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Suspension isomorphism in reduced singular homology

Statement

Let G be an abelian group. For a based well-pointed space X—meaning that the basepoint inclusion {x0}↪X is a cofibration—reduced singular homology has natural isomorphisms H~n+1(ΣX;G)≅H~n(X;G) for all integers n. Here ΣX is the suspension with two distinct apices, as in The adjunction space Y∪fX glued along a continuous map, and, for a nonempty space, the cone and the suspension as quotients of X×[0,1].

Facts & Assumptions

Given: A based space X whose basepoint inclusion is a cofibration, and its suspension covered by two cone neighborhoods.

Proof

technique · direct
1.1givenconstruct

Write q:X×[0,1]→ΣX for the quotient. The sets U=q(X×[0,2/3)) and V=q(X×(1/3,1]) are open, cover ΣX, and contract to their respective apices by moving the height coordinate linearly to 0 or 1. Their intersection is W≅X×(1/3,2/3); projection p:W→X is a homotopy equivalence, with section at height 1/2. Since X has its specified basepoint, these spaces are nonempty.

2.1step 1.1algebra

A point has H0(∗;G)=G and Hj(∗;G)=0 for j>0: its singular complex has one copy of G in each degree, with boundary alternately zero and identity. Thus Contractible nonempty spaces have the homology of a point gives the same groups for U,V, with the degree-zero isomorphism induced by augmentation. For n≥1, ordinary exactness in Mayer–Vietoris sequence in singular homology gives Hn+1(ΣX;G)≅Hn(W;G)≅Hn(X;G), the last isomorphism by Homotopy equivalences induce isomorphisms on singular homology. These degrees are positive, so the groups are also reduced groups.

3.1step 2.1algebra

For n=0, the same exact sequence gives 0→H1(ΣX;G)→δH0(W;G)→(ε,−ε)G⊕G. Its last kernel is exactly H~0(W;G). Projection to X preserves augmentation and is an ordinary homology isomorphism, so it identifies this kernel with H~0(X;G) under Augmentation at 0-simplices and reduced singular homology.

4.1step 1.1step 3.1algebra

Every point of ΣX has a height path to an apex, and the height path through x0 joins the two apices. Hence ΣX is path connected: differences of singular points bound paths, so augmentation identifies its H0 with G and its reduced H0 is zero. This proves the shift for n=−1; for n<−1 both sides are zero by the stated reduced-complex convention. The arguments include the one-point space and G=0.

5.1step 2.1step 3.1step 4.1algebra∎

A based map f:X→Y induces [x,t]↦[f(x),t] and preserves these covers and their projections. At chain level the connecting map takes a small cycle z=u+v to [∂u]; applying f# gives [∂f#u]=[f#∂u]. Thus the connecting maps commute with f, and so do their degree-zero kernel restrictions and the projection isomorphisms. This proves naturality in every degree.

Depends on

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Sources