Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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Global sphere degree is the sum of local degrees

Statement

Let f:Sn→Sn be continuous, n≥1, with source and target orientations fixed. If f−1(y) is finite, then deg⁡(f)=∑x∈f−1(y)deg⁡xf. The sum over an empty fibre is 0.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

For n≥1, Hn(Sn,Sn∖{x};Z)≅Z, with generator the restriction of the global sphere orientation. The local degree in def-local-degree-at-an-isolated-preimage is independent of shrinking its neighborhood. For every finite nonempty F⊂Sn, Hn(Sn,Sn∖F;Z)≅⨁x∈FHn(Sn,Sn∖{x};Z), and the global orientation maps to the tuple of local orientation generators. (Local sphere orientations and finite puncture excision)

[F2]

A continuous map between oriented n-spheres, n≥1, whose degree is nonzero must be surjective. (A map of nonzero degree between spheres is surjective)

Proof

1.1F2

If the fibre is empty, f omits a point, so its degree is zero by F2. This equals the empty sum.

1.2F1

For a nonempty finite fibre F, use the global-to-relative maps for (Sn,Sn∖F) and (Sn,Sn∖{y}). Functoriality makes the square with f commute. By F1, the source global generator maps to (1)x∈F and the target global generator maps to 1.

2.1F1step 1.2algebra∎

On the summand indexed by x, the lower map in this square is multiplication by deg⁡xf, by the local definition and excision. Its value on the diagonal is the sum of these integers. The other route through the square gives deg⁡(f), proving the formula, also for a singleton fibre.

Depends on

Used by

Dependency tree · two levels

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Sources