Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A sequential abelian colimit is the cokernel of one minus shift

Statement

For any sequence of abelian groups G0→u0G1→u1⋯, let D=⨁i≥0Gi and let s:D→D send the ith coordinate by ui into coordinate i+1. Then 0⟶D→1−sD⟶colim⁡iGi⟶0 is exact, where the last map sums the canonical maps to the colimit. The maps ui need not be injective.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

Proof

1.1givenalgebra

If (1−s)x=0, its coordinate zero is x0=0. Recursively its coordinate i is xi−ui−1xi−1=0, forcing xi=0 for every i. Thus 1−s is injective, even if some or all transition maps vanish.

2.1step 1.1algebra∎

The quotient D/im⁡(1−s) imposes the relations ιi(g)=ιi+1(uig). A homomorphism from this quotient to any abelian group B is exactly a family of homomorphisms vi:Gi→B satisfying vi+1ui=vi: define the map on a finite-support tuple by the finite sum ∑ivi(xi). This proves the colimit universal property, so the quotient is the colimit and the last map is surjective with the stated kernel. Zero groups and a sequence supported at only one index are included.

Used by

Dependency tree · 0 levels

Nothing. This result depends on no other item in the library.

Sources