Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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Almost-sure convergence of an independent series is a zero-one event

Statement

Let (Xn)n∈N be an independent sequence of real random variables. Then the event

{∑n=0∞Xn converges}

has probability 0 or 1.

Facts & Assumptions

Given: An independent sequence of real random variables (Xn)n∈N.

[L1]

The tail sigma-algebra consists of the events determined by all but finitely many coordinates. (Tail sigma-algebra of a sequence)

[L2]

Finite sums and absolute values of measurable real-valued functions are measurable. (Arithmetic and lattice operations preserve measurability whenever they are defined)

[L3]

Every tail event of an independent sequence has probability 0 or 1. (Kolmogorov zero-one law)

Proof

technique · direct
1.1givenL1L2

Let E:={∑n=0∞Xn converges} and fix m∈N. The series ∑n=0∞Xn converges if and only if the tail series ∑n=m∞Xn converges, because removing finitely many initial terms changes every partial sum by a fixed finite constant. By the Cauchy criterion, E=⋂r=1∞⋃N=m∞⋂q≥p≥N{∣∑n=pqXn∣≤1r}. For q≥p≥N≥m, the partial sum ∑n=pqXn is measurable with respect to σ(Xn:n≥m) by repeated use of [L2], so each displayed event lies in σ(Xn:n≥m). Therefore E∈σ(Xn:n≥m) for every m.

2.1step 1.1L3∎

Step 1.1 shows that E lies in the tail sigma-algebra, so [L3] gives P(E)∈{0,1}.

Depends on

Used by

Dependency tree · two levels

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Sources