Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-26
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Rooted plane binary trees satisfy B(x)=1+xB(x)2

Statement

Let B(x) be the generating function of rooted plane binary trees, specified by

B=E+Z×B2.

Then B(x) is the unique formal power series satisfying

B(x)=1+xB(x)2.

Facts & Assumptions

Given: The recursive specification B=E+Z×B2.

[L1]

Disjoint union and Cartesian product translate to addition and multiplication of ordinary generating functions (Disjoint union and Cartesian product translate to addition and multiplication of ordinary generating functions).

[L2]

An order-raising recursive specification has a unique solution (An order-raising recursive specification has a unique solution).

[L3]

Formal order is non-Archimedean under sums and satisfies ord⁡x(fg)≥ord⁡x(f)+ord⁡x(g) over a commutative ring (Formal order is non-Archimedean under sums and additive under products over a domain).

Proof

technique · direct
1.1L3algebra

The associated operator is F(Y)=1+xY2. For any U,V, one has F(U)−F(V)=x(U+V)(U−V), so [L3] gives ord⁡x(F(U)−F(V))≥ord⁡x(U−V)+1. Thus the specification is order-raising.

2.1step 1.1L2

By [L2], the specification has a unique formal power series solution B(x).

3.1step 2.1L1∎

The neutral class contributes 1, the atomic class contributes x, and the ordered pair of left and right subtrees contributes B(x)2 by [L1]. Hence the specification translates to B(x)=1+xB(x)2.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources