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CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
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The absolute line integral of the constant function 1 is the length of the path

Statement

For every rectifiable contour γ, ∫γ1 ∣dz∣=L(γ).

Facts & Assumptions

Given: A rectifiable contour γ:[a,b]→C.

[L1]

The absolute line integral is ∫ab∣f(γ(t))∣ dsγ(t) (The absolute line integral over a rectifiable path using its arc-length function).

[L2]

The arc-length function satisfies sγ(a)=0 and sγ(b)=L(γ) (The arc-length function sγ(t)=L(γ∣[a,t]) of a rectifiable path).

Proof

technique · direct
1.1L1algebra

With f≡1, [L1] becomes ∫ab1 dsγ=sγ(b)−sγ(a).

2.1step 1.1L2∎

Substitute [L2] to obtain L(γ). Singleton and constant paths have both sides 0.

Depends on

Used by

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources