Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Cw homotopy equivalence inclusions are strong deformation retracts

Statement

If AX is a CW subcomplex and its inclusion is a homotopy equivalence, then X strongly deformation retracts onto A. Moreover, if (Y,B) is a CW pair and u0,u1:BZ are homotopic, then the adjunction spaces Zu0Y and Zu1Y are homotopy equivalent relative to their common subspace Z.

Facts & Assumptions

Given: The objects and hypotheses in the statement above.

[F1]

If (X,A) is a relative CW complex, then AX has the homotopy extension property; in particular it is a cofibration. (Relative CW inclusions are cofibrations)

Proof

1.1

First prove the relative inverse assertion: if f:(X,A)(Y,A) is a homotopy equivalence, equals the identity on A, and both inclusions have HEP, let g be an inverse and ht:gfidX. Extend htA over Y by HEP, starting at g, to obtain gt with g1A=id. CW inclusions have the needed HEP by F1.

F1given
2.1

Concatenate the homotopy g12tf for 0t1/2 with h2t1 for 1/2t1. It runs from g1f to the identity, and on A is a path followed by its reverse. Such a loop contracts relative to its endpoints: if its first-half path is γ, replace γ(min(2t,22t)) by γ((1u)min(2t,22t)). HEP for (X×I,A×I) extends this homotopy of homotopies. Following the left, top, and right sides of the parameter square now gives g1fidX relative to A. This product HEP follows by taking the product of the HEP retraction X×IX×{0}A×I with the other interval.

F1step 1.1
3.1

Repeat the preceding adjustment with g1 and f interchanged, obtaining f1 fixed on A with f1g1idY relative to A. Then f1f1g1ff relative to A, so fg1idY relative to A. Apply this result with the map AX: its relative inverse is a retraction, and the relative inverse homotopy is precisely a strong deformation retraction. If A is empty, the existence of an inverse forces X empty.

step 1.1step 2.1
4.1

For a homotopy U:B×IZ from u0 to u1, use the common space W=ZU(Y×I). The CW prism retraction of Y×I onto Y×{0}B×I fixes B×I and descends to a strong deformation retraction of W onto the first adjunction space, fixed on Z. The reversed prism gives the second retraction. These prism retractions can be built cellwise using radial projection of Dr×I onto its bottom and sides; concatenate over dimensions with the CW weak topology, as in the HEP construction. Composing the two inclusions and retractions gives inverse homotopy equivalences relative to Z.

F1algebra

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Sources