How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
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- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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These labels describe origin, not correctness: citations and verification chips remain separate evidence.
A comparison isomorphism propagates over one skeleton stage
Statement
Let be an existing morphism of ordinary theories, natural on CW pairs and commuting with connecting maps. For a CW skeleton stage , if and are isomorphisms for every , then is an isomorphism for every .
Facts & Assumptions
Given: The objects and hypotheses in the statement above.
For ordinary theories as in def-unreduced-homology-theory-on-cw-pairs, a morphism consists of homomorphisms , natural for all maps of CW pairs and all , satisfying . For a specified homomorphism , the morphism is coefficient-normalized by if . A comparison equivalence has every component invertible and is normalized by a specified coefficient isomorphism. Neither the existence nor uniqueness of such an extension is part of this definition. (Coefficient normalized morphism of ordinary homology theories)
For a CW pair and an ordinary theory with coefficient , put and for . Set Each is the direct sum of copies of indexed by the relative -cells. Define and for let be the triple boundary to followed by its map to . Then , naturally for cellular maps of CW pairs. (Any ordinary homology theory has a cellular chain complex on a cw pair)
Let and be long exact sequences in an abelian category, together with a morphism of these sequences. If the four comparison maps at are isomorphisms, then the comparison map is an isomorphism. (Five lemma for a morphism of long exact sequences)
Proof
F1 means that gives a commuting morphism of the pair long exact sequences. The skeletal pair of F2 has the five consecutive terms , and the analogous row for .
The four comparison homomorphisms surrounding the middle term are isomorphisms by the stated hypotheses. Apply F3 to these five terms to conclude that the already specified middle homomorphism is an isomorphism. Since was arbitrary this proves the result in all degrees, even at the empty bottom skeleton. This argument propagates invertibility; it does not construct .
Depends on
Used by
Dependency tree · two levels
9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- May, A Concise Course in Algebraic Topology, 15§2, skeletal exactness pp.119–120 (standard reference, not scraped)
- Miller, Algebraic Topology I lecture notes, Proposition 9.6, opening p.22 (standard reference, not scraped)