebra
1.2

Choose mutually disjoint small open coordinate balls Ux around the finitely many points. Excision removes the closed set SnUx, which is contained in the open complement of F. The relative chain complex of the disjoint balls splits into their direct sum, by the same simplex-by-component decomposition as F3. Excision in each ball then gives the displayed isomorphism. This argument includes a singleton F.

F1F3
2.1

The homomorphism induced by (Sn,SnF)(Sn,Sn{x}) is projection onto the x summand: all other summands factor through a pair (Uz,Uz) and vanish. Its composite with the global map restricts the global class to its local generator. Hence the global tuple is diagonal.

F2step 1.1step 1.2
3.1

For nested allowed neighborhoods, the inclusion of punctured pairs is an excision isomorphism and carries one restricted generator to the other. Their maps to the target pair commute. Thus their integer multipliers agree. Two arbitrary allowed neighborhoods have an allowed open intersection, so shrinking proves full independence.

F1F2step 1.1
TheoremStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Global sphere degree is the sum of local degrees

Statement

Let f:SnSn be continuous, n1, with source and target orientations fixed. If f1(y) is finite, then deg(f)=xf1(y)degxf. The sum over an empty fibre is 0.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For n1, Hn(Sn,Sn{x};Z)Z, with generator the restriction of the global sphere orientation. The local degree in def-local-degree-at-an-isolated-preimage is independent of shrinking its neighborhood. For every finite nonempty FSn, Hn(Sn,SnF;Z)xFHn(Sn,Sn{x};Z), and the global orientation maps to the tuple of local orientation generators. (Local sphere orientations and finite puncture excision)

[F2]

A continuous map between oriented n-spheres, n1, whose degree is nonzero must be surjective. (A map of nonzero degree between spheres is surjective)

Proof

1.1

If the fibre is empty, f omits a point, so its degree is zero by F2. This equals the empty sum.

F2
1.2

For a nonempty finite fibre F, use the global-to-relative maps for (Sn,SnF) and (Sn,Sn{y}). Functoriality makes the square with f commute. By F1, the source global generator maps to (1)xF and the target global generator maps to 1.

F1
2.1

On the summand indexed by x, the lower map in this square is multiplication by degxf, by the local definition and excision. Its value on the diagonal is the sum of these integers. The other route through the square gives deg(f), proving the formula, also for a singleton fibre.

F1step 1.2algebra
PropositionStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Every integer occurs as the degree of a sphere map

Statement

For every dZ and n1 there exists a continuous self-map of Sn of degree d.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

Let f:SnSn be continuous, n1, with source and target orientations fixed. If f1(y) is finite, then deg(f)=xf1(y)degxf. The sum over an empty fibre is 0. (Global sphere degree is the sum of local degrees)

[F2]

On SnRn+1 for n1, the identity, a constant map, any single coordinate reflection, and the antipodal map have degrees 1, 0, 1, and (1)n+1 respectively. (Degree of identity constant reflection and antipodal sphere maps)

Proof

1.1

For d=0 take a constant map, which has degree zero by F2.

F2
1.2

For k=d>0, choose k disjoint closed coordinate balls with nonempty interiors. Collapse their boundaries and the complement of their interiors to a single point. The quotient is a wedge of k copies of Dn/DnSn: a homeomorphism of the ball interior with Rn, followed by inverse stereographic projection, extends to this quotient by sending the boundary to the omitted pole. Fold these copies to a common target sphere. Use an orientation-preserving homeomorphism on each copy if d>0, and compose each with a coordinate reflection if d<0. The maps agree at the collapsed point, so the quotient construction is continuous.

givenF2
2.1

A point distinct from the common pole has exactly one preimage in each ball. At each such point the local degree is +1 or 1 as chosen: an orientation-preserving chart restricts the local generator unchanged, and reflection reverses it. F1 gives degree ksgn(d)=d. This works for k=1 and for one-dimensional balls as well.

F1F2step 1.2
TheoremStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

No retraction from a disk onto its boundary

Statement

For every integer n1, there is no continuous retraction DnSn1 of the closed unit ball onto its boundary.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For n1, H~k(Sn;G) is G for k=n and 0 otherwise. For S0, H~0(S0;G)G and all other reduced groups vanish. Thus H0(Sn;G)G for n1, whereas H0(S0;G)GG. (Homology of spheres)

[F2]

For any abelian group G, H0(;G)G and Hn(;G)=0 for every integer n0. For every set-indexed family of pairs the canonical map αHn(Xα,Aα;G)Hn(αXα,αAα;G) is an isomorphism. Together with the structural axioms, singular homology is an ordinary theory with coefficient group G. (Singular homology satisfies dimension and arbitrary additivity)

[F3]

If X is a nonempty contractible topological space, then for every n0 and every abelian group G, Hnsing(X;G)Hnsing(;G), where denotes a one-point space. (Contractible nonempty spaces have the homology of a point)

Proof

1.1

The disk contracts by (x,t)(1t)x. Thus its reduced integral homology is zero, by F3 and the point computation F2. In contrast H~n1(Sn1;Z)=Z by F1, including reduced H0(S0) when n=1.

F1F2F3
2.1

A retraction r of the boundary inclusion i would satisfy ri=id. Functoriality on reduced homology would factor the identity of Z through the zero group H~n1(Dn;Z). That composite is zero, whereas the identity sends 1 to 1, a contradiction.

step 1.1algebra
LemmaStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

A fixed point free ball map produces a boundary retraction

Statement

For n1, a continuous fixed-point-free map f:DnDn would produce a continuous retraction r:DnSn1 by following the ray from f(x) through x to the boundary.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

Proof

1.1

Put b=f(x), v=xb, a=b,v, and q(s)=b+sv21. Since v0, this is an upward quadratic with q(0)0 and q(1)0. Its larger root is t(x)=a+a2+(1b2)v2v2. The discriminant is nonnegative and q(1)0 implies t(x)1.

givenalgebra
2.1

Set r(x)=b+t(x)v. The nonzero denominator and the continuous square root of a nonnegative continuous function make t and r continuous. The root equation gives r(x)=1, so r has the required target. No differentiability or uniform lower bound on the denominator is needed.

step 1.1algebra
3.1

If x=1, then q(1)=0 and q(1)=2x,xb=2(1x,b)>0: equality in x,bb1 would force b=x, excluded by hypothesis. Thus 1 is the larger root and r(x)=x. This proves the retraction property, also on the two endpoints when n=1.

step 1.1step 2.1algebra
TheoremStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Brouwer fixed point theorem

Statement

Every continuous map f:DnDn of the closed unit ball has a fixed point, for every integer n0.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For every integer n1, there is no continuous retraction DnSn1 of the closed unit ball onto its boundary. (No retraction from a disk onto its boundary)

[F2]

For n1, a continuous fixed-point-free map f:DnDn would produce a continuous retraction r:DnSn1 by following the ray from f(x) through x to the boundary. (A fixed point free ball map produces a boundary retraction)

Proof

1.1

When n=0, D0 is a singleton, and its unique point is fixed by every self-map.

given
2.1

For n1, a fixed-point-free map would give a continuous boundary retraction by F2. F1 excludes precisely such a retraction in every positive dimension. Therefore a fixed point exists.

F1F2
TheoremStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

No nowhere zero tangent vector field on an even sphere

Statement

For every positive even integer n, no continuous map v:SnRn+1 can satisfy both v(x),x=0 and v(x)0 for all x. Thus an even-dimensional sphere has no continuous nowhere-zero tangent vector field.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For n1 and continuous sphere self-maps f,g, homotopic maps have the same degree and deg(gf)=deg(g)deg(f). Every homotopy equivalence SnSn has degree 1 or 1. (Degree is homotopy invariant and multiplicative under composition)

[F2]

On SnRn+1 for n1, the identity, a constant map, any single coordinate reflection, and the antipodal map have degrees 1, 0, 1, and (1)n+1 respectively. (Degree of identity constant reflection and antipodal sphere maps)

Proof

1.1

If such v existed, w(x)=v(x)/v(x) would be continuous, orthogonal to x, and of norm one. Hence H(x,t)=cos(πt)x+sin(πt)w(x) has squared norm cos2(πt)+sin2(πt)=1 for all 0t1.

givenalgebra
2.1

The homotopy has endpoints H(x,0)=x and H(x,1)=x. By F1 their degrees agree, but by F2 these degrees are 1 and (1)n+1=1 because n is even. The unequal integers contradict the existence of v.

F1F2step 1.1
PropositionStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

An odd sphere admits a nowhere zero tangent vector field

Statement

For n=2m11, identify R2m with Cm. The map v:SnR2m given by v(x)=ix is a continuous unit tangent vector field.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

Proof

1.1

In real coordinates, v(x1,x2,,x2m)=(x2,x1,,x2m,x2m1). This linear map is continuous and v(x),x=j=1m(x2jx2j1+x2j1x2j)=0.

givenalgebra
2.1

Moreover v(x)2=j=12mxj2=1 on the sphere, so the field never vanishes. For m=1 this is the usual quarter-turn field on the circle.

step 1.1algebra
TheoremStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

A sphere has a nowhere zero tangent vector field iff its dimension is odd

Statement

For every integer n1, Sn admits a continuous nowhere-zero tangent vector field if and only if n is odd.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For every positive even integer n, no continuous map v:SnRn+1 can satisfy both v(x),x=0 and v(x)0 for all x. Thus an even-dimensional sphere has no continuous nowhere-zero tangent vector field. (No nowhere zero tangent vector field on an even sphere)

[F2]

For n=2m11, identify R2m with Cm. The map v:SnR2m given by v(x)=ix is a continuous unit tangent vector field. (An odd sphere admits a nowhere zero tangent vector field)

Proof

1.1

If a field exists, n cannot be positive even by F1. Every positive integer is even or odd, so n must be odd.

F1given
2.1

Conversely, for odd n1 write n=2m1 with m1. F2 constructs the continuous unit tangent field xix. This proves the reverse implication as well.

F2
CorollaryStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

A fixed point free sphere map has antipodal degree

Statement

For n1, any continuous fixed-point-free map f:SnSn has degree (1)n+1. Consequently, a self-map of any other degree has a fixed point.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

On SnRn+1 for n1, the identity, a constant map, any single coordinate reflection, and the antipodal map have degrees 1, 0, 1, and (1)n+1 respectively. (Degree of identity constant reflection and antipodal sphere maps)

[F2]

For n1 and continuous sphere self-maps f,g, homotopic maps have the same degree and deg(gf)=deg(g)deg(f). Every homotopy equivalence SnSn has degree 1 or 1. (Degree is homotopy invariant and multiplicative under composition)

Proof

1.1

Let u(x,t)=(1t)f(x)tx. Its endpoint values are unit vectors. If it vanished for 0<t<1, equality of norms would imply 1t=t and hence f(x)=x, contrary to the hypothesis. Thus H(x,t)=u(x,t)/u(x,t) is a continuous sphere homotopy.

givenalgebra
2.1

Its endpoints are f and the antipodal map. F2 and F1 give deg(f)=(1)n+1. If a map of any other degree lacked fixed points, the just-proved equality would contradict its degree, proving the consequence.

F1F2step 1.1
CorollaryStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

A group acting freely on a positive even sphere has at most two elements

Statement

If a group Γ acts freely by homeomorphisms on S2m with m1, then Γ2. If it is nontrivial, it is isomorphic to Z/2Z. The antipodal action realizes the nontrivial case.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For n1, any continuous fixed-point-free map f:SnSn has degree (1)n+1. Consequently, a self-map of any other degree has a fixed point. (A fixed point free sphere map has antipodal degree)

[F2]

For n1 and continuous sphere self-maps f,g, homotopic maps have the same degree and deg(gf)=deg(g)deg(f). Every homotopy equivalence SnSn has degree 1 or 1. (Degree is homotopy invariant and multiplicative under composition)

[F3]

On SnRn+1 for n1, the identity, a constant map, any single coordinate reflection, and the antipodal map have degrees 1, 0, 1, and (1)n+1 respectively. (Degree of identity constant reflection and antipodal sphere maps)

Proof

1.1

Let ag be the homeomorphism associated to gΓ. F2 makes d(g)=deg(ag) a homomorphism Γ{1,1}, since agh=agah and a homeomorphism is a homotopy equivalence.

F2
2.1

For every ge, freeness says ag has no fixed point. F1, in positive even dimension, gives d(g)=1. Thus kerd={e}, so d is injective and Γ2, including the trivial group. A nontrivial subgroup of {1,1} is the entire two-element group.

F1step 1.1algebra
3.1

The antipodal involution squares to the identity and has no fixed point on a unit sphere: x=x would imply x=0. Together with the identity it therefore gives a free two-element action, of nonidentity degree 1 by F3.

F3algebra
TheoremStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

Invariance of dimension for euclidean spaces

Statement

For nonnegative integers m,n, a homeomorphism RmRn implies m=n.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For n1, H~k(Sn;G) is G for k=n and 0 otherwise. For S0, H~0(S0;G)G and all other reduced groups vanish. Thus H0(Sn;G)G for n1, whereas H0(S0;G)GG. (Homology of spheres)

[F2]

If f,g:XY are homotopic continuous maps, then for every n0 and every abelian group G the induced homomorphisms on singular homology agree: Hn(f#)=Hn(g#):Hnsing(X;G)Hnsing(Y;G). (Homotopic maps induce the same map on singular homology)

Proof

1.1

The space R0 is a singleton, whereas Rk contains at least two points for k>0. Thus if one dimension is zero, a homeomorphism forces the other to be zero.

given
1.2

Suppose m,n>0. A homeomorphism restricts to Rm{0}Rn{f(0)}. Translate the omitted target point to zero. For k>0 the formula R(x,t)=((1t)+t/x)x is a strong deformation retraction of Rk{0} onto Sk1: its scalar is positive and equals one when x=1.

givenalgebra
2.1

Homotopy invariance in F2, restricted to the augmentation kernels in degree zero, now identifies the reduced homology of these spheres. By F1 with integral coefficients, the only nonzero reduced group of Sk1 is Z in degree k1, including k=1. Equality of this support forces m1=n1 and hence m=n.

F1F2step 1.2

5 · Examples, counterexamples and false statements

None yet.

Sources